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Test: Hydrogen Bonding - NEET MCQ


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17 Questions MCQ Test Chemistry Class 11 - Test: Hydrogen Bonding

Test: Hydrogen Bonding for NEET 2024 is part of Chemistry Class 11 preparation. The Test: Hydrogen Bonding questions and answers have been prepared according to the NEET exam syllabus.The Test: Hydrogen Bonding MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Hydrogen Bonding below.
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Test: Hydrogen Bonding - Question 1

Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Which of the following compounds are soluble in H2O ? 

Detailed Solution for Test: Hydrogen Bonding - Question 1




All these are soluble in water due to intermolecular H-bonding.

Test: Hydrogen Bonding - Question 2

Which of the following has maximum boiling point?

Detailed Solution for Test: Hydrogen Bonding - Question 2

Due to intermolecular H-bonding at two terminals boiling point of glycol is maximum.

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Test: Hydrogen Bonding - Question 3

In which of the following boiling point of Column I is not higher than that of Column II?

Detailed Solution for Test: Hydrogen Bonding - Question 3

(a) Intermolecular H-bonding, boiling point increases with molecular weight for compounds within the same family.
(b) H-bonding is absent is CH3CH2CH3.
(c) Methanol is the larger molecule but H2O has more H-bonding because of two O—H bonds.
Thus, boiling point of H2O(ll) > CH3OH(l).
(d) Molecular weight of butanol is much higher and overcomes attractive forces of butanol.

Test: Hydrogen Bonding - Question 4

Which of the following correctly represents H-bonding?

Detailed Solution for Test: Hydrogen Bonding - Question 4

H-bonding is between polar and electronegative 0, N and F C-atom or H attached to C is not polar. Thus, (a), (c), (d) are incorrect.

Test: Hydrogen Bonding - Question 5

In dimer formation of which O-atom(s) is/are involved through H-bonding?

Detailed Solution for Test: Hydrogen Bonding - Question 5

Test: Hydrogen Bonding - Question 6

In the following compounds, select the points of interm olecular H-bonding (linear),

Detailed Solution for Test: Hydrogen Bonding - Question 6


1. Enoiic H, acidic and polar takes part in H-bonding.
2. 3° alcohol least acidic maximum basic.
3. Carbonyl oxygen is not involved.
4. Acidic and polar H, takes part in H-bonding.

Test: Hydrogen Bonding - Question 7

In the following alcohol, which — OH group is involved to the maximum extent in H-bonding?

Detailed Solution for Test: Hydrogen Bonding - Question 7

O — H group is attached to (ene) is m ost a cidic and thus, has maximum intermolecular H-bonding.

Test: Hydrogen Bonding - Question 8

Among the following sets, highest boiling points are of the species.

I. HF, HCI, HBr, HI
II. H2O, H2S, H2Se, H2Te
III. NH3,PH3, AsH3,SbH3

Detailed Solution for Test: Hydrogen Bonding - Question 8

F, O and N are electronegative elements. Thus, HF molecules are associated by intermolecules H-bonding giving it a liquid state and thus highest boiling point out of HF, HCl.HBr and HI.
Similarly, H2O has highest boiling point, and NH3 has highest boiling point.

Test: Hydrogen Bonding - Question 9

The H-bond is shortest in 

Detailed Solution for Test: Hydrogen Bonding - Question 9

A hydrogen bond is a weak type of force that forms a special type of dipole-dipole attraction which occurs when a hydrogen atom bonded to a strongly electronegative atom exists in the vicinity of another electronegative atom with a lone pair of electrons.
F is the most electronegative atom. Hence hydrogen bond is shortest in F - H ........F.

Test: Hydrogen Bonding - Question 10

What is the dominant intermolecular force or bond that must be overcome in converting liquid CH3CH2OH to vapours?

Detailed Solution for Test: Hydrogen Bonding - Question 10

CH3CH2OH is in liquid state due to association as a result of intermolecular H-bonding.

Test: Hydrogen Bonding - Question 11

Number of water molecules directly attached to one water molecule is

Detailed Solution for Test: Hydrogen Bonding - Question 11


One water molecule is directly attached to four water molecules. Thus, coordination number of water is 4.

Test: Hydrogen Bonding - Question 12

Consider the following compounds

I. HCI
II. HF
III. CH3COOH
IV. CH4
V. CH3OH
VI. CH3COO-

Q. 
H-bonding is not present in

Detailed Solution for Test: Hydrogen Bonding - Question 12

HCI: EN of Cl is smaller, hence less polar than HF.
CH4 :non-polar
CH3COO- : H attached to C-atom is non-polar hence
HCI, CH4, CH3COO- — lack H-bonding.

*Multiple options can be correct
Test: Hydrogen Bonding - Question 13

Direction (Q. Nos. 13-16) This section contains 4 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

Q.
In which of the following I is more volatile than II?
 

Detailed Solution for Test: Hydrogen Bonding - Question 13


I. Intermolecular H-bonding makes boiling point higher than that of I. Thus, I is more volatile 

II. Ortho nitrophenol is more volatile than para nitrophenol because O-Nitrophenol has intramolecular hydrogen bonding whereas para nitrophenol has inter molecular H bonding and so boils relatively at higher temperature
(c) BP of H2O > > H2S
(d) BP of CH3CH2OH (due to H-bonding) > > CH3— O — CH3 

*Multiple options can be correct
Test: Hydrogen Bonding - Question 14

Hydrogen bonding plays a central role in the following phenomenon

[JEE Advanced 2014]

Detailed Solution for Test: Hydrogen Bonding - Question 14

(a) When liquid water changes to ice, there is an air gap inside the cage formed due to intermolecular H-bonding. Thus, volume of ice > volume of water.


Hence, density (ice) < density (water).
Thus, ice floats on water - hydrogen bonding plays its role.
(b) In gaseous phase, basicity of 1° < 2° < 3° amines due to increase of electron density at N-atom

But in aqueous (H2O) solvent, RNH2 is stabilised by solvation. Thus 1° amine is more

basic than 3° amine (3° < 1° < 2°) amines.
(c) l+ (positive inductive effect) explains this

Dimer due to intermolecular H- bonding.

*Multiple options can be correct
Test: Hydrogen Bonding - Question 15

Which of the following molecules are stabilised by intramolecular H-bonding?

Detailed Solution for Test: Hydrogen Bonding - Question 15

(a) intramolecular H-bonding.



*Multiple options can be correct
Test: Hydrogen Bonding - Question 16

Out of

Q. unstable compound is/are 

Detailed Solution for Test: Hydrogen Bonding - Question 16

I. CCI3CH (OH)2 with two — OH groups on same carbon atom is stable due to intramolecular H-bonding.



Test: Hydrogen Bonding - Question 17

Direction (Q. Nos. 17) Choice the correct combination of elements and column I and coloumn II  are given as option (a), (b), (c) and (d), out of which ONE option is correct.

Q. Match the species in Column I with rank order of their boiling point in Column II. (Species with lowest boiling points is at SN1).

Detailed Solution for Test: Hydrogen Bonding - Question 17

n-butane lacks H-bonding. Hence, its boiling point is least. 

due to difference in polar H+ for H-bonding.
Boiling point of CH3CH2CH2CH2OH > H2O due to much larger size of alcohol.

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