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Test: Basics of Refrigerating Machine - 2 - Mechanical Engineering MCQ


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10 Questions MCQ Test GATE Mechanical (ME) Mock Test Series 2025 - Test: Basics of Refrigerating Machine - 2

Test: Basics of Refrigerating Machine - 2 for Mechanical Engineering 2024 is part of GATE Mechanical (ME) Mock Test Series 2025 preparation. The Test: Basics of Refrigerating Machine - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Basics of Refrigerating Machine - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Basics of Refrigerating Machine - 2 below.
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Test: Basics of Refrigerating Machine - 2 - Question 1

The COP of a heat pump can be increased either by decreasing TH by ΔT or by increasing TL by ΔT. The new COP of the heat pump is

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 1


Assuming initially


If higher temperature is decreased by 5°C. New conditions

Then the COP of heat pump is

If lower temperature is increased by 5°C.
New conditions

Then the COP of heat pump is 

Hence COP will be highest when lower temperature is increased rather than decreasing higher temperature by same amount.

Test: Basics of Refrigerating Machine - 2 - Question 2

The expression for COP of reversed Brayton cycle is (rp is the pressure ratio)

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 2



Heat absorbed by the air during constant pressure expansion
= cp(T1 - T4)
We know work done during the cycle
= Heat rejected - Heat absorbed
Coefficient of performance



We know that for isentropic compression process 1-2.

Similarly, for isentropic expansion process 3-4.

Since, p2 = p3 and p1 = p4, therefore from equations (ii) and (iii)

Now substituting these values in equation (i), we get

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Test: Basics of Refrigerating Machine - 2 - Question 3

A reversible heat engine runs between high temperature T1 and low temperature T2. The work output of this heat engine is used to run a reversible refrigeration cycle absorbing heat at temperature T3 and rejecting at temperature T2.

What is the COP of the combined system?

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 3


COP of the combined system


 

Test: Basics of Refrigerating Machine - 2 - Question 4

If COP of a refrigerator is 5 and efficiency of a heat engine of the same temperature limit is 50%. Then what is the ratio of heat supplied to engine to heat absorbed by the refrigerator from the space

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 4




By equating, we get 

⇒ 

Test: Basics of Refrigerating Machine - 2 - Question 5

COP of a Carnot heat pump operating between -3°C and 27°C is

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 5

 

(COP)c.p. = T1/(T1 - T2)

= 300/(30)

= 10
 

Test: Basics of Refrigerating Machine - 2 - Question 6

A condenser of a refrigeration system rejects heat at a rate of 120 kW, while its compressor consumes a power of 30 kW. The COP of the system would be

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 6

Test: Basics of Refrigerating Machine - 2 - Question 7

If an engine of 40% thermal efficiency drives a refrigerator having a coefficient of performance of 5, then the heat input to engine for each kJ of heat removed from the cold body of the refrigerator is

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 7



Test: Basics of Refrigerating Machine - 2 - Question 8

In the given figure E is a heat engine with efficiency of 0.4 and R is a refrigerator'given that Q2 + Q4 = 3Q1., the COP of the refrigerator is

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 8



Test: Basics of Refrigerating Machine - 2 - Question 9

A refrigerator working on reversed Car not cycle absorbs 10 kW power and has a COP of 4. What will be the quantity of heat delivered to a building if it works as a heat pump

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 9



Hence heat supplied to building
= 40 + 10 = 50 kW

Test: Basics of Refrigerating Machine - 2 - Question 10

A water chiller with a capacity of 30 tons of refrigeration cools 20 m3/hr of water entering at 12°C. What is the temperature of water leaving the chiller

Detailed Solution for Test: Basics of Refrigerating Machine - 2 - Question 10


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