Test: Cartesian Plane

 the distance of the point (-5, 6) from y- axis is |-5| units.

In general, the distance of the point (x,y) from x-axis is y and from y-axis is x.

we have, 

2 = (3p - 2)/2   and 2p + 2  = (2q + 4)/2

3p = 6  and 2p = q

p = 2

and q = 2p = 4

"The distance between the origin and the coordinates (2, 3) is

Square root of (2 – 0)^2 + (3 – 0)^2

Square root of 2^2 + 3^2

Square root of 4 + 9

Square root of 25

Hence 5 will be the total distance between the coordinates and origin.

In case of x-axis we will only consider the value of y coordinate that is 3.

Option C is correct answer.

For the given point  (2,1)

x = 2 and y = 1

Putting value in 2x + y = 5
2 (2) +1 = 5
5 = 5

So point (2,1) lies on the line 2x + y = 5

The distance of a point from the y -axis is always the value of it's x-coordinate

That is , the distance of point p(2,3 ) from y axis is 2 units.

Distance of point from y-axis is x -coordinate of given point,
So,since,value of x-coordinate is 4
so, distance = 4 unit 

This is because if it will be not 0 at then the point will fall somewhre else on the graph instead of y- axis.So the co-ordinatemust be (0,Y) to fall on y- axis.