Test: Linear Algebra - 1

# Test: Linear Algebra - 1

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## 20 Questions MCQ Test Topic-wise Tests & Solved Examples for IIT JAM Mathematics | Test: Linear Algebra - 1

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Test: Linear Algebra - 1 - Question 1

### Define T(v) = Av, where A = . Then T(v):

Detailed Solution for Test: Linear Algebra - 1 - Question 1

We are given that
T(v) = Av
where A = We need to define T(v)
Let v = ,  then T(v) = Av = Which reflects v about the x2-axis.

Test: Linear Algebra - 1 - Question 2

### If the linear transformation T(v) = Av rotates the vectors (-1, 0) and (0,1), x radians clockwise, then:

Detailed Solution for Test: Linear Algebra - 1 - Question 2

We are given that the linear transformation T(v) = Av rotates the vectors (-1,0) and (0,1), π radians clockwise.
We need to find the matrix A.
We know that if a vector (a, b) is rotated through an angle a under T. Then  Therefore, the matrix of T is
A = Test: Linear Algebra - 1 - Question 3

### If the linear transformation T(v) = Av rotates the vectors v1 = (-1, 0) and v2 = (0, 1) clockwise π radians, the resulting vectors are:

Detailed Solution for Test: Linear Algebra - 1 - Question 3

We are give that the linear transformation T(v) = Av rotates the vectors v1 = (-1,0) and v2 = (0,1) clockwise π radians. We need to find the image of v= (-1, 0) and v2 = (0,1) under T
We know that if a vector (a, b) is rotated through an angle α under linear transformation T, then Here v1 = (-1, 0) and a = π
Therefore,v2 = (0,1) = (1,0)
and T(v2) = T(0, 1) = (0,-1)

Test: Linear Algebra - 1 - Question 4

If the linear transformation T(v) = Av rotates the vectors v1 = (-1, 0) and v2 = (0, 1) clockwise π/2 radians, the resulting vectors are:

Detailed Solution for Test: Linear Algebra - 1 - Question 4

We are given that the linear transformation T(v) = Av rotates the vector v1 = (-1, 0) and v2 = (0,1) clockwise π/2radians.
We know that if a vector (a, b) is rotated through an angle a clockwise direction under linear transformation T.Then Here, v= (-1 , 0) and a = π/2 radians
Therefore, T(v1) = T(-1, 0)
= = (0,1)
Therefore, T(-1, 0) = (0,1)
Similarly, for v2 = (0, 1) and α = π/2,
and T(v2) = T(0 ,1) = (1,0)
Therefore, T(0,1) = (1 ,0 ).

Test: Linear Algebra - 1 - Question 5

If the linear transformation T(v) = Av rotates the vectors (-1, 0) and (0, 1) clockwise π/2 radians then:

Detailed Solution for Test: Linear Algebra - 1 - Question 5

We are given that the linear transformation T(v) = Av rotates the vectors (-1, 0) and (0, 1) clockwise π/2 radians. We need to find the matrix A.
We know that if a vector (a, b) is rotated through an angle a clockwise under T. Then Here, (a, b) = (-1, 0)  and a = π/2
Therefore, T (-1, 0) = (0, 1) = 0(-1, 0) + 1(0, 1)
and (a, b) = (0,1), α = π/2 = (1, 0) = - 1(-1, 0) + 0(0, 1)
Therefore, the matrix of T is A = Test: Linear Algebra - 1 - Question 6

If A = satisfies the matrix equation A2 - kA + 2I = 0, then what is the value of k?

Detailed Solution for Test: Linear Algebra - 1 - Question 6

We need to find the value o f k where the matrix
A = satisfies the equations A2 - kA + 2I = 0.
But A = So, Putting these values in the equation
A2 - kA + 2I= 0, we get or or 1 - 3k + 2 = 0 => k = 1

Test: Linear Algebra - 1 - Question 7

Under which one of the following condition does the system of equations have a unique solution?

Detailed Solution for Test: Linear Algebra - 1 - Question 7

We are given that the system of equations Reduce this system of equations to echelon form, using the operations "R2 ----> + R2 - 2R1" and R3 ---> R3 - R1.
These operations yields: Also we have, this system has a unique solution so a - 8 ≠ 0
or a ≠ 8

Test: Linear Algebra - 1 - Question 8

What is the determinant of the following matrix? Detailed Solution for Test: Linear Algebra - 1 - Question 8

We need to find the determinant of the given matrix, determinant of A = or det (A) = det (A) = 1/n!

Test: Linear Algebra - 1 - Question 9

If the system of equations
x - 2y - 3z = 1, (p + 2)z = 3, (2p + 1)y + z = 2 is inconsistent, then what is the value of P?

