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# Test: Discrete Time System Analysis

## 10 Questions MCQ Test Digital Signal Processing | Test: Discrete Time System Analysis

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This mock test of Test: Discrete Time System Analysis for Electrical Engineering (EE) helps you for every Electrical Engineering (EE) entrance exam. This contains 10 Multiple Choice Questions for Electrical Engineering (EE) Test: Discrete Time System Analysis (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Discrete Time System Analysis quiz give you a good mix of easy questions and tough questions. Electrical Engineering (EE) students definitely take this Test: Discrete Time System Analysis exercise for a better result in the exam. You can find other Test: Discrete Time System Analysis extra questions, long questions & short questions for Electrical Engineering (EE) on EduRev as well by searching above.
QUESTION: 1

### Resolve the sequence into a sum of weighted impulse sequences

Solution:

Explanation: We know that, x(n)δ(n-k)=x(k)δ(n-k)
x(-1)=2=2δ(n+1)
x(0)=4=4δ(n)
x(2)=3=3δ(n-2)
Therefore, x(n)= 2δ(n+1)+4δ(n)+3δ(n-2).

QUESTION: 2

### The formula​that gives the response y(n) of the LTI system as the function of the input signal x(n) and the unit sample response h(n) is known as:

Solution:

Explanation: The input x(n) is convoluted with the impulse response h(n) to yield the output y(n).As we are summing the different values, we call it as Convolution sum.

QUESTION: 3

### What is the order of the four operations that are needed to be done on h(k) in order to convolute x(k) and h(k)? Step-1:Folding Step-2:Multiplicaton with x(k) Step-3:Shifting Step-4:Summation

Solution:

Explanation: First the signal h(k) is folded to get h(-k). Then it is shifted by n to get h(n-k). Then it is multiplied by x(k) and then summed over -∞ to ∞.

QUESTION: 4

The impulse response of a LTI system is h(n)={1,1,1}. What is the response of the signal to the input x(n)={1,2,3}?

Solution:

Explanation: Let y(n)=x(n)*h(n)(‘*’ symbol indicates convolution symbol)
From the formula of convolution we get,
y(0)=x(0)h(0)=1.1=1
y(1)=x(0)h(1)+x(1)h(0)=1.1+2.1=3
y(2)=x(0)h(2)+x(1)h(1)+x(2)h(0)=1.1+2.1+3.1=6
y(3)=x(1)h(2)+x(2)h(1)=2.1+3.1=5
y(4)=x(2)h(2)=3.1=3
Therefore, y(n)=x(n)*h(n)={1,3,6,5,3}.

QUESTION: 5

Determine the output y(n) of a LTI system with impulse response h(n)=anu(n),|a|<1with the input sequence x(n)=u(n).

Solution:

Explanation: Now fold the signal x(n) and shift it by one unit at a time and sum as follows
y(0)=x(0)h(0)=1
y(1)=h(0)x(1)+h(1)x(0)=1.1+a.1=1+a
y(2)=h(0)x(2)+h(1)x(1)+h(2)x(0)=1.1+a.1+a2.1=1+a+a2
Similarly, y(n)=1+a+a2+….an= (1-a(n+1))/(1-a).

QUESTION: 6

x(n)*(h1(n)*h2(n))=(x(n)*h1(n))*h2(n)

Solution:

Explanation: According to the properties of convolution, Convolution of three signals obeys Associative property.

QUESTION: 7

Determine the impulse response for the cascade of two LTI systems having impulse responses h1(n)=(1/2)2 u(n) and h2(n)= (1/4)2 u(n).

Solution:

Explanation: Let h2(n) be shifted and folded.
so, h(k)=h1(n)*h2(n)=

For k<0, h1(n)= h2(n)=0 since the unit step function is defined only on the right hand side.

QUESTION: 8

x(n)*[h1(n)+h2(n)]=x(n)*h1(n)+x(n)*h2(n)

Solution:

Explanation: According to the properties of the convolution, convolution exhibits distributive property.

QUESTION: 9

An LTI system is said to be causal if and only if

Solution:

Explanation: Let us consider a LTI system having an output at time n=n0given by the convolution formula

=(h(0)x(n0)+h(1)x(n0-1)+h(2)x(n0-2)+….)+(h(-1)x(n0+1)+h(-2)x(n0+2)+…)
As per the definition of the causality, the output should depend only on the present and past values of the input. So, the coefficients of the terms x(n0+1), x(n0+2)…. should be equal to zero.
that is, h(n)=0 for n<0 .

QUESTION: 10

x(n)*δ(n-n0)=

Solution:

Explanation: