The length of each side of a rhombus is 10cm and one of its diagonal is of length 16cm. The Length of the other Diagonal is:
In a Quadrilateral ABCD, AB = BC and CD = DA, then the quadrilateral is a
ABCD is a Parallelogram in which AB = 9.5cm and its perimeter is 30cm. Find the length of each side of the Parallelogram?
We know that the perimeter of parallelogram ABCD can be written as
Perimeter = AB + BC + CD + DA
We know that opposite sides of parallelogram are equal
AB = CD and BC = DA
By substituting the values
Perimeter = 9.5 + BC + 9.5 + BC
It is given that perimeter = 30 cm
So we get
30 = 19 + 2BC
It can be written as
2BC = 30 – 19
By subtraction
2BC = 11
By division we get
BC = 5.5 cm
Therefore, AB = 9.5 cm, BC = 5.5 cm, CD = 9.5 cm and DA = 5.5 cm.
The angle between two altitudes of a Parallelogram through the vertex of an obtuse angle of the Parallelogram of 60∘. Find the angles of the Parallelogram
If an angle of a parallelogram is two-third of its adjacent angle, then find the smallest angle of the parallelogram.
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If ABCD is a Parallelogram with 2 Adjacent angles ∠A =∠B, then the parallelogram is a
Given a triangular prism, then what can we conclude about the lateral faces?
If angles A, B, C and D of the quadrilateral ABCD, taken in order, are in the ratio 3:7:6:4, then ABCD is
Given, ratio of angles of quadrilateral ABCD is 3 : 7 : 6 : 4.
Let angles of quadrilateral ABCD be 3x, 7x, 6x and 4x, respectively. We know that, sum of all angles of a quadrilateral is 360°.
3x + 7x + 6x + 4x = 360°
=> 20x = 360°
=> x=360°/20° = 18°
ABCD is a Trapezium in which AB∥DC and ∠A = ∠B = 45∘. Find angles C and D of the Trapezium
Angles of a quadrilateral are in the ratio 3 : 6 : 8: 13. The largest angle is :
3p + 6p + 8p + 13p = 30p = 360° ⇒ p
= 12° Largest angle is 13p = 13 × 12°
= 156°
If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is:
Consecutive angles of a Parallelogram are
The angles of a quadrilateral are in the ratio 4: 5: 10: 11. The angles are
Let x be the common angle among all the four angles of a quadrilateral.
As per angle sum property, we know:
4x+5x+10x+11x = 360°
30x = 360°
x = 12°
Hence, angles are
4x = 4 (12) = 48°
5x = 5 (12) = 60°
10x = 10 (12) = 120°
11x = 11 (12) = 132°
One Angle of a quadrilateral is of 108∘ and the remaining three angles are equal. Find each of the three equal angles.
ABCD is a Rectangle. Find the values of x and y?
AB =30 DA= 14 DC= x+y CB=x-y
ABCD Is A Rectangle, In Which Pair Of Opposite Sides are Equal
So, AB = CD
AD = BC
30 = x + y
14 = x - y
By Solving The Equations
x = 22
y = 8
If area of a Parallelogram with sides ‘a’ and ‘b’ is A and that of a rectangle with sides ‘a’ and ‘b’ is B, then
A diagonal of a Rectangle is inclines to one side of the rectangle at an angle of 25∘. The Acute Angle between the diagonals is :
Diagonals of a Parallelogram ABCD intersect at O. If ∠BOC = 90∘, ∠BDC = 50∘ then ∠OAB is
Angles of a quadrilateral are in the ratio 3 : 4 : 4 : 7. Find all the angles of the quadrilateral.
In Triangle ABC which is right angled at B. Given that AB = 9cm, AC = 15cm and D, E are the mid-points of the sides AB and AC res. Find the length of BC?
The Parallel sides of a trapezium are ‘a’ and ‘b’ res. The line joining the mid-points of its non-parallel sides will be
If a diagonal AC and BD of a quadrilateral ABCD bisect each other, then ABCD is a
Which of the following is not true for the Parallelogram?
The angles of the quadrilateral are in the ratios 3 : 5 : 9 : 13. Find all the angles of the Quadrilateral
The length of each side of a rhombus is 10cm and one of its diagonal is of length 16cm. The Length of the other Diagonal is:
Use pythagoras theorem in right triangle,
102 -[16/2]2 = 100 -64 = 36 = [6]2 ; hence the other diagonal = 6x2 = 12cm
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