Test: Mealy Machine - Computer Science Engineering (CSE) MCQ

The automaton may be allowed to change its state without reading the input symbol using epsilon but this does not mean that epsilon has become an input symbol. On the contrary, one assumes that the symbol epsilon does not belong to any alphabet.

An e-NFA consist of 5 tuples: A=(Q, S, d, q0. F)
Note: e is never a member of S.

e-NFA do come up with a convenient feature but nothing new.They do not extend the class of languages that can be represented.

Design a NFA for the language:
L: {an | n is even or divisible by 3}

The language can be represented using a Non-deterministic Finite Automaton (NFA) with the following characteristics:

• The NFA should accept strings where the number of as is either even or divisible by 3.
• This can be achieved by creating states that reflect the conditions of being even or divisible by 3.

To simulate this NFA, the following methods can be employed:

• e-NFA: This method allows the use of epsilon transitions, enabling the automaton to transition between states without consuming input.
• Power Construction Method: This method converts the NFA into a Deterministic Finite Automaton (DFA) by creating a state for every possible subset of NFA states.
• Both methods are valid and can be used to simulate the NFA.

Therefore, the correct answer is both methods, denoted as C

The epsilon closure of the set q is the set that contains q, together with all the states which can be reached starting at q by following only epsilon transitions.

The epsilon closure set of f2 consist of the elements:{f2, f3}. Thus the count of the element in the closure set is 2.

The given are the steps followed while eliminating epsilon transitions from a NFA or converting an e-NFA to just NFA.

Yes, the language is preserved during the dteps of construction: L(N)=L(N1)=L(N2)=L(3).