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Test: Network Equation (Mesh & Node) - 1


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10 Questions MCQ Test Network Theory (Electric Circuits) | Test: Network Equation (Mesh & Node) - 1

Test: Network Equation (Mesh & Node) - 1 for Electrical Engineering (EE) 2022 is part of Network Theory (Electric Circuits) preparation. The Test: Network Equation (Mesh & Node) - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Network Equation (Mesh & Node) - 1 MCQs are made for Electrical Engineering (EE) 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Network Equation (Mesh & Node) - 1 below.
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Test: Network Equation (Mesh & Node) - 1 - Question 1

v1 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 1

Applying the nodal analysis

Test: Network Equation (Mesh & Node) - 1 - Question 2

va = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 2

va = 2(3 + 1) + 3 (1) = 11 V

Test: Network Equation (Mesh & Node) - 1 - Question 3

v1 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 3

Test: Network Equation (Mesh & Node) - 1 - Question 4

va = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 4

Test: Network Equation (Mesh & Node) - 1 - Question 5

v2 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 5

Test: Network Equation (Mesh & Node) - 1 - Question 6

ib = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 6

Correct Answer :- B

Explanation : Current due to voltage source is:

I' = 10/(64+36) 

= 0.1A.

Current due to current source is:

I = 0.5A.

Current ib = I' + I 

= 0.5+ 0.1

= 0.6A

Test: Network Equation (Mesh & Node) - 1 - Question 7

Find the power supplied by the dependent voltage source in the circuit given below.

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 7

3loops = 3KVL equations. Solving them gives currents flowing in the circuit. I1 = 5A, I2 = -1.47A, I3 = 0.56A. Power supplied by dependent voltage source = 0.4V1 (I1 - I2).

Test: Network Equation (Mesh & Node) - 1 - Question 8

i1 = ?

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Test: Network Equation (Mesh & Node) - 1 - Question 9

i1 = ?

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Test: Network Equation (Mesh & Node) - 1 - Question 10

i1 = ?

Detailed Solution for Test: Network Equation (Mesh & Node) - 1 - Question 10


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