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Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - JEE MCQ


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10 Questions MCQ Test Physics for JEE Main & Advanced - Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution for JEE 2024 is part of Physics for JEE Main & Advanced preparation. The Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution questions and answers have been prepared according to the JEE exam syllabus.The Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution below.
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Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 1

A uniform surface charge density of 10 nC/m2 is present in the region x = 0,-2 ε = ε0The electric field at p(3,0,0) has

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 1


So there is only x component.

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 2

The electric field E at (1, 1, -1) due to three charge distributions – 10nC/m2 at plane x = 2, 15 nC/m2 at plane y = -3 and 10 π nc/m line charge at x = 0, z = 2 is

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 2

The electric charge distributions are as shown below

The filed due to plane y = 
The field due to plane x = 
The field due to line charge 
is the unit vector along perpendicular to the line charge passing through P.

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Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 3

Which of one of the following statements is not correct regarding potential due to a point charge?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 3

Concept:

The electric potential due to a point charge is given by:

where, V = Electrical potential 
Q = Point charge
d = Distance from charge
ϵo = Permittivity of free space
The relationship between potential and electric field intensity is:
E = V/d

Explanation:

From the above expressions, the electric potential is:

  • It is directly proportional to the magnitude of the charge.
  • It is inversely proportional to the distance from the charge.
  • It is independent of the relative permittivity of the medium in which the charge is placed but inversely proportional to the permittivity of free space.
  • It is directly proportional to the electric field intensity.
Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 4

An infinitely long uniform charge of density 30 nC/m is located at y = 3, z = 4. The field intensity at (0, 5, 1) is E. Now, what is the field intensity at (2, 5, 1)?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 4

Concept:

The magnitude of electric field intensity at a point P due to infinitely long uniform charge density λ is

r → the perpendicular distance from the point to the infinitely long charge density

Analysis:

Here, the point (0, 5, 1) and (2, 5, 1)

r is the same and is equal to

∴ the electric field will be same in both the cases.

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 5

The electric flux lines 

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 5

Electric flux lines originate from positive charges and terminate at negative charges as shown:​


Note: It is the magnetic field lines that form a closed loop as shown:

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 6

A point charge q is located at the origin. What is the electric field at a point P, located at a distance r from the origin along the x-axis?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 6

According to Coulomb's law, the electric field due to a point charge q at a distance r is given by E = (kq)/(r²), where k is the electrostatic constant.

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 7

A charged ring of radius R has a total charge Q. What is the electric field at the center of the ring?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 7

Due to the symmetry of the charged ring, the electric field vectors produced by each element of charge on the ring cancel each other at the center. Therefore, the net electric field at the center of the ring is zero.

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 8

A uniformly charged ring of radius R has a linear charge density λ. What is the electric field at a point on the axis of the ring at a distance x from the center?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 8

The electric field at a point on the axis of a uniformly charged ring is given by E = (kλ)/(4πx²), where k is the electrostatic constant, λ is the linear charge density, and x is the distance from the center of the ring.

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 9

A spherical shell has a positive charge Q distributed uniformly on its surface. What is the electric field inside the shell?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 9

According to Gauss's law, the electric field inside a uniformly charged spherical shell is zero. This is because the net flux through any closed surface inside the shell is zero, indicating that the electric field is zero.

Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 10

A uniformly charged rod of length L has a total charge Q. What is the electric field at a point P, located at a perpendicular distance r from the midpoint of the rod?

Detailed Solution for Test: Electric Field due to a Point charge, Charged Ring and Continuous Charge distribution - Question 10

The electric field at a point perpendicular to the midpoint of a uniformly charged rod is given by E = (kQ)/(4πr), where k is the electrostatic constant, Q is the total charge on the rod, and r is the distance from the midpoint.

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