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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  GATE Mechanical (ME) Mock Test Series 2025  >  Test: Basics of Refrigerating Machine - 2 - Mechanical Engineering MCQ

Test: Basics of Refrigerating Machine - 2 - Mechanical Engineering MCQ


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10 Questions MCQ Test GATE Mechanical (ME) Mock Test Series 2025 - Test: Basics of Refrigerating Machine - 2

Test: Basics of Refrigerating Machine - 2 for Mechanical Engineering 2024 is part of GATE Mechanical (ME) Mock Test Series 2025 preparation. The Test: Basics of Refrigerating Machine - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Basics of Refrigerating Machine - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Basics of Refrigerating Machine - 2 below.
Solutions of Test: Basics of Refrigerating Machine - 2 questions in English are available as part of our GATE Mechanical (ME) Mock Test Series 2025 for Mechanical Engineering & Test: Basics of Refrigerating Machine - 2 solutions in Hindi for GATE Mechanical (ME) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt Test: Basics of Refrigerating Machine - 2 | 10 questions in 30 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study GATE Mechanical (ME) Mock Test Series 2025 for Mechanical Engineering Exam | Download free PDF with solutions
Test: Basics of Refrigerating Machine - 2 - Question 1
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The COP of a heat pump can be increased either by decreasing TH by ΔT or by increasing TL by ΔT. The new COP of the heat pump is

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 1


Assuming initially


If higher temperature is decreased by 5°C. New conditions

Then the COP of heat pump is

If lower temperature is increased by 5°C.
New conditions

Then the COP of heat pump is 

Hence COP will be highest when lower temperature is increased rather than decreasing higher temperature by same amount.

Test: Basics of Refrigerating Machine - 2 - Question 2
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The expression for COP of reversed Brayton cycle is (rp is the pressure ratio)

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 2



Heat absorbed by the air during constant pressure expansion
= cp(T1 - T4)
We know work done during the cycle
= Heat rejected - Heat absorbed
Coefficient of performance



We know that for isentropic compression process 1-2.

Similarly, for isentropic expansion process 3-4.

Since, p2 = p3 and p1 = p4, therefore from equations (ii) and (iii)

Now substituting these values in equation (i), we get

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Test: Basics of Refrigerating Machine - 2 - Question 3
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A reversible heat engine runs between high temperature T1 and low temperature T2. The work output of this heat engine is used to run a reversible refrigeration cycle absorbing heat at temperature T3 and rejecting at temperature T2.

What is the COP of the combined system?

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 3


COP of the combined system


 

Test: Basics of Refrigerating Machine - 2 - Question 4
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If COP of a refrigerator is 5 and efficiency of a heat engine of the same temperature limit is 50%. Then what is the ratio of heat supplied to engine to heat absorbed by the refrigerator from the space
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 4




By equating, we get 

⇒ 

Test: Basics of Refrigerating Machine - 2 - Question 5
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COP of a Carnot heat pump operating between -3°C and 27°C is
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 5

 

(COP)c.p. = T1/(T1 - T2)

= 300/(30)

= 10
 

Test: Basics of Refrigerating Machine - 2 - Question 6
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A condenser of a refrigeration system rejects heat at a rate of 120 kW, while its compressor consumes a power of 30 kW. The COP of the system would be
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 6

Test: Basics of Refrigerating Machine - 2 - Question 7
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If an engine of 40% thermal efficiency drives a refrigerator having a coefficient of performance of 5, then the heat input to engine for each kJ of heat removed from the cold body of the refrigerator is
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 7



Test: Basics of Refrigerating Machine - 2 - Question 8
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In the given figure E is a heat engine with efficiency of 0.4 and R is a refrigerator'given that Q2 + Q4 = 3Q1., the COP of the refrigerator is
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 8



Test: Basics of Refrigerating Machine - 2 - Question 9
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A refrigerator working on reversed Car not cycle absorbs 10 kW power and has a COP of 4. What will be the quantity of heat delivered to a building if it works as a heat pump
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 9



Hence heat supplied to building
= 40 + 10 = 50 kW

Test: Basics of Refrigerating Machine - 2 - Question 10
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A water chiller with a capacity of 30 tons of refrigeration cools 20 m3/hr of water entering at 12°C. What is the temperature of water leaving the chiller
Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 10


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