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# Test: Inverse Trigonometry -1

## 25 Questions MCQ Test Mathematics (Maths) Class 12 | Test: Inverse Trigonometry -1

Description
This mock test of Test: Inverse Trigonometry -1 for JEE helps you for every JEE entrance exam. This contains 25 Multiple Choice Questions for JEE Test: Inverse Trigonometry -1 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Inverse Trigonometry -1 quiz give you a good mix of easy questions and tough questions. JEE students definitely take this Test: Inverse Trigonometry -1 exercise for a better result in the exam. You can find other Test: Inverse Trigonometry -1 extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

Solution:
QUESTION: 2

Solution:
QUESTION: 3

### If 2tan−1(cos x) = tan−1(2cosec x) , then x =

Solution:

If 2 tan-1 (cos x) = tan -1(2 cosec x),

2tan-1(cos x) = tan-1 (2 cosec x) = tan-1(2 cosec x) = cot x cosec x = cosec x = x = π/4

QUESTION: 4

tan−1(−2) + tan−1(−3) is equal to

Solution:

tan-1(-2) + tan-1(-3)  QUESTION: 5

The values of x which satisfy the trigonometric equation are :

Solution:     QUESTION: 6

The maximum value of sin x + cos x is

Solution:
QUESTION: 7

The value of tan15+ cot15is

Solution:

The value of tan150 + cot 150 QUESTION: 8 is equal to

Solution: QUESTION: 9

The number of solutions of the equation sin-1 x - cos-1 x = sin-1(1/2) is

Solution:   Hence , the given equation has only one solution.

QUESTION: 10 Solution: cot-1a - cot-1b + cot-1 b - cot-1 c - cot-1 a = 0

QUESTION: 11

The minimum value of sin x − cos x is

Solution: QUESTION: 12

sin (200)0 + cos (200)0 is

Solution:

Because both sin 2000 and cos 2000 lies in 3rd quadrant. In 3rd quadrant values of sin and cos are negative.

QUESTION: 13

If cos(-1)x + cos(-1)y = 2π, then the value of sin(-1)x + sin(-1)y is

Solution:

If cos(-1)x + cos(-1) y = 2π, then the value of sin(-1)x + sin(-1)y  = π−2π = −π.

QUESTION: 14

Domain of f(x) = sin−1x−sec−1x is

Solution:

Since sin−1x is defined for |x|⩽1, and sec−1x is defined for |x|⩾1,therefore,f(x) is defined only when|x|=1.so, Df = {−1,1}.

QUESTION: 15

The value of sin is

Solution:

put therefore the given expressionis sin2θ = 2sinθcosθ QUESTION: 16

If 5 sin θ = 3, then is equal to

Solution: QUESTION: 17

If sin A + cos A = 1, then sin 2A is equal to

Solution:

(sinA+cosA)2
= sin2A+cos2A+2sinAcosA
=11+sin2A=1sin2A=0.
(because Sin 2A = 2sin A cos A)

QUESTION: 18

If θ = cos-1 , then tan θ is equal to

Solution:  Therefore, tanθ = QUESTION: 19

The number of solutions of the equation cos-1(1-x) - 2cos-1 x = π/2 is

Solution:

As no value of x in (0, 1) can satisfy the given equation.Thus, the given equation has only one solution.

QUESTION: 20

tan (sin−1x) is equal to

Solution: QUESTION: 21

If x ∈ R, x ≠ 0, then the value of sec θ + tan θ is

Solution:    QUESTION: 22

The value of cos 1050 is

Solution:
QUESTION: 23

If cos(2sin−1x) = 1/9 then x =

Solution:

Put

sin-1 x = θ ⇒ x = sin θ  QUESTION: 24 Solution:      QUESTION: 25

cot (cos−1x) is equal to

Solution:

Put,
cos-1x = θ ⇒ x = cos θ ⇒ cos θ 