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Test: General Properties of d-Block Elements

25 Questions MCQ Test Topic-wise MCQ Tests for NEET | Test: General Properties of d-Block Elements

Description

Attempt Test: General Properties of d-Block Elements | 25 questions in 35 minutes | Mock test for NEET preparation | Free important questions MCQ to study Topic-wise MCQ Tests for NEET for NEET Exam | Download free PDF with solutions

QUESTION: 1

Only One Option Correct Type

Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q.

Atomic number of second transition series lies from

A.
38 to 47
B.
39 to 48
C.
40 to 49
D.
41 to 50

Solution:

Since,1st transition series belongs to 3d orbital and 2nd transition series belongs to 4d-orbital. According to the given option, atomic number 39 to 48 (5s²4d^1-10) belongs to second transition series.

QUESTION: 2

Which has lower standard reduction potential (SRP) value?

A.
Mn²⁺/Mn
B.
Zn²⁺ /Zn
C.
Fe²⁺/Fe
D.
Ni²⁺ /Ni

Solution:

Mn²⁺/ Mn have - 1.18SRPvalue.

QUESTION: 3

An element has configuration 4d⁵5s². The element belongs to

A.
3rd group and 4th period
B.
5th group and 5th period
C.
7th group and 5th period
D.
7th group and 7th period

Solution:

Ford-block elements, group number is equal to the number of electrons in (n - 1)d subshell + number of electrons in valence shell (nth shell).

QUESTION: 4

The electronic configuration of palladium is

A.
[Ar] 4f¹⁴ 5d⁹6s¹
B.
[Kr] 4d⁸ 5s²
C.
[Kr] 5d⁸6s²
D.
[Kr]4d¹⁰5s⁰

Solution:

[Kr]4d¹⁰5s⁰

QUESTION: 5

Which has lowest and highest first ionisation enthalpy in 3d series?

A.
Sc and Zn
B.
Zn and Sc
C.
Cu and Zn
D.
Cr and Zn

Solution:

Sc (3d¹4s²)has 631 kJ mol^-1 and Zn (3d¹⁰ 4s²) has 906 kJ mol^-1

QUESTION: 6

The electronic configuration of the element which is just above the element with atomic number 42 in the same group

A.
[Ar] 3d⁴4s²
B.
[Ar] 3d³4s¹
C.
[Ar] 3d⁵ 4s¹
D.
[Ar] 3d¹⁰ 4s¹

Solution:

The element lying above Z = 42 has Z value 24, i.e. chromium. Hence, Cr configuration is [Ar]3d⁵4s¹

QUESTION: 7

Which one of the following exists in the oxidation state other than +3?

A.
B
B.
Al
C.
Ce
D.
Ga

Solution:

The correct answer is option C

Ce exist in the oxidation state other than +3 .

(a) B - Boron has +1 and +3 oxidation state.

(b) Al - Aluminium has +1,+2 and +3 oxidation state.

(d) Ga - Gallium has +1 and +3 oxidation state.

Cerium (Ce) have [Xe] 4f²6s² electronic configuration.

QUESTION: 8

Electronic configuration of a transition element X in +3 oxidation state is [Ar] 3d⁵ and Y in +2 state is [Ar] 3d⁸. What are the atom ic numbers of the elements?

A.
23 and 26
B.
26 and 28
C.
21 and 25
D.
24 and 26

Solution:

Fe (Z = 26) in + 3 oxidation state show Fe³⁺ ([Ar] 3d⁵) configuration. Ni(28) in +2 oxidation state show Ni²⁺([Ar]3d⁸) configuration.

QUESTION: 9

The atomic radii of Cu and Ag are 1.17 Å and 1.34 Å. The atomic radius of gold is expected to be

A.
1.41 Å
B.
1.51 Å
C.
1.34 Å
D.
1.12 Å

Solution:

Due to lanthanide contraction, Ag and Au have nearly same size.

QUESTION: 10

A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube. The red solid is

A.
(NH₄)₂Cr₂O₇
B.
HgI₂
C.
HgO
D.
Pb₃O₄

Solution:

*Multiple options can be correct

QUESTION: 11

One or More than One Options Correct Type

Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Identify the pairs in which one covalent radii of elements are almost similar.

A.
Nb and Ta
B.
Mo and W
C.
La and Lu
D.
Sc and Y

Solution:

Due to lanthanide contraction.

QUESTION: 12

Which one is of the following is the lightest transition element?

A.
Ti
B.
Sc
C.
Fe
D.
Hg

Solution:

The correct answer is Option B.

Sc has the lowest density (3.1 g cm−3). It is the lightest transition element.

*Multiple options can be correct

QUESTION: 13

Which of the following have pseudo noble gas configuration?

