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A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.1. The value of capacitor is
BW = ω_{2}  ω_{1} = 2π(90  86)k = 8π krad/s
= 19.89 nF
A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.The value of inductor is
= 0.16 mH
A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.The quality factor is
A parallel resonant circuit has a midband admittance of 25 x 10^{3} S, quality factor of 80 and a resonant frequency of 200 krad/s.The value of R is
Ay midband frequency Z = R, Y = 1/R
A parallel resonant circuit has a midband admittance of 25 x 10^{3} S, quality factor of 80 and a resonant frequency of 200 krad/s.The value of C is
= 10 μF
A parallel RLC circuit has R =1 kΩ and C = 1 μF. Thequality factor at resonance is 200. The value of inductor is
⇒ L = 25 μH
A parallel circuit has R =1 k , C = 50 μF and L = 10mH. The quality factor at resonance is
A series resonant circuit has an inductor L = 10 mH.The resonant frequency ω_{o} = 106 rad/s and bandwidth is BW = 10^{3} rad/s. The value of R and C will be
= 100pF
A series resonant circuit has L = 1 mH and C = 10μF. The required R for the BW 15 9 . Hz is
⇒
For the RLC parallel resonant circuit when R = 8 kΩ , L = 40 mH and C = 0.25 μF, the quality factor Q is
Thevenin equivalent seen by L  C combination
Open Circuit : v_{1} = 0, v∝ = 3V
For the circuit shown in fig. resonant frequency f_{o} is
Applying 1 A at input port V_{1} = 10 V
voltage across 1 A source
Z_{in} = V_{test}
At resonance Im {Z_{in}} = 0
⇒ ⇒
For the circuit shown in fig. the resonant frequency f_{o} is
At resonance Im {Y} = 0
The value of input frequency is required to cause again equal to 1.5. The value is
For any value of ω, R,C gain ≤ 1.
Thus (D) is correct option.
In the circuit of fig. phase shift equal to 45^{0} is required at frequency ω =20 rad/s . The value of R is
phase shift =  tan^{1} ωCR = 450°
ωCR = 1,
20 x 1 x 10^{6} R = 1 ⇒ R = 50KΩ
For the circuit of fig., Vs is the source voltage and the response is the resistance voltage Vo, R = 30Ω and L = 2H. Suppose the input frequency is adjusted until the gain is equal to 0.6. The value of the frequency is
Bode diagram of the network function V_{o} /V_{s }for the circuit of fig. is
20 dB/decade line starting from ω = 5.56 rad/s
20 dB/decade line starting from ω = 16.67 rad/s
Hence 20 dB/decade line for 5.56 < ω < 16.67 parallel to ω axis to ω >16.67
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