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Test: Quantitative Aptitude- 3 - GMAT MCQ


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21 Questions MCQ Test Quantitative for GMAT - Test: Quantitative Aptitude- 3

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Test: Quantitative Aptitude- 3 - Question 1

Concentrated orange juice comes inside a cylinder tube with a radius of 2.5 inches and a height of 15 inches. The tubes are packed into wooden boxes, each with dimensions of 11 inches by 10 inches by 31 inches. How many tubes of concentrated orange juice, at the most, can fit into 3 wooden boxes?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 1

The best answer is A.

You want to waste as little amount of space as possible, therefore make the height of the box 11 and fit 4 boxes at the bottom so you lose only 1 inch of margin at the top and on one of the sides.

You can see that 8 tubes can fit into one box thus 24 tubes fit into 3 boxes.

Test: Quantitative Aptitude- 3 - Question 2

A certain car’s price decreased by 2.5% (from the original price) each year from 1996 to 2002, during that time the owner of the car invested in a new carburetor and a new audio system for the car, which increased her price by $1,500. If the price of the car in 1996 was $22,000, what is the car’s price in 2002?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 2

The best answer is C.

The price of the car decreased by 2.5% every year on a course of 6 years. That means that the price of the car in 2002 is 15% lower than the original + $1500 of new investments.
The new price is ($22,000 x 0.85 = 18,700 + 1500 = $20,200).

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Test: Quantitative Aptitude- 3 - Question 3

The average price of an antique car increases over the years. If from 1990 to 1996, the price of the car increased by 13% and from 1996 to 2001 it increased by 20%, what is the price of the car in 2001 if the price in 1990 was $11,500?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 3

The best answer is A.
The price in 1990 was 11,500. In 1996 the price is (11,500 x 1.13 = 12,995).
The price we are looking for, in 2002, is (12,995 x 1.2 = $15,594).

Test: Quantitative Aptitude- 3 - Question 4

The apartment on King-Williams street is an asset that it’s value is tramping about.
From the year 1973 to 1983 it’s value decreased by 16% and from 1983 to 1993 it’s value increased by 16%. What is the value of the asset in 1993 if in 1973 it was worth $40,000?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 4

The best answer is C.

Be careful, the value of the asset didn’t stay the same after the two changes in the value.

In the first 10 years, the value decreased by 16% (40,000 x 0.84 = 33,600).
Then, in the next ten years the value increased by 16% (33,600 x 1.16 = 38,976).
Therefore the answer is C.

Test: Quantitative Aptitude- 3 - Question 5

The value of a “Tin-Rin” stock in the stock market decreased by 15% in the last two years.
The economic experts believe that the value of the stock will increase by 7% during the following year, which will make the value $440. What was the approximate price of the stock two years ago?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 5

Let the stock value was x.
x* 0.85 * 1.07= 440
x= 440/0.85*1.07= 490 (approximately)
A is the answer

Test: Quantitative Aptitude- 3 - Question 6

Which of the following expressions is equivalent to |X| <4 ?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 6

The best answer is E.
An absolute value means that the sign of the variable is insignificant, therefore X can be between –4 and 4 and still he will fulfill the original equation. 

Test: Quantitative Aptitude- 3 - Question 7

Which of the following statements is equivalent to (8 + 2X < 18 – 6X < 23 + 2X) 

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 7

The best answer is C.

Take the expression and simplify it: Take (8 + 2x) from each side to get:  (0<10 – 8X<15).
Substitute 10, -10<-8X<5.
Divide all by (-8), 5/4 > X > -5/8. Therefore the answer is C.

Test: Quantitative Aptitude- 3 - Question 8

At the faculty of Aerospace Engineering, 312 students study Random-processing methods, 232 students study Scramjet rocket engines and 112 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 8

The best answer is D.

Use the group formula.
Total = groupA + groupB – Both + Neither.
Total = 312 + 232 – 112 + 0 = 432 students

Test: Quantitative Aptitude- 3 - Question 9

In the faculty of Reverse-Engineering, 226 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 9

The best answer is D.

Use the group formula.
Total = groupA + groupB – Both + Neither.
Total = 226 + 423 – 134 + 0 = 515 second year students.
The second year students are 80% of the total amount, therefore (515/80 x 100 = 643.75).
The best answer is D.

Test: Quantitative Aptitude- 3 - Question 10

In the Biotechnology class of 2000, there were X graduates. 32 of the graduates found a job, 45 continued on to their second degree and 13 did both. If only 9 people didn’t do both, What is X equal to?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 10

The best answer is C.

