Test: Network Elements - 1 - Electrical Engineering (EE) MCQ

# Test: Network Elements - 1 - Electrical Engineering (EE) MCQ

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## 10 Questions MCQ Test Network Theory (Electric Circuits) - Test: Network Elements - 1

Test: Network Elements - 1 for Electrical Engineering (EE) 2024 is part of Network Theory (Electric Circuits) preparation. The Test: Network Elements - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Network Elements - 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Network Elements - 1 below.
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Test: Network Elements - 1 - Question 1

### Find the energy (power) drawn by the circuit shown in the figure below.

Detailed Solution for Test: Network Elements - 1 - Question 1

Sign convention for Power delivered and absorbed:
When current is leaving the positive voltage terminal of the element or current is entering the negative voltage terminal of the element then the particular element is delivering power.
∴ P = +Vi

• When current is entering the positive voltage terminal of the element or current is leaving the negative voltage terminal of the element then the particular element is absorbing power.

∴ P = -Vi

• The power delivered to an element is denoted by the positive sign, whereas, power supplied by an element is denoted by the negative sign.
• In figure (i), when current enters through the positive terminal of the circuit, the power has a positive sign.
• In figure (ii) when the current leaves the positive terminal, the power has a negative sign

Calculation:
Given that,
V = 2 volts,
i = 3 A

In the above circuit, the current is leaving the positive voltage terminal of the element or the current is entering the negative voltage terminal of the element then the particular element is delivering power.
Thus, the power drawn by the circuit shown in the above figure can be calculated as
P = + Vi
=> P = +(2 × 3)
∴ P = + 6 W

Test: Network Elements - 1 - Question 2

### A varistor is a/an:

Detailed Solution for Test: Network Elements - 1 - Question 2

Linear and Non-linear Element:

• An element is said to be Linear if its V-I characteristics follow only one equation of the straight line or Ohm's law and pass through the origin.
• Resistor (R), inductor (L), and capacitor (C) elements are considered as a linear element.
• The characteristics of the linear element are shown below.

• An element is said to be Non-linear if its V-I characteristics not follow only one equation and not follow Ohm's law.
• Diode, BJT, JFET, SCR, varistor etc are considered as the non linear element.
• The characteristics of the non-linear element are shown below.

Test: Network Elements - 1 - Question 3

### Three resistors of 6 Ω are connected in parallel. So, what will be the equivalent resistance?

Detailed Solution for Test: Network Elements - 1 - Question 3

When resistances are connected in parallel, the equivalent resistance is given by

When resistances are connected in series, the equivalent resistance is given by

Calculation:
Given that R1 = R2 = R= 6 Ω and all are connected in parallel

​​​​​​​

Test: Network Elements - 1 - Question 4

Ohm’s law is applicable to

Detailed Solution for Test: Network Elements - 1 - Question 4

Ohm’s law: Ohm’s law states that at a constant temperature, the current through a conductor between two points is directly proportional to the voltage across the two points.
Voltage = Current × Resistance
V = I × R
V = voltage, I = current and R = resistance
The SI unit of resistance is ohms and is denoted by Ω.
It helps to calculate the power, efficiency, current, voltage, and resistance of an element of an electrical circuit.

Limitations of ohms law

• Ohm’s law is not applicable to unilateral networks. Unilateral networks allow the current to flow in one direction. Such types of networks consist of elements like a diode, transistor, etc.
• Ohm’s law is also not applicable to non – linear elements. Non-linear elements are those which do not have current exactly proportional to the applied voltage that means the resistance value of those elements’ changes for different values of voltage and current. An example of a non-linear element is thyristor.
• Ohm’s law is also not applicable to vacuum tubes.
Test: Network Elements - 1 - Question 5

If 5 A of electric current flows for a period of 3 minutes, what will be the amount of charge transferred?

Detailed Solution for Test: Network Elements - 1 - Question 5

Electric current: If the electric charge flows through a conductor, we say that there is an electric current in the conductor.
If Q charge flow through the conductor for ‘t’ seconds, then the current given by that conductor is

Q = I × t
I = current
t = times

Calculation:
Given I = 5 amp
t = 3 min = 180 sec
Q = I × t
Q = 5 × 180 = 900 C

Test: Network Elements - 1 - Question 6

Resistivity of a wire depends upon

Detailed Solution for Test: Network Elements - 1 - Question 6

The resistance (R) of a conducting wire depends upon the length of wire, cross-sectional of the wire, and its resistivity.

