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(Q.1Q.3) A parallel resonant circuit has a resistance of 2k ohm and half power frequencies of 86 kHz and 90 kHz.
Q. The value of capacitor is
BW = 2p(9086)k = 1/RC or C = 19.89 nF.
w = (86 + 90)k/2 = 88 = (1/LC)^{(0.5)} or L = 0.16 mH.
Q = w/BW = 176pK/8pk = 22.
(Q.4Q.5) A parallel resonant circuit has a midband admittance of 25 X 10(3) S, quality factor of 80 and a resonant frequency of 200 krad s.4. The value of R (in ohm) is
At midband frequency Y = 1/R or R = 1000/25 or 40 ohm.
Q = wRC or C = 80/(200 x 1000 x 40) or 10 µF.
A parallel RLC circuit has R 1 k and C 1 F. The quality factor at resonance is 200. The value of inductor is
Use Q = R (L/C)^{0.5}.
A parallel circuit has R = 1k ohm , C = 50 µF and L = 10mH. The quality factor at resonance is
Use Q = R (L/C)^{0.5}.
A series resonant circuit has L = 1 mH and C = 10 F. The required R (in ohm) for the BW = 15 9 . Hz is
Use BW = R/L.
For the RLC parallel resonant circuit when R = 8k, L = 40 mH and C = 0.25 F, the quality factorQ is
use Q = R (C/L)^{0.5}.
A series resonant circuit has an inductor L = 10 mH. The resonant frequency w = 10^6 rad/s and bandwidth is BW = 10^{3} rad/s. The value of R and C will be
Use wxw = 1/LC and BW = R/L.
Correct Answer : a
Explanation : LC combination
3 = v_{1} + 10(v_{1}  0.105v_{1})/125
= v_{1} = 100
Isc = 1100/125
= 0.8V
RTH = 3/0.8
= 3.75 ohm
Wo = 1/(LC)1/2
= 1000
Q = w0L/RTH
= (1000*4)/3.75
= 1066.67
v_{c}_{max} = Q*vTH
= 1066.67*3
= 3200V
The value of input frequency is required to cause a gain equal to 1.5. The value is
In the circuit shown phase shift equal to 45 degrees and is required at frequency w = 20 rad/s. The value of R (in kiloohm) is
For the circuit shown the input frequency is adjusted until the gain is equal to 0.6. The value of the frequency is
For a stable closed loop system, the gain at phase crossover frequency should always be:
Phase crossover frequency is the frequency at which the gain of the system must be 1 and for a stable system the gain is decibels must be 0 db.
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