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This mock test of Test: Factorisation- 2 for Class 8 helps you for every Class 8 entrance exam.
This contains 10 Multiple Choice Questions for Class 8 Test: Factorisation- 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

Factorise 12a^{2}b+ 15ab^{2}

Solution:

QUESTION: 2

Factorise: x^{2}+ 8x + 16

Solution:
C ) (x^2 +8x +16) = (x^2 + 4x ×4x + 16) = ( x^2 + 4x )(4x + 16 ) = x(x + 4 ) 4(x + 4 ) =(x + 4)(x + 4) =(x + 4)^2 OR(x^2 +8x + 16)(x^2 +2 × x × 4x + 4^2)(x + 4)^2

QUESTION: 3

Solve: –20(x)^{4 }÷ 10(x)^{2}

Solution:

QUESTION: 4

When we factorise an expression, we write it as a ________ of factors.

Solution:

QUESTION: 5

Factorise 6xy – 4y + 6 – 9x.

Solution:

QUESTION: 6

Factorize x² + 8x + 12

Solution:

Factors of 12x are 2*2*3*x and factors of 36 are 2*2*3*3. Hence the common factors are2*2*3 =12.

QUESTION: 7

Which of the following is quotient obtained on dividing –18 xyz^{2} by –3 xz?

Solution:

x and z gets cancelled ,-3 gets cancelled . So the quotient obtained is 6yz

QUESTION: 8

Divide the given polynomial by the given monomial: (5x^{2}− 6x) ÷ 3x

Solution:

QUESTION: 9

Divide as directed: 5 (2x + 1) (3x + 5) ÷ (2x + 1)

Solution:

QUESTION: 10

Factorise: p^{4}– 81

Solution:

We have p4 - 81 = (p^2)^2 - (9^2)^2

Now using a^2 - b^2 = (a + b)(a - b), we have

(p^2)^2 - (9)^2 = (p^2 + 9)(p^2 -9)

We can factorise p^2 - 9 further as

p^2 - 9 = (p)^2 - (3)^2

= (p + 3)(p - 3)

∴ p^4 - 81 = (p + 3)(p - 3)(p^2 + 9)

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