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Test: Dipole in Uniform & Non-Uniform Electric Field


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Test: Dipole in Uniform & Non-Uniform Electric Field - Question 1

Which among the following molecule is not a dipole?

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 1

Though water and ammonia are covalent molecules, they have a net dipole moment due to their distorted structure than the ideal one. Hydrochloric acid has a linear molecular structure but its net dipole moment is towards the Hydrogen atom. But methane has a symmetrical tetrahedral structure and its net dipole moment is zero hence it doesn’t behave as a permanent dipole. Methane solvents are therefore non-polar solvents.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 2

What is the dimension of the dipole moment?

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 2

The dipole moment is defined as the product of a charge and distance. The dimension of charge (current*time) is [I T] and the dimension of distance is [L]. Therefore the dimension of dipole moment is [L T I]. Its unit in the CGS and the SI system are esu*cm and C*m respectively.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 3

Dipole moment depends on _______

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 3

Dipole is defined as two equal but opposite charges, kept at a small distance and having a dipole moment. The dipole moment is simply the product of the electric charge and length of the dipole. The dielectric constant of the medium doesn’t affect the dipole moment i.e. dipole moment of an electric dipole will be the same in water as well as in the air.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 4

An electric dipole is placed inside a cube. What will be the nature of electric flux from the cube surface?

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 4

An electric dipole consists of two point charges. The amount of charges is the same but their polarities are different. Therefore the sum of total charges in a dipole is always 0. But flux from a closed surface is related to the total charge inside a surface. As the total charge inside the cube is zero, so there will be no flux coming out or going in towards the surface.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 5

If an electric dipole is placed in a uniform electric field ______ will act on the dipole.

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 5

Dipole is the combination of two equal but opposite charges, kept at a certain distance. If it is placed in a uniform electric field, both the charges will suffer the same but opposite forces on them. As a result, the net force on the dipole becomes zero, but due to equal and opposite forces acting on two different points, there is a net torque acting on the dipole.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 6

If an electric dipole is placed in a non-uniform electric field ______ will act on the dipole.

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 6

In the case of a non-uniform electric field, the force acting on both the charges of the dipole will be unequal. So, there will be a net force acting on the dipole in a certain direction. Also, there will be a torque due to two forces acting at two different points. But in case of a uniform electric field, the net force on the dipole will be zero but net torque will be non-zero.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 7

An electric dipole will be in stable equilibrium if the angle between the axis of the dipole and the electric field is ________

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 7

Torque acting on a dipole is p*E*sinθ where E is the electric field. Now θ is 0 degree, so sinθ becomes 0 and hence no torque acts on the dipole. So in this case, no force or torque acts on the dipole. Therefore it will be the condition of stable equilibrium. In the case of θ=180 degree, sinθ is also 0 but the condition is known as unstable equilibrium i.e. if we rotate the dipole a bit, it will not come back to its initial position.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 8

If a non-polar substance is placed in an electric field, what will happen?

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 8

A non-polar substance consists of a huge number of dipoles in it, but they are oriented randomly and hence the net dipole moment of the substance becomes 0 and it acts as a non-polar substance. But if it is placed in an electric field, the dipoles present in it will orient themselves in the direction of the field and hence a net dipole moment will be observed, known as induced dipole moment. No current flow or oscillation of the substance will be observed.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 9

1uC and -1uC are placed at a distance of 5 cm forming a dipole. What is the amount of torque required to place the dipole perpendicularly to an electric field of 3*105 N/C?

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 9

Dipole moment of the dipole = 1*10-6*5*10-2 C. m=5*10-8 C. m. Given the electric field-intensity is E=3*105 N/C. Therefore required torque will be p*E*sinθ where θ is the angle between the electric field and the dipole moment = 90 degrees. Therefore torque required in this case will be 5 *10-8*3*105*sin 90 N. m=15*10-3 N. m.

Test: Dipole in Uniform & Non-Uniform Electric Field - Question 10

If the force acting on a point charge kept on the axis of an electric dipole is F, what will be the amount of force if the distance of the point charge is doubled from the dipole?

Detailed Solution for Test: Dipole in Uniform & Non-Uniform Electric Field - Question 10

If the distance of a point charge, kept on the axis of a dipole, is sufficiently large than the separation between the charges of a dipole, then it can be shown that electric field E at a distance r from the dipole varies as E α 1/r3. Now if the distance becomes 2r, electric field intensity will decrease by a factor of 23=8 times. Therefore the force F will now become F/8.

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