Detailed Solution for Test: Linear Algebra - 1 - Question 9

We are given that the system of equations,
x - 2y - 3z = l, (p + 2)z =3, (2p + l) y + z = 2 is inconsistent. Then we need to find the value of p.
The augmented matrix of this system of equations is, The solution of this matrix is inconsistent if
p + 2 = 0
or p = -2

Test: Linear Algebra - 1 - Question 10

If x, y, z are in AP with common difference d and the rank of the matrix is 2, then the value of d and k are

Detailed Solution for Test: Linear Algebra - 1 - Question 10

We are given that x, y, z are in A.P. with common difference d i. e.,
or and the rank of is z.
We need to find the values of d and k. The given matrix can be written as, Applying R2 -> R2, R1 and R--> R-R2 Applying, R3 ---> R3 - R2,  Test: Linear Algebra - 1 - Question 11

The linear transformation T(x, y) = can be written as:

Detailed Solution for Test: Linear Algebra - 1 - Question 11

We have or equivalently
T(x,y) = (x,y)

Test: Linear Algebra - 1 - Question 12

The linear transformation T(x, y) = (x + 2y, x - 2y), can be written as a matrix transformation T(x, y) where:

Detailed Solution for Test: Linear Algebra - 1 - Question 12

We are given that a linear transformation defined by
T(x, y) = (x + 2y, x - 2y)
Let B ={(1, 0), (0, 1)} be a standard basis then
T(1,0) = (1,1) = 1 (1 ,0)+ 1(0,1)
T(0, 1) = (2 ,-2) = 2(1,0) - 2(0 ,1)
Therefore, the matrix of T with respect to the basis B is Test: Linear Algebra - 1 - Question 13

Is the transformation T(x, y, z) = (x, y, 0) linear?

Detailed Solution for Test: Linear Algebra - 1 - Question 13

We are given that a transformation defined by
T(x,y,z) = (x,y, 0)
Let α and β be scalars and (x1, y1, z1) and (x2, y2, z2) be two vectors. Then
T[α(x1, y1, z1) + β(x1, y2, z2)] or equivalently Hence, T is linear.

Test: Linear Algebra - 1 - Question 14

What is the range of T(v) = Av where A = ?

Detailed Solution for Test: Linear Algebra - 1 - Question 14

We are given that a linear transformation T defined by
T(v) = Av
where Let Then Let v1, v2, v3 ∈ ker T. Then Using the definition of T, we get or equivalently or equivalently
v1 = v2 = v3 = - v1
Therefore,ker T=  {(v1, v1, - v1): v ∈ R}.
Therefore, dim ker T= 1
Using Rank-Nullity theorem|
Rank T= 3 - dim ker T
= 3 - 1 = 2
Therefore, the range of T is a plane in R3

Test: Linear Algebra - 1 - Question 15

Suppose T1: V ---> U and T2 : U —> W be two linear transformation, Then:

Test: Linear Algebra - 1 - Question 16

Which one of the following is true?

Detailed Solution for Test: Linear Algebra - 1 - Question 16

We need to find the dim Horn (R3, R4).
Since dim R3 = 3 and dim R4 = 4
Therefore,dim Horn (R3, R4)
= 3 x 4 = 12
Let U and V be n and m dimensional vector space.
Then dim Hom (U, V) = nm

Test: Linear Algebra - 1 - Question 17

If C is a non-singular matrix and B then

Detailed Solution for Test: Linear Algebra - 1 - Question 17

We are given that C is a non-singular matrix and
B = or B is similar to The eigen values of are all zeroes.

Hence, Bk = 0
For       k = 3
B3 = 0

Test: Linear Algebra - 1 - Question 18

If X = ,  the rank of XTX, where XT denotes the transpose of X, is

Detailed Solution for Test: Linear Algebra - 1 - Question 18

We are given that the matrix
X= We need to find the rank of XTX. The transpose of X,
XT= Now,  Rank (XTX) = 3

Test: Linear Algebra - 1 - Question 19

The system of equation kx +y + z = 1,x + ky + z = k and x + y + kz = k3 does not have a solution, if k is equal to

Detailed Solution for Test: Linear Algebra - 1 - Question 19

We are given that the system of equation does not have a solution. We need to find the value of k. The given linear system of equation can be written as, This system of equation has no. solution if rank (A) # rank (aug A) the augmented matrix is, This augmented matrix has no. solutions if k = -2.

Test: Linear Algebra - 1 - Question 20

We are given that the system of equation has

Detailed Solution for Test: Linear Algebra - 1 - Question 20

We are given that the system of equation It may be written as Here, the rank of the given coefficient matrix ≤ 3 and number of unknowns are four.
Hence, rank < no. of unknowns this system of equations has infinitely many solutions.

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