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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Compensation Techniques - Electrical Engineering (EE) MCQ

Test: Compensation Techniques - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Compensation Techniques

Test: Compensation Techniques for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Compensation Techniques questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Compensation Techniques MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Compensation Techniques below.
Solutions of Test: Compensation Techniques questions in English are available as part of our course for Electrical Engineering (EE) & Test: Compensation Techniques solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Compensation Techniques | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Compensation Techniques - Question 1
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Assertion (A): The closed loop stability can be determined from the poles of an open loop system and the polar plot of the frequency response.
Reason (R): Unstable system has right half poles.

Detailed Solution for Test: Compensation Techniques - Question 1

Explanation: Closed loop system can be made stable if the poles of the closed loop system are all lying on the left half of the plane and this can be determined from the poles of an open loop system.

Test: Compensation Techniques - Question 2
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The open loop control transfer function of a unity feedback system is given by :
G(s) =K/(s+2)(s+4)(s^2+6s+25)
Which is the value of K which causes sustained oscillations in the closed loop system? 

Detailed Solution for Test: Compensation Techniques - Question 2

Explanation: The value of the sustained oscillations is calculated from the Rout-Hurwitz table by equation the quadratic equation=0.

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Test: Compensation Techniques - Question 3
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The characteristic equation of the control system is s5+15s4+85s3+225s2+274s+120=0 . What are the number of roots of the equation which lie to the left of the line s+1 = 0? 

Detailed Solution for Test: Compensation Techniques - Question 3

Explanation: The solution is obtained with the help of the Routh-Hurwitz table and in this the solution is obtained by equating the value as s-1 in the given equation.

Test: Compensation Techniques - Question 4
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The characteristic equation of a system is 2s5+s4+4s3+2s2+2s+1=0 . Which one of the following is correct? 
Detailed Solution for Test: Compensation Techniques - Question 4

Explanation: The solution is obtained by using the Routh-Hurwitz table in which with the conventional method the number of sign changes are seen in the first row of the table and number of sign changes is equal to the number of the roots on the right half of s plane.

Test: Compensation Techniques - Question 5
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The characteristic equation of a control system is given by s5+s4+2s3+2s2+4s+6=0. The number of the roots of the equation which lie on the right half of s-plane: 
Detailed Solution for Test: Compensation Techniques - Question 5

Explanation: The solution is obtained by using the Routh-Hurwitz table in which with the conventional method the number of sign changes are seen in the first row of the table and number of sign changes is equal to the number of the roots on the right half of s plane.

Test: Compensation Techniques - Question 6
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Which of the following may result in instability problem?
Detailed Solution for Test: Compensation Techniques - Question 6

Explanation: High gain results in instability problem and this is due to the low damping factor and damping factor is inversely proportional to the gain of the system.

Test: Compensation Techniques - Question 7
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For what values of K does the polynomial s4+8s3+24s2+32s+K=0 have roots with zero real parts? 
Detailed Solution for Test: Compensation Techniques - Question 7

Explanation: The solution is obtained by using the Routh-Hurwitz table and in which with the conventional method the number of sign changes are seen in the first row of the table and number of sign changes is equal to the number of the roots on the right half of s plane.

Test: Compensation Techniques - Question 8
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How many roots with positive real parts do the equation s3+s2-s+1=0 have? 
Detailed Solution for Test: Compensation Techniques - Question 8

Explanation: The roots with positive real parts are calculated with the help of the routh-hurwitz table and since the sign changes two times in first column therefore have two roots have positive parts.

Test: Compensation Techniques - Question 9
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Phase margin is always positive for stable feedback system?
Detailed Solution for Test: Compensation Techniques - Question 9

Explanation: Phase margin is calculated at the gain cross over frequency at which the gain is 1 and this is calculated for stability and is always positive for stable feedback system.

Test: Compensation Techniques - Question 10
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In closed loop control system, what is the sensitivity of the gain of the overall system, M to the variation in G?
Detailed Solution for Test: Compensation Techniques - Question 10

Explanation: The sensitivity of the control system is defined as the change in the output to the change in the input and senstivity of the gain of the overall system, M to the variation in G is 1/1+GH.

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Important Questions for Compensation Techniques

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