GMAT Exam  >  GMAT Tests  >  Quantitative for GMAT  >  Test: LCM & GCD - 3 - GMAT MCQ

Test: LCM & GCD - 3 - GMAT MCQ


Test Description

15 Questions MCQ Test Quantitative for GMAT - Test: LCM & GCD - 3

Test: LCM & GCD - 3 for GMAT 2024 is part of Quantitative for GMAT preparation. The Test: LCM & GCD - 3 questions and answers have been prepared according to the GMAT exam syllabus.The Test: LCM & GCD - 3 MCQs are made for GMAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: LCM & GCD - 3 below.
Solutions of Test: LCM & GCD - 3 questions in English are available as part of our Quantitative for GMAT for GMAT & Test: LCM & GCD - 3 solutions in Hindi for Quantitative for GMAT course. Download more important topics, notes, lectures and mock test series for GMAT Exam by signing up for free. Attempt Test: LCM & GCD - 3 | 15 questions in 30 minutes | Mock test for GMAT preparation | Free important questions MCQ to study Quantitative for GMAT for GMAT Exam | Download free PDF with solutions
Test: LCM & GCD - 3 - Question 1

What is HCF of  36/75, 48/150 , 72/135? 

Detailed Solution for Test: LCM & GCD - 3 - Question 1



Test: LCM & GCD - 3 - Question 2

Rajesh had to arrange his books in uniform groups. He makes groups of 4 books each. But 3 books are left. He tries it with groups of 5 books each. But still 3 books are left. 3 books are still left when he tried with groups of 9 or 10 books each. How many books does he have?

Detailed Solution for Test: LCM & GCD - 3 - Question 2

Since we need total number of books, we must find LCM of 4,5,9,10

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: LCM & GCD - 3 - Question 3

HCF and LCM of two numbers is 8 and 96. Sum of those numbers is 56. Then what is sum of their reciprocals?

Detailed Solution for Test: LCM & GCD - 3 - Question 3


Test: LCM & GCD - 3 - Question 4

What is LCM of  36/225, 48/150 , 72/65 ? 

Detailed Solution for Test: LCM & GCD - 3 - Question 4


Numerators = 36, 48 and 72.
72 is largest number among them. 72 is not divisible by 36 or 48
Start with table of 72.
72 x 2 = 144 = divisible by 72, 36 and 48
∴ LCM of numerators =144
Denominators= 225, 150 and 65.
We can see that they can be divided by 5.
On dividing by 5 Imeget 45, 30 and 13
We cannot divide further. So, HCF = GCD =5 

Test: LCM & GCD - 3 - Question 5

Manoj wants to paste wallpaper on wall of his room. The wall is 4 meters and 50 cm in length and 3 meters and 50 cm in height. But the wall should be covered completely only by square pieces of wallpaper having same size. What is the number of maximum sized wallpaper squares needed to cover the walls completely?

Detailed Solution for Test: LCM & GCD - 3 - Question 5

Wall can be covered only by using square sized wallpaper pieces.
Different sized squares are not allowed.
Length = 4 m 50 cm = 450 cm ; Height = 3 m 50 cm = 350 cm
Maximum square size of possible means HCF of 350 and 450
We can see that 350 and 450 can be divided by 50.
On dividing by 50, we get 7 and 9.
Since we cannot divide further, HCF = 50 = size of side of square 

Test: LCM & GCD - 3 - Question 6

The ratio of two numbers is 5 : 6 and their LCM is 480, then their HCF is?

Detailed Solution for Test: LCM & GCD - 3 - Question 6


Test: LCM & GCD - 3 - Question 7

The length and breadth of a rectangular floor are 16.25 metre and 12.75 metre respectively. Find how many minimum number of square tiles would be required to cover it completely? 

Detailed Solution for Test: LCM & GCD - 3 - Question 7

Since we require minimum number of square tiles, the size of the tile is given as the H.C.F. of two sides of the room. The H.C.F. Of 1625 cm & 1275 cm. is 25 cms. Hence, we get,
Required Number = (1625 * 1275) / (25 * 25) = 3315

Test: LCM & GCD - 3 - Question 8

The L.C.M. of two number is 60. The numbers are in the ratio 4 : 5. Find the sum of numbers. 

Detailed Solution for Test: LCM & GCD - 3 - Question 8

Let the numbers be 4x and 5x.
Then, their L.C.M. = 20x. 
20x = 60 or x = 3.
The numbers are 12 and 15.
Hence, required sum = (12 + 15) = 27.

Test: LCM & GCD - 3 - Question 9

The L.C.M. Of 2, 2.7 and 0.09 is: 

Detailed Solution for Test: LCM & GCD - 3 - Question 9

Given numbers are 2.00, 2.70 and 0.09.
L.C.M. of 200, 270 and 9 is 5400.
L.C.M. Of given numbers = 54.00 = 54

Test: LCM & GCD - 3 - Question 10

Find the least number which should be added to 2430 so that the sum is exactly divisible by 5, 4 and 2 

Detailed Solution for Test: LCM & GCD - 3 - Question 10

L.C.M of 5, 4, and 2 = 20. On dividing 2430 by 20, the remainder is 10.
Therefore, number to be added = (20 - 10) = 10

Test: LCM & GCD - 3 - Question 11

The ratio of two numbers is 4 : 5 and their H.C.F is 4. Find their L.C.M. 

Detailed Solution for Test: LCM & GCD - 3 - Question 11

Let the numbers be 4x and 5x.

H.C.F = x. So, x=4.
So, the numbers are 16 and 20
L.C.M of 16 and 20 = 80.

Test: LCM & GCD - 3 - Question 12

A man decides to pave with square tiles his hall which is 4.8 metres long and 5.38 metres wide. Find the largest size of the tile that he could use.

Detailed Solution for Test: LCM & GCD - 3 - Question 12

The largest size of the tile is H.C.F. of 480 cm and 538 cm is 2 cm.

Test: LCM & GCD - 3 - Question 13

3 bells beep at an interval of 12, 20, and 35 minutes. If they beep together at 10 a.m., then they will again beep together at:

Detailed Solution for Test: LCM & GCD - 3 - Question 13

The L.C.M. of 12, 20 and 35 is 420. Hence, all 3 bells beep together after 420 minutes = 7 hours
Hence, the 3 bells will beep together 7 hours after 10 a.m. i.e. at 5 p.m.

Test: LCM & GCD - 3 - Question 14

The least number which is a multiple of 11 and when divided by 3, 5 and 9 leaves 2 as remainder:

Detailed Solution for Test: LCM & GCD - 3 - Question 14

The L.C.M. of 3, 5 and 9 is 45.
Hence, the number is of the form (45a + 2).
The least value of ‘a’ for which (45a + 2) is multiple of 11 is 9.
Therefore, the number is 407.

Test: LCM & GCD - 3 - Question 15

LCM of two numbers is 495. HCF of these numbers is 5. If the sum of the numbers is 100, find out the difference between the two numbers.

Detailed Solution for Test: LCM & GCD - 3 - Question 15

It is given that sum of two numbers is 100. Let the two numbers be x and 100 – x and HCF is 5 and LCM is 495

=> We need to apply the formula: HCF x LCM = Product of two numbers

Which gives x(100 – x) = 495 x 5

Solving the equation we get a quadratic which looks like this:

Therefore, Two numbers are 55 and 45

115 videos|106 docs|113 tests
Information about Test: LCM & GCD - 3 Page
In this test you can find the Exam questions for Test: LCM & GCD - 3 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: LCM & GCD - 3, EduRev gives you an ample number of Online tests for practice

Top Courses for GMAT

115 videos|106 docs|113 tests
Download as PDF

Top Courses for GMAT