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Test: Mesh & Nodal Analysis


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20 Questions MCQ Test Basic Electrical Technology | Test: Mesh & Nodal Analysis

Test: Mesh & Nodal Analysis for Electrical Engineering (EE) 2022 is part of Basic Electrical Technology preparation. The Test: Mesh & Nodal Analysis questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Mesh & Nodal Analysis MCQs are made for Electrical Engineering (EE) 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mesh & Nodal Analysis below.
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Test: Mesh & Nodal Analysis - Question 1

Find the value of the currents I1, I2 and I3 flowing clockwise in the first, second and third mesh respectively.

Detailed Solution for Test: Mesh & Nodal Analysis - Question 1

The three mesh equations are:
-3I1+2I2-5=0
2I1-9I2+4I3=0
4I2-9I3+10=0
Solving the equations, we get I1= 1.54A, I2=-0.189 and I3= -1.195A.

Test: Mesh & Nodal Analysis - Question 2

Find the value of the currents I1 and I2 flowing clockwise in the first and second mesh respectively.

Detailed Solution for Test: Mesh & Nodal Analysis - Question 2

The two mesh equations are:
5I1-3I2=10
-3I1+7I2=-15
Solving the equations simultaneously, we get I1=0.96A and I2=-1.73A.

Test: Mesh & Nodal Analysis - Question 3

Find the value of V if the current in the 3 ohm resistor=0.

Detailed Solution for Test: Mesh & Nodal Analysis - Question 3

Taking the mesh currents in the three meshes as I1, I2 and I3, the mesh equations are:
3I1+0I2+0V=5
-2I1-4I2+0V=0
0I1+9I2+V=0
Solving these equations simultaneously and taking the value of I2=0, we get V=7.5V.

Test: Mesh & Nodal Analysis - Question 4

Find the value of V1 if the current through the 1 ohm resistor=0A.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 4

Taking I1, I2 and I3 as the currents in the three meshes and taking I3=0 since it is the current across the 1 ohm resistor, the three mesh equations are:
15I1-5I2=V1
-5I1+10I2+0V1=0
0I1-3I2+0V1=10
Solving these equations simultaneously we get V1= 83.33V.

Test: Mesh & Nodal Analysis - Question 5

Calculate the mesh currents I1 and I2 flowing in the first and second meshes respectively.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 5

In this circuit, we have a super mesh present. Let I1 and I2 be the currents in loops in clockwise direction. The two mesh equations are:
I2-I1=3
-5I1-3I2=5
Solving these equations simultaneously, we get I1= -1.75A and I2= 1.25A.
Since no specific direction given so currents in loop 1 and loop 2 are 1.75A and 1.25A respectively.

Test: Mesh & Nodal Analysis - Question 6

 I1 is the current flowing in the first mesh. I2 is the current flowing in the second mesh and I3 is the current flowing in the top mesh. If all three currents are flowing in the clockwise direction, find the value of I1, I2 and I3.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 6

Explanation: The two meshes which contain the 3A current is a super mesh. The three mesh equations therefore are:
I3=2A
I2-I1=3
-2I1-I2=-26
Solving these equations simultaneously we get:
I1=7.67A, I2=10.67A and I3=2A.

Test: Mesh & Nodal Analysis - Question 7

Calculate the mesh currents.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 7

The two meshes which contain the 3A source, act as a supper mesh. The mesh equations are:
I1-I2=3
-11I1-4I2+14I3=-10
10I1+4I2-28I3=0
Solving these equations simultaneously, we get the three currents as 2A, 1A and 0.57A.

Test: Mesh & Nodal Analysis - Question 8

Mesh analysis employs the method of ___________

Detailed Solution for Test: Mesh & Nodal Analysis - Question 8

KVL employs mesh analysis to find the different mesh currents by finding the IR products in each mesh.

Test: Mesh & Nodal Analysis - Question 9

Mesh analysis is generally used to determine _________

Detailed Solution for Test: Mesh & Nodal Analysis - Question 9

Mesh analysis uses Kirchhoff’s Voltage Law to find all the mesh currents. Hence it is a method used to determine current.

Test: Mesh & Nodal Analysis - Question 10

Mesh analysis can be used for __________

Detailed Solution for Test: Mesh & Nodal Analysis - Question 10

If the circuit is not planar, the meshes are not clearly defined. In planar circuits, it is easy to draw the meshes hence the meshes are clearly defined.

Test: Mesh & Nodal Analysis - Question 11

Find the value of the node voltage V. ​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 11

The node equation is:
-2+8+V/10=0 => 6 + v/10 = 0 => v = 10*6=>60v
Solving this equation, we get V=60V.

Test: Mesh & Nodal Analysis - Question 12

Calculate the node voltages V1 and V2.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 12

The nodal equations are:
2V1-V2=-4
-4V1+5V2=88
Solving these equations simultaneously, we get V1=11.33V and V2=26.67V.

Test: Mesh & Nodal Analysis - Question 13

Find the node voltage V.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 13

The nodal equation is:
(V-10)/2+(V-7)/3+V/1=0
Solving for V, we get V=4V.

Test: Mesh & Nodal Analysis - Question 14

Calculate the node voltages.
​ 

Detailed Solution for Test: Mesh & Nodal Analysis - Question 14

The nodal equations, considering V1, V2 and V3 as the first, second and third node respectively, are:
-8+(V1-V2)/3-3+(V1-V3)/4=0
3+V2+(V2-V3)/7+(V2-V1)/3=0
2.5+(V3-V2)/7+(V3-V1)/4+V3/5=0
Solving the equations simultaneously, we get V1=24.32V, V2=4.09V and V3=7.04V.

Test: Mesh & Nodal Analysis - Question 15

Find the value of V1 and V2.​

Detailed Solution for Test: Mesh & Nodal Analysis - Question 15

The nodal equations are:
0.3V1-0.2V2=16
-V1+3V2=-15
Solving these equations simultaneously, we get V1=64.28V and V2=16.42V.

Test: Mesh & Nodal Analysis - Question 16

Nodal analysis is generally used to determine_______

Detailed Solution for Test: Mesh & Nodal Analysis - Question 16

Nodal analysis uses Kirchhoff’s Current Law to find all the node voltages. Hence it is a method used to determine voltage.

Test: Mesh & Nodal Analysis - Question 17

KCL is associated with_________

Detailed Solution for Test: Mesh & Nodal Analysis - Question 17

KCL employs nodal analysis to find the different node voltages by finding the value if current in each branch.

Test: Mesh & Nodal Analysis - Question 18

If there are 10 nodes in a circuit, how many equations do we get?

Detailed Solution for Test: Mesh & Nodal Analysis - Question 18

The number of equations we get is always one less than the number of nodes in the circuit, hence for 10 nodes we get 9 equations.

Test: Mesh & Nodal Analysis - Question 19

Nodal analysis can be applied for________

Detailed Solution for Test: Mesh & Nodal Analysis - Question 19

Nodal analysis can be applied for both planar and non-planar networks since each node, whether it is planar or non-planar, can be assigned a voltage.

Test: Mesh & Nodal Analysis - Question 20

How many nodes are taken as reference nodes in nodal analysis?

Detailed Solution for Test: Mesh & Nodal Analysis - Question 20

In nodal analysis one node is treated as the reference node and the voltage at that point is taken as 0.

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