Resistance is directly proportional to the length of the conductor and Inversely proportional to the cross-sectional area.

Where l is the length of the conductor, a is the cross-sectional area of the conductor, ρ is resistivity.
Resistivity: The resistivity is the resistor depends upon the nature of the conductor and temperature.
∴ Material Resistivity is the same for given conducting material at a given temperature and does not depend upon dimensions of wire.

If a wire is stretched, its volume remains the same.

Test: Network Elements - 1 - Question 7

When capacitors are connected in series across DC voltage __________.

Detailed Solution for Test: Network Elements - 1 - Question 7

When capacitors are connected in series across DC voltage:

• The charge of each capacitor is the same and the same current flows through each capacitor in the given time.
• The voltage across each capacitor is dependent on the capacitor value.

When capacitors are connected in parallel across DC voltage:

• The charge of each capacitor is different and the current flows through each capacitor in the given time are also different and depend on the value of the capacitor.
• The voltage across each capacitor is the same.
Test: Network Elements - 1 - Question 8

The circuit whose properties are same in either direction is known as

Detailed Solution for Test: Network Elements - 1 - Question 8

Unilateral Circuits:

• Allows the current flow in one direction only
• Circuit properties changes by changing the direction of current or voltage
• Diode, transistors are the examples

Bilateral Circuits:

• Allows the current flow in both the directions
• Circuit properties will remain the same even by changing the direction of current or voltage
• Resistance, inductance and capacitance are the examples

Irreversible circuit:

• An irreversible circuit is a circuit whose inputs cannot be reconstructed from its outputs.

Reversible circuit:

• An reversible circuit is a circuit whose inputs can be reconstructed from its outputs.
Test: Network Elements - 1 - Question 9

When two identical resistors are connected in series across a battery, the power dissipated is 10 W. If these resistors are connected in parallel across the same battery, the total power dissipated will be

Detailed Solution for Test: Network Elements - 1 - Question 9

When two or more electrical devices of the same voltage are connected in parallel connection, their equivalent power rating can be calculated as
Peq = P1 + P2 + P3 + ……
When ‘n’ number of devices of the same voltage and same power rating (P) are connected in parallel connection, their equivalent power rating can be calculated as
Peq = nP
When two or more electrical devices of the same voltage rating are connected in a series connection, their equivalent power rating can be calculated as

When ‘n’ number of devices of the same voltage and same power rating (P) are connected in series connection, their equivalent power rating can be calculated as

Calculation:
When two identical bulbs are resistors are connected in series across a battery, their equivalent power (Peq) is ‘10 W’

∴ The power rating of each bulb, P = 20 W

When these two resistors are connected in parallel, then the equivalent power dissipated is
Peq = 2 × P
Peq = 40 W

Alternate Approach:
Series circuit:
In the series circuit, the voltage drop across each resistor = V/2
The total current through the circuit = V/2R amps.
The power dissipated by each resistor = V/2 × V/2R = V2/4R
Which must be equal to 5 Watts in order to make a total of 10 W.

Parallel circuit:
The voltage drop across each resistor = V.
The current through each resistor = V/R.
Multiplying these gives V2/R which is 4 times the series value of V2/4R
∴ The total power dissipated in parallel circuit = 4 × 10 = 40 W

Test: Network Elements - 1 - Question 10

Consider an element represented by the relationship between current i (t) and voltage v (t) as follows: v(t) = i2(t). This device is classified as:

Detailed Solution for Test: Network Elements - 1 - Question 10

Linear Element: An element is linear if :

• It follows additivity and superposition
• V-I graph is a straight line passing through the origin

Time variant Element: An element is said to be time-variant if the V-I graph varies with time.

Application:
Given V-I characteristic : v(t) = i2(t)
The characteristics can be drawn as,

It is not a straight line so non-linear
It is time-invariant because in any network analysis problem we take the circuit parameters V and I to be time-invariant.

Alternate Method:

Shifting the input, we get:
v1(t) = i12 (t - t1)
Now, shifting the output with the same amount, we can write:
v2 (t) = v1(t - t1) = i12 (t - t1) = v1 (t)

Since v1(t) = v2(t), the system is time invariant.

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