The half life of a first order reaction is equal to:
The correct answer is Option C
For a first-order reaction, the half-life is given by: t1/2 = 0.693/k
For zero order reaction, linear plot was obtained for [A] vs t, the slope of the line is equal to:
For zero order reaction the rate equation is [A] = -kt + [Ao]
Thus the slope of the line is -ko
The first order rate constant for the decomposition of N2O5 is 6.2 x 10-4 sec-1. The t1/2 of the decomposition reaction is
The correct answer is option B
t1/2 = k0.693
= 0.693/(6.2 × 10− 4) = 1117.7s
Find the overall order of a reaction whose rate constant is k = 3x10-4 s-1
The correct answer is option D
Units:- for K can be calculated by (Mole)1-n (Litre )n-1 Time -1...
Here,n is the order of the reaction ....
On substituting n = 1.
We get, K units as;
K = (Mole)1-1( Litre)1-1 sec-1.
Which of the following represents the expression for the 3/4th life of a first order reaction?
The correct answer is option A
As we know, for a first order reaction,
The type of reaction that gives constant half life is
The correct answer is Option A
For first order reaction, the half-life period is independent of initial concentration.
For first order reaction, the half-life period expression (t1/2) is given by the expression t1/2= , where k is the rate constant.
The half life period of first order reaction is 15 min. Its rate constant will be equal to
The half life of a reaction is 15 min
Here we go..
Formula to be used :
K =0.693/t = 0.693/15
__= 0.462/10 = 0.0462 min^-1
For zero order reaction, the integrated rate equation is:
The half life of a zero order reaction is equal to:
[A] = -kt + [A]0
Here, [A] = [A0]/2
[A]0/2 = -kt + [A]0
kt = [A]0 - [A]0/2
t = [A]0/2k
t1/2 = [A]0/2k
If [A] is the concentration of reactant A at any time t and [Ao] is the concentration at t=0, then for the first order reaction the rate equation can be written as: