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Test: Laws of Exponents - Class 9 MCQ


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20 Questions MCQ Test Mathematics (Maths) Class 9 - Test: Laws of Exponents

Test: Laws of Exponents for Class 9 2025 is part of Mathematics (Maths) Class 9 preparation. The Test: Laws of Exponents questions and answers have been prepared according to the Class 9 exam syllabus.The Test: Laws of Exponents MCQs are made for Class 9 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Laws of Exponents below.
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Test: Laws of Exponents - Question 1

Which of the following is the value of (4/5)-9 / (4/5)-9?

Detailed Solution for Test: Laws of Exponents - Question 1

(4/5)-9 ÷ (4/5)-9 simplifies as follows:
Using the division rule of exponents, subtract the exponents:
(4/5)-9 ÷ (4/5)-9 = (4/5)-9 - (-9) = (4/5)0
Any non-zero number raised to the power of 0 is 1:
(4/5)0 = 1
The answer is C: 1.

Test: Laws of Exponents - Question 2

 Find (64)-3/2

Detailed Solution for Test: Laws of Exponents - Question 2

(64)-3/2 = ( 8 )2 x - 3/2 =  (8)-3  

= 1 / (8)3 = 1/ 512 

So option B is correct answer . 

Test: Laws of Exponents - Question 3

3x-3 x  5x-4 = 45
What is the value of x?

Detailed Solution for Test: Laws of Exponents - Question 3

Given,
first factorise 45 = 32 x 51
[3(x-3)] 5(x-4) = 45 = 32 (51)
On comparing both sides we get,
x-3 = 2 and x-4 = 1
By solving we get
=> x = 5
Hence, option A is the correct answer.

Test: Laws of Exponents - Question 4

Which of the following  (100 - 990) x 100?

Detailed Solution for Test: Laws of Exponents - Question 4

To solve this problem, we need to evaluate the expression (100 - 990) x 100. Let's break it down step by step:
Step 1: Evaluate 990: Any number raised to the power of 0 is equal to 1. So, 990 = 1.
Step 2: Substitute the value of 990 into the expression: (100 - 1) x 100 = 99 x 100.
Step 3: Multiply 99 and 100: 99 x 100 = 9900.
Therefore, the value of the expression (100 - 990) x 100 is 9900.
Hence, the correct answer is C: 9900.

Test: Laws of Exponents - Question 5

Simplified value of (25)1/3 x (5)1/3 is:

Detailed Solution for Test: Laws of Exponents - Question 5

(25)1/3=(52)1/3=(5)2/3
52/3x51/3=53/3  = 52/3+1/3   = 51   [ax a = a(m+n)  ]
so answer is 5

Test: Laws of Exponents - Question 6

163/2 is equal to ———-

Detailed Solution for Test: Laws of Exponents - Question 6

Interpret the exponent:

  • The fractional exponent 3/2 means:
    16(3/2) = (16(1/2))3
    Here, 16(1/2) is the square root of 16.

Calculate the square root:
16(1/2) = √16 = 4

Raise the result to the power of 3:
(16(1/2))3 = 43 = 64

Test: Laws of Exponents - Question 7

Simplify: (13(1/5)) / (13(1/3))

Detailed Solution for Test: Laws of Exponents - Question 7

Using the quotient rule for exponents, (am / an) = a(m - n):

131/5 / 131/3 = 13(1/5 - 1/3)
= 131/5 - 1/3
= 13 3 - 5 / 15
= 13-2/15

Test: Laws of Exponents - Question 8

(16(3/2)) ÷ (16(1/2)) = ?

Detailed Solution for Test: Laws of Exponents - Question 8

Correct answer is D. 16.
= (16(3/2)) ÷ (16(1/2)) = ?
= (16)3/2  -  1/2
= (16)
= 16.

Test: Laws of Exponents - Question 9

What is 8(- 5/3) equal to?

