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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Random Process - Electrical Engineering (EE) MCQ

Test: Random Process - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Random Process

Test: Random Process for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Random Process questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Random Process MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Random Process below.
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Test: Random Process - Question 1
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For random process X = 6 and Rxx (t, t+t) = 36 + 25 exp(|t|). Consider following statements:
(i) X(t) is first order stationary.
(ii) X(t) has total average power of 36 W.
(iii) X(t) is a wide sense stationary.
(iv) X(t) has a periodic component.

Q. Which of the following is true?

Detailed Solution for Test: Random Process - Question 1

X Constant and Rxx() is not a function of t, so X(t) is a wide sense stationary. So (i) is false & (iii) is true. Pxx = Rxx(0) 36+25 = 61. Thus (ii) is false if X(t) has a periodic component, then RXX(t) will have a periodic component with the same period. Thus (iv) is false.

Test: Random Process - Question 2
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White noise with power density No/2 = 6 microW/Hz is applied to an ideal filter of gain 1 and bandwidth W rad/s. If the output’s average noise power is 15 watts, the bandwidth W is

Detailed Solution for Test: Random Process - Question 2

Pyy = 1/2p Integral(?xx(w) |H(w)|^2 dw ) from plus infinity to minus infinity. Hence solve for W.

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Test: Random Process - Question 3
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(Q.3-Q.4) The two-level semi-random binary process is defined by X(t) A or -A where (n 1)T < t < nt and the levels A and -A occur with equal probability. T is a positive constant and n = 0, ±1, ±2.

The mean value E[X(t)] is

Detailed Solution for Test: Random Process - Question 3

 E[X(t)] = A P(A) – (-A)P(-A) which is zero.

Test: Random Process - Question 4
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The auto correlation Rxx(t1 = 0.5T, t2 = 0.7T) will be
Detailed Solution for Test: Random Process - Question 4

Here Rxx is AxA if both t1 and t2 are different and zero if they are same. Hence the answer is AxA.

Test: Random Process - Question 5
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 Air craft of Jet Airways at Ahmedabad airport arrive according to a Poisson process at a rate of 12 per hour. All aircraft are handled by one air traffic controller. If the controller takes a 2 – minute coffee break, what is the probability that he will miss one or more arriving aircraft?
Detailed Solution for Test: Random Process - Question 5

P (miss/or more aircraft) = 1 – P(miss 0) = 1 – P(0 arrive).

Test: Random Process - Question 6
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A stationary random process X(t) is applied to the input of a system for which h(t) = u(t) t2e(-8t). If E[X(t)] = 2, the mean value of the system’s response Y(t) is
Detailed Solution for Test: Random Process - Question 6

The mean value of Y(t) is integral of h(t)dt over negative infinity to positive infinity which gives the value equal to 3/128.

Test: Random Process - Question 7
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A random process is defined by X(t) + A where A is continuous random variable uniformly distributed on(0,1).

The auto correlation function and mean of the process is
Detailed Solution for Test: Random Process - Question 7

E[X(t)X(t+t)] = 1/3 and E[X(t)] = 1/2 respectively.

Test: Random Process - Question 8
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(Q.8-Q.9) The auto correlation function of a stationary ergodic random process is shown below.

Q.  The mean value E[X(t)] is
Detailed Solution for Test: Random Process - Question 8

Lim |t| tends to infinity, Rxx(t) = 20 = X2. hence X is sqrt(20).

Test: Random Process - Question 9
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The E[X2(t)] is
Detailed Solution for Test: Random Process - Question 9

Rxx(0) = X2 = 50.

Test: Random Process - Question 10
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The variance is
Detailed Solution for Test: Random Process - Question 10

Here X = 0, y = 0, Rxx(0) = 5, Ryy(0) = 10. The only value that satisfies all the given conditions is 30.

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