A.
Cu²⁺
B.
Zn²⁺
C.
Ag⁺
D.
Au³⁺

Solution:

An element with pseudo noble gas configuration has 18 electrons in the highest energy level instead of 8.
Zn²⁺(28) = 3s², 3p⁶, 3d¹⁰
Ag⁺ (46) = 4s²4p⁶4d¹⁰

*Multiple options can be correct

QUESTION: 14

Which one of the following is a diamagnetic ion?

A.
CO²⁺
B.
Cu²⁺
C.
Mn²⁺
D.
Sc³⁺

Solution:

The correct answer is option A,D.
About two–thirds of all metals crystallize in closest-packed arrays with coordination numbers of 12. Metals that crystallize in an HCP structure include Cd, Co, Li, Mg, Na, and Zn, and metals that crystallize in a CCP structure include Ag, Al, Ca, Cu, Ni, Pb, and Pt.

*Multiple options can be correct

QUESTION: 15

The pair of ions that have same electronic configuration

A.
Fe²⁺ and Mn²⁺
B.
Fe²⁺ and Co³⁺
C.
Fe³⁺ and Co³⁺
D.
V²⁺ and Cr³⁺

Solution:

Both Fe²⁺ and Co³⁺ have [Ar] 3d⁶ configuration while V²⁺ and Cr³⁺ have [Ar] 3d³.

QUESTION: 16

Comprehension Type

Direction (Q. Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

The atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.
The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.

Which pair of elements has nearly same atomic size?

A.
Sc and Y
B.
V and Zr
C.
Zr and Hf
D.
La and Y

Solution:

Due to lanthanide contraction.

QUESTION: 17

Passage

The metal with high melting point in 3d series is

A.
Cu
B.
Zn
C.
Cr
D.
Fe

Solution:

The high melting point of Cr metal is attributed to the involvement of greater number of electrons from (n - 1) d in addition to ns electrons in the interatomic metallic bonding.

QUESTION: 18

Matching List Type

Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Match the Column I with Column II and mark the correct option from codes given below.

Solution:

(i) → (s), (ii) → (r), (iii) → (q), (iv) → (p)

QUESTION: 19

Which one of the following ions exhibits colour in aqueous solution

A.
Sc³⁺
B.
Ni²⁺
C.
Ti⁴⁺
D.
Zn²⁺

Solution:

*Answer can only contain numeric values

QUESTION: 20

One Integer Value Correct Type

Direction (Q. Nos. 20-23) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

The number of elements that do not have completely filled d subshell among the elements Ni, Pd, Pt, Cu, Ag, Au, Zn, Cd and Hg are

Solution:

Ni has 3d⁸4s² and Pt has 5d⁹6s¹.

*Answer can only contain numeric values

QUESTION: 21

Total spin of the electrons in a chromium atom is

Solution:

Chromium has 6 unpaired electrons and hence, its spin value is - 3 or +3. Cr,

There are 6 unpaired electrons in chromium.

*Answer can only contain numeric values

QUESTION: 22

Number of electrons with l = 2 and s = 1/2 in zinc atom are

Solution:

l = 2 means d-subshell. Zinc has 10 electrons ind-subshell in which 5 electrons are + 1/2 spin and 5 electrons are - 1/2.

*Answer can only contain numeric values

QUESTION: 23

Number of elements that generally do not show variable valencies Cu, Zn Au, Cd, Sc, La, Pt, Co.

Solution:

Zn, Cd, Sc and La do not show variable valencies.

QUESTION: 24

During the process of electrolytic refining of copper, some metals present as impurity settle as ‘anode mud’ These are

A.
Sn and Ag
B.
Pb and Zn
C.
Ag and Au
D.
Fe and Ni

Solution:

The correct answer is option C
In Electrolytic refining, the impure metal is made to act as an anode. A strip of the same metal in pure form is used as a cathode.
They are put in a suitable electrolytic bath containing a soluble salt of the same metal.
The more basic metal remains in the solution and the less basic ones go to the anode mud.
Copper is refined using an electrolytic method.
Impurities from the blister copper deposit as anode mud which contains antimony, selenium, tellurium, silver, gold, and platinum; recovery of these elements may meet the cost of refining.

QUESTION: 25

Statement Type

Direction (Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Statement I : The highest oxidation state of osmium is +8.

Statement II : Osmium is a 5-d block element.

A.
Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I
B.
Both Statement I and Statement II are correct but Statement II is the correct explanation of Statement I
C.
Statement I is correct but Statement II is incorrect
D.
Statement II is correct but Statement I is incorrect

Solution:

Osmium has the electronic configuration 5de⁶s². As 5d and 6s are close in energy, all the 8 electron can participate in bonding. highest oxidation state of osmium is +8 due to its ability to expand their octet by using its all 8 electrons (2 from 6s and 6 from 5d).