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Diffraction pattern cannot be observed with:
For diffraction, the width of the slit must be less than the wavelength of the incident ray.
Diffraction of light gives the information of:
Diffraction of light takes place for all types of waves transverse or longitudinal.
In a single slit experiment, suppose the slit width is equal to the wavelength of light used, then:
This is because for maximum diffraction the slit width always equals to the wavelength of light.
Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2m. What is the distance of the screen?
Beta(central Maxima) = 2 * lambda * D(distance of the screen) / d(distance between slits)
beta = 2 m, wavelength = 500nm = 5 ×10-7m & d = 0.1mm = 1×10-4m
► 2 = 2 × 5 × 10-7 * D/10-4
► 1 = 5 × 10-3 D
► D = 1000/5
► D = 200m
The phenomenon of diffraction can take place in sound waves?
What is the angular spread of the first minimum and the central maximum when diffraction is observed with 540 nm light through a slit of width 1mm?
The First minimum is located at the place where the central maximum ends. And the first minimum spreads further upto half the fringe width.
The change in the diffraction pattern of a single slit, when the monochromatic source of light is replaced by a source of white light will be:
The diffraction of light is not easily noticed if:
Actually, diffraction occurs all the time. But when the aperture/wavelength ratio is large, the spacing between fringes becomes too small, and the diffractive effects are unnoticeable.
In the diffraction of a single slit experiment, if the slit width is half then the width of the central maxima will be:
Fringe width is inversely proportional to the distance between slits so it will be doubled.
Which of the following undergoes the largest diffraction?