Use the group formula.
Total = groupA + groupB – Both + Neither.
Total = 32 + 45 – 13 + 9 = 73 graduates.

Test: Quantitative Aptitude- 3 - Question 11

In the equation (X + Y = k), k is a constant and X equals 13 when Y equals 23.5. What can be the value of X2 when Yis equal to 36?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 11

The best answer is E.

First, find the constant k. Plug in the numbers to get k = 13 + 23.5 = 36.5.
Now, Y2 = 36 → Y = 6 or (-6). Plug both numbers to get X = 30.5 or X = 42.5.
The best answer is E, (30.5)2 = 930.25.

Test: Quantitative Aptitude- 3 - Question 12

Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, How many cases can Kramer pack in 2 hours?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 12

The best answer is B.

Y/X is the time it takes Kramer to fill a case with boxes (in minutes).
In two hours there are 120 minutes, so 120/(Y/X) is 120X/Y, and that is the number of cases that Kramer can fill in two hours.

Test: Quantitative Aptitude- 3 - Question 13

In the equation 4Y- 3kX = 18, k is a constant and Y equals 42 when X equals 12. What is the approximate value of X when Y equals 36?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 13

The best answer is B.

First, find the constant k. Plug in the numbers for X and Y, to receive 4 x 42 – 3k x 12 = 18 → k = (168-18)/36 = 25/6.

Now, plug in the value of Y to receive: 4 x 36 – 3kX = 18 → after a little math, X is equal to 10.08, therefore the approximate answer is 10.

Test: Quantitative Aptitude- 3 - Question 14

George can fill Q cans of paint in 3 minutes. If there are R cans of paint in one gallon, how many gallons can George fill in 45 minutes?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 14

The best answer is E.

George can fill Q/3 cans of paint in one minute à There are R cans in one gallon, so R/(Q/3) = 3R/Q
Is the time it takes George to fill one gallon (in minutes).
In 45 minutes George can fill up 45/(3R/Q) = 15Q/R.

Test: Quantitative Aptitude- 3 - Question 15

A confectioner decides to sell all of his pastry due to the coming holiday. His pastry goods are equally divided among a group of 28 regular customers. If only 49 customers come to the bakery, each one will receive 6 less pastry goods. How much pastry does the confectioner needs to sell?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 15

The best answer is A.

You can use the answers to back-solve the question or you could write the equations.
Take 392 pastry goods and divide them by 28 customers, each one will receive 14 products.
If there were 49 customers, each one would receive (392/49 = 8), which is 6 less.

Test: Quantitative Aptitude- 3 - Question 16

A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many apples did each person get before 45 people joined the feast?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 16
- Let the original number of people be x.
- Each person initially gets 1430/x apples.
- After 45 more join, the number of people becomes x + 45.
- Each then gets 1430/(x + 45) apples.
- The condition given is: 1430/(x + 45) = 1430/x - 9.
- Solving this equation gives x = 22.
- Therefore, each person initially received 1430/22 = 65 apples.
Test: Quantitative Aptitude- 3 - Question 17

A jar of 264 marbles is divided equally among a group of marble-players. If 2 people join the group, each one would receive 1 marble less. How many people are there in the group today?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 17

Test: Quantitative Aptitude- 3 - Question 18

How many 3-digit numbers are possible using permutations with repetition allowed if digits are 1-9?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 18

1-9 digits which means 9 digits are possible. We have to arrange 3 digits at a time out of 9 digits with repetition allowed. So, total permutations are nr = 93 = 729.

Test: Quantitative Aptitude- 3 - Question 19

if x and y are positive integers (x>y), what is the units’ digit of (10x – 9y)2 ?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 19

The best answer is E.

Try some numbers, x=2, y=1.
(106 – 92)2 = 81. And it will work with any given number under the conditions given.

Test: Quantitative Aptitude- 3 - Question 20

Two brothers took the GMAT exam, the higher score is X and the lower one is Y. If the difference between the two scores is equal to their average, what is the value of Y/X ?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 20

The best answer is D.

If the difference is equal to the average, then we could write the equation: X – Y = (X +Y)/2.
→ X – 3Y = 0 →Y/X = 1/3

Test: Quantitative Aptitude- 3 - Question 21

Two people measure each other’s height, the height of the taller person is H and the height of the other person is L. If the differences in their height is equal to their average height, what is the Value of H/L ?

Detailed Solution for Test: Quantitative Aptitude- 3 - Question 21

The best answer is D.

If the difference is equal to the average, then we could write the equation: H – L = (H+L)/2.
→ H – 3L = 0 → H/L = 3.

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