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The electron in Bohr’s model of hydrogen atom is pictured as revolving around the nucleus in order for it to
Revolving electrons possess energy.
Given below are the spectral lines for an atom of hydrogen. Mark the lines which are not correctly matched with the value of n_{1} and n_{2}?
(ii) Balmer, n_{1} = 2 ; n_{2} = 3, 4 ; region  visible
(iv) Pfund, n_{1} = 5 ; n_{2} = 6, 7; region  infrared
What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to ground state?
Maximum number of emission lines
What is the maximum number of emission lines obtained when the excited electron of a H atom in n = 5 drops to the ground state?
Number of lines produced when electron from nth shell drops,to ground state is given by
What is the colour corresponding to the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from n = 4 to n = 2?
Colour corresponding to this wavelength is blue.
_____series of lines are the only lines in hydrogen spectrum which appear in the visible region.
In Balmer series, the lines appear in visible region.
An electron in excited hydrogen atom falls from fifth energy level to second energy level. In which of the following regions, the spectrum line will be observed and is part of which series of the atomic, spectrum?
For Balmer series, n_{1} = 2, n_{2} = 3, 4, 5,....
The spectral lines are seen in visible region.
The third line of the Balmer series in the emission spectrum of the hydrogen atom is due to the transition from the
Rydberg’s formula for calculation of wavenumbers of hues in hydrogen spectrum is
For Balmer series, n_{1} = 2 and n_{2} = 3, 4, 5, so third line of the Balmer series is due to transition from fifth Bohr orbit to second Bohr orbit
The angular momentum of an electron in a given stationary state can be expressed as .
Based on this expression an electron can move only in those orbits for which its angular momentum is?
An electron can move only in those orbit for which angular momentum is a multiple of h/2π. n = 1,2,3,...
According to Bohr’s theory, the angular momentum of an electron in 5th orbit is
The radius of the stationary state which is also called Bohr radius is given by the expression r_{n} = n^{2}a_{0} where the value of a_{0} is
If the radius of first Bohr orbit is x pm, then the radius of the third orbit would be
r = x × n^{2} or (9 × x) pm
What does the negative electronic energy (negative sign for all values of energy) for hydrogen atom means?
The negative sign means that the energy of an electron iii an atom is lower than the energy of a free electron at rest. When electronis free from the influence of nucleus, the energy is taken as zero. When the electron is attracted by the nucleus, the energy is emitted and lowered.
If the ionisation energy of hydrogen atom is 13.6 eV, the energy required to excite it from ground state to the next higher state is approximately
Bohr’s theory can also be applied to the ions like
Bohr’s atomic theory is applicable to hydrogen and monoatomic ions like He^{+}, Li^{2+}, Be^{3+}, etc.
According to Bohr’s theory, the electronic energy of Hatom in Bohr’s orbit is given by
Which of the following is not correctly matched?
Energy of 1 mole of photons
where N_{0} is Avogadro’s number, h = Planck’s constant, c is speed of light and λ is wavelength.
What is the trend of energy of Bohr’s orbits?
Energy of the orbit increases as we move away from the nucleus or as the value of n increases.
The radius of hydrogen atom in ground state is 0.53 Å. What will be the radius of _{3}Li^{2+} in the ground state?
Radius of orbit is given by
What is the velocity of electron present in first Bohr orbit of hydrogen atom?
From Bohr’s theory,
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