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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - JEE MCQ


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7 Questions MCQ Test 35 Years Chapter wise Previous Year Solved Papers for JEE - Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced

Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced for JEE 2024 is part of 35 Years Chapter wise Previous Year Solved Papers for JEE preparation. The Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced questions and answers have been prepared according to the JEE exam syllabus.The Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced below.
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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 1
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Which one of the following has the smallest heat of hydrogenation per mole? (1993)

Detailed Solution for Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 1

TIPS/Formulae : Heat of hydrogenation is related to stability of molecules; higher the stability, lower is the heat of hydrogenation.
Butadiene, CH2 = CHCH = CH2 has two double bonds so its heat of hydrogenation will be more than the other three.
Alkenes follow the following order of stability

Thus here stability order of the given monoalkenes is

NOTE : The trans-2-butene is more stable than the cis-because in the cis-isomer the two bulky groups are crowded together with the result it has more van der Waal’s strain than the trans-isomer.

 

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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 2
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Toluene, when treated with Br2/Fe, gives p-bromotoluene as the major product because CH3 group (1999 - 3 Marks)

Detailed Solution for Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 2

Hyperconjugation in toluene activates the benzene ring for electrophilic substitution.

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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 3
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N(isomeric products) ; C5H11Cl

(isomeric products) Identify N and M (2006 - 5M,)

Identify N and M (2006 - 5M, –1)

Detailed Solution for Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 3

So, the value of N will be 1 + 2 + 2 + 1 = 6.
Since enantiomers have nearly same physical properties, II and III as well as IV and V can’t be separated, hence the number of isomers (M) will be 1 + 1 + 1 + 1 = 4.

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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 4
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Among P, Q, R and S, the aromatic compound(s) is/are (JEE Advanced 2013-I)
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Note : P has 2 p electrons, while Q, R & S have 6 p electrons each. Hence all the 4 are aromatic.

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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 5
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In the following reaction, the major product is (JEE Adv. 2015)
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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 6
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Compound(s) that on hydrogenation produce(s) optically inactive compound(s) is (are) (JEE Adv. 2015)
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Test: MCQs (One or More Correct Option): Hydrocarbons | JEE Advanced - Question 7
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Among th e followin g, r eaction(s) wh ich gives(give) tert-butyl benzene as the major product is(are) (JEE Adv. 2016)
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