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# Test: Dimensional Geometry - 4

## 20 Questions MCQ Test Topic-wise Tests & Solved Examples for IIT JAM Mathematics | Test: Dimensional Geometry - 4

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This mock test of Test: Dimensional Geometry - 4 for Mathematics helps you for every Mathematics entrance exam. This contains 20 Multiple Choice Questions for Mathematics Test: Dimensional Geometry - 4 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Dimensional Geometry - 4 quiz give you a good mix of easy questions and tough questions. Mathematics students definitely take this Test: Dimensional Geometry - 4 exercise for a better result in the exam. You can find other Test: Dimensional Geometry - 4 extra questions, long questions & short questions for Mathematics on EduRev as well by searching above.
QUESTION: 1

### The equation of a straight line which makes an angle of 60° with x-axis and passes through the point (√3, 2) is given by

Solution:

The required equation
(i) makes an angle of 60° with x-axis
(ii) passes through the point (√3 , 2)
Now
(i) ⇒ equation of the straight line will be
y = tan 60° x + c
or y = √3 x + c ...(i)
(ii) ⇒ the coordinates of the point will satisfy equation (i) QUESTION: 2

### The line y - x + 2 = 0 cuts the line joining (3, -1) and (8, 9) in the ratio

Solution:

First remember the following points:
l.The equation of a line passing through two p o in ts (x1,y1) and (x2, y2) is given by 2. The. coordinates of the point R which divides the line joining P(x1,y1) and Q(x2, y2) internally in the ratio m1 : m2 are given by 3. If R divides PQ externally in the ratio m1 : m2, then Now the given straight line is
y - x + 2 - 0 ...(iv)
The equation of the straight line joining the points (3,-1) and (8, 9) is given by (see (i)) or y - 2x + 7 = 0 ...(v)
The point of intersection of (iv) and (v) is obtained on solving these equations and is given by (5,3)
Let the points of intersection (5, 3) divide the line joining (3. -4) and (8. 9) in the ratio m : n.
Then QUESTION: 3

### The equation of the straight line passing through (4, 5) and parallel to the line 2x - 3y = 5 is given by

Solution:

The given straight line is The equation of a straight line parallel to (i) will be Since (ii) passes through P(4, 5), therefore the coordinates of P A\*ill satisfy equation (ii) ∴ Required equation of the straight line is QUESTION: 4

The condition that the three straight lines
ax + by+ c = 0
a1x + b1y + c = 0
a2x + b2y + c2 = 0
may meet in a point, is that, the value of the determinant must be

Solution:

The condition for three lines lines to be concurrent is that QUESTION: 5

The point (x1,y1) lies on the positive side of the straight line Ax + By + C = 0

Solution:

First of all learn the following:
Division of a plane by the line
L : Ax + By + C = 0
As shown in the adjoining Figure, the line L divides the plane into three parts, namely I, L and II, where
Ax1 + By1 + C > 0 for all poins (x1, y1) in l
Ax2 + By2 + C = 0 for all points (x2, y2) on L
Ax3 + By3 + C < 0 for all points (x3, y3) in II

QUESTION: 6

The point (3, 2) lies on the

Solution:

Given point is (3, 2)
Given straight lines are   QUESTION: 7

When two straight lines 2x- 3y + 1 = 0 and 3x -6y + 2 = 0 are traced, we get four different compartments. Which of the following four points lie in the same compartment? A(0, 0), B(-1, 1), C(-7, -4), D(9, 6)

Solution:

The given straight lines are   QUESTION: 8

The angle between the lines ax + by + c = 0 and a'x  + b'x + c' = 0 is given by

Solution:

Comments. The angle φ between two straight lines
y = mx + c and y = m'x + c‘
is given by Since the straight lines are ax + by + c = 0 and a'x +b'y + c' = 0
therefore Both φ and π - φ shall be the angles between the given lines.

QUESTION: 9

The straight lines ax + by + c = 0 and a'x + b'y + c' = 0 arc perpendicular if

Solution:

The angle φ between the lines is given by  QUESTION: 10

The line passing through the origin is given by

Solution:

Remark: A straight line passing through the origin shall be of the form
y = mx
and there will not bo any constant term in the eouation.

QUESTION: 11

The four points (0, 4, 1), (2, 3, -1), (4, 5, 0). (2, 6, 2) are the vertices of a

Solution:
QUESTION: 12

Let A(3, 2, 0), B(5, 3, 2), C( 9, 6, -3) be the three points forming a triangle. Let the bisector of the angle BAC meet BC in D. Then D divides BC in the ratio of

Solution:
QUESTION: 13

Let A(-1,2, -3), B(5, 0, -6), C(0, 4, -1) be the three points. Then the direction cosines of the internal bisector of the angle BAC are proportional to

Solution:

Proof in short : verify that
AB = 7 and AC = 3  where θ is the angle between AB (with d.c.'s [l1, m1, n1]) and AC (with d.c.’s [l2, m2, n2)
∴ the d.c.’s of the internal bisector are proprotional to l1+l2, m1+m2, n1+n2
or proportional to or proportional to or proportional to 25, 8, 5

QUESTION: 14

Which of the following is incorrect?
If l1, m1, n1, : l2, m2, n2, : l3, m3, n3 be the direction cosines of three mutually perpendicular lines then

Solution:

In fact, we shall have QUESTION: 15

The direction ratios of the line, which is equally inclined to the three mutually perpendicular lines with direction cosines l1, m1, n1: l2, m2, n2 : l3, m3, n3; are given by

Solution:

Proof: Let the three mutually perpendicular lines be   QUESTION: 16

“If O, A, B, C be the four points not lying in the same plane such that OA ⊥ BC, OB ⊥ CA, then OC ⊥ AB". if the points O, A, B, C are coplanar, then the above reduces to

Solution:
QUESTION: 17

If a1, b1, c1 and a2, b2, c2 are the direction ratios of two lines, then the angle between them is not given by

Solution:
QUESTION: 18

If the edges of a rectangular parallelepiped are OA , OB and OC along coordinate axes such that OA = a, OB = b, OC = c and PL, PM and PN are the perpendiculars drawn from P(a, b, c) on XY, ZX and YZ planes respectively, then angle between OP and AN is given by

Solution:
QUESTION: 19

If a variable line in two adjacent positions has direction cosines as then the small angle dθ between those two positions.in given by

Solution:   QUESTION: 20

The area of the triangle with vertices (0, 0, 0), (0, b, 0) and (0, 0, c) is given by

Solution:

Proof: The area of the triangle OAB, where O is the origin and the coordinates of A and B are (x1, y1, z1) a n d [x2, y2, z2) respectively, Here since the coordinates of A and B are (0,b,0) and (0.0,c), therefore the required area A is given by