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An integer on the horizontal number line is greater than the number on its left and less than the number on its right.
Therefore, here 1 will be greater than 5.
If a x (b − c) is 8 for a = 2, b = 10 and c = 6 then a x b − a x c is equal to:
By Distributive law,
a x (b − c) = a x b  a x c
⇒ a x b  a x c = 8
Alternative method
a x b  a x c = 2 x 10  2 x 6
⇒ a x b  a x c = 20  12 = 8 [using BODMAS]
Thus, option D is the correct.
The product of 3 negative integers will always be negative.
a * (a) = a^{2}
(a) * (a) = a^{2}
(a) * (a) * (a) = a^{2} * (a) = a^{3}
The additive identity property says that if you add an integer to zero or add zero to the integer, then you get the same integer back i.e. a + 0 = 0 + a = a.
Thus, 0 is an additive identity for the integers.
According to Distributive Law of Multiplication over Addition, a x (b + c) must be equal to:
According to Distributive Law of Multiplication over Addition:
a x (b + c) = a x b + a x c
x gives the absolute value of x i.e. the magnitude of the real number without regard to its sign.
The magnitude of a number is its size.
Therefore, I89I = 89, I21I = 21
Thus, option C is correct.
The multiplicative identity of any integer p is a number q which when multiplied with p, leaves it unchanged, i.e. p × q = p.
Since, p × 1 = p = 1 × p
Therefore, 1 is the multiplicative identity for integers.
The additive inverse of a number x is the number that, when added to x, gives zero i.e. x + (x) = 0.
This number is also known as the opposite number.
Thus, 7 is the additive inverse of 7.
The integers between 8 & 2 are: 7 , 6 , 5 , 4 , 3 , 2 , 1 , 0 , 1
⇒ There are 9 integers between 8 & 2.
Firstly we will solve brackets according to BODMAS rule,
(4) x (9) x (25) = 900
(2) x (3) x (5) = 30
⇒ [(4) x (9) x (25)] ÷ [(2) x (3) x (5)] = (900)/(30) = 30
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