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The pH of a solution formed by maixing 40.0 mL of 0.1 M HCl with 10.0 mL of NaOH is
40ml of 0.1MHCl
(0.1/1000)×40
= 0.004 moles of HCl
Similarly, 10ml of 0.45MNaOH
= (0.45)/1000 × 10
= 0.0045 moles of NaOH
Thus, NaOH left unneutralised = 0.0005 moles in a volume of 50ml
Concentration of NaOH = (1000×0.0005)/50=0.01
= 10-2M
Therefore, [OH-]=10-2M or [H+]
= 10-12M or pH = 12.0
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