Detailed Solution for Test: Laws of Exponents - Question 9

Recognize that 8 can be expressed as 23, as 2 x 2 x 2 = 8.
Rewrite 8-5/3 as (23)-5/3
Apply the power of a power rule, which states that (am)n = amn. In this case,
multiply the exponents: 3 x -5/3
Simplify the expression.
Let's go through the steps:
(23)-5/3
(2)-5
Now, 2-5 means taking the reciprocal of 25 (since a negative exponent indicates
reciprocal), so: 
2-5 = 1/  25
= 1/32  [ 2= 2x2x2x2x2 = 32 ]

Test: Laws of Exponents - Question 10

Which of the following is equal to (- 3/4)-3

Detailed Solution for Test: Laws of Exponents - Question 10

According to the exponent rules, (-3/4)-3 is equal to (-4/3)3, which corresponds to option 1.

Test: Laws of Exponents - Question 11

Simplified value of (16(-1/4) × (4√16) is:

Detailed Solution for Test: Laws of Exponents - Question 11

(16)-1/4 × (4√16).

The fourth root of 16 is 2, so (16)-1/4 simplifies to 1/2, and √16 is 4, hence 4√16 simplifies to 16.

Thus:

(16)-1/4 × (4√16) = 1/2 × 16 = 8.

Test: Laws of Exponents - Question 12

Which of the following statement is true

Detailed Solution for Test: Laws of Exponents - Question 12
Explanation:
To find the value of x0, we need to understand the concept of exponentiation.
- When a number is raised to the power of 0, it always equals 1. This is true for any number except 0.
Therefore, the correct statement is:
x0 = 1
The other statements are incorrect:
- A: x0 = 1/x - This is not true. x0 is always equal to 1, not 1/x.
- B: x0 = x - This is not true. x0 is always equal to 1, not x.
- C: x0 = 0 - This is not true. x0 is always equal to 1, not 0.
Therefore, the correct answer is D: x0 = 1.
Test: Laws of Exponents - Question 13

The value of (20 × 70) / 50 is:

Detailed Solution for Test: Laws of Exponents - Question 13

Anything to the power 0 is always 1. 
The answer is 1 because of a0= 1.
So 1×1/1 = 1

Test: Laws of Exponents - Question 14

(256)3/4 = ?

Detailed Solution for Test: Laws of Exponents - Question 14

2563/4
= (4√256)3
= (4√(4 × 4 × 4 × 4))3
= (4)3
= 64

Test: Laws of Exponents - Question 15

What is the value of (-1)-1?

Detailed Solution for Test: Laws of Exponents - Question 15

(-1)-1 =  - 1 / 1 = -1

Test: Laws of Exponents - Question 16

811/2 is equal to ——

Detailed Solution for Test: Laws of Exponents - Question 16

811/2  can be written as (9) 2x1/2 =  9 

Test: Laws of Exponents - Question 17

The value of 491/2 is equal to———

Detailed Solution for Test: Laws of Exponents - Question 17

491/2 can be written as  (7)2x1/2 = 7

Test: Laws of Exponents - Question 18

125-1/3 × 25-1/2 = ?

Detailed Solution for Test: Laws of Exponents - Question 18

 ( 5 ) 3 x -1/3   x  ( 5 ) 2  x -1/2 

  ( 5 ) -1  x   ( 5 )  -1

   1 / 25 

Test: Laws of Exponents - Question 19

 (am)is equal to

Detailed Solution for Test: Laws of Exponents - Question 19

- The expression  (am)n involves exponentiation rules.
- The rule for powers of a power is (am)n = amn
- This means you multiply the exponents when raising a power to another power.

Test: Laws of Exponents - Question 20

3. Very small numbers can be expressed in standard form using __________ exponents.

Detailed Solution for Test: Laws of Exponents - Question 20

- Very small numbers in standard form are expressed using negative exponents.
- Standard form is a way of writing numbers as a product of a number between 1 and 10, and a power of 10.
- For small numbers, the power of 10 is negative, indicating division by a power of 10.
- Example: 0.001 is written as 10-3
- Negative exponents simplify representing very small values efficiently.

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