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If 2^{x }x 3^{y }x 5^{z} = 360 then what is the value of x, y, z?
Find the value of [log_{10 }25  log_{10}(2^{3}) + log_{10}(4)^{2}]
= [log_{10 }25  log_{10}(2^{3}) + log_{10}(4)^{2}]
= (1.397940009  0.903089987 + 1.204119983)
= 1.698970005
If 2^{x}2^{x1}=4 then x^{x} is equal to :
2^{x}2^{x1} =4 , then taking common 2^{x1}
2^{x1}(21) = 4 , 2^{x1} =4 ,
2^{x}1=2^{2}, simplify
x1 = 2, x = 3 then
x^{x }= 3^{3 }= 27
hence 27 is the required answer
What must be added to each term of the ratio 49:68, so that it becomes 3:4?
If A, B and C started a business by investing Rs. 1,26,000, Rs. 84,000 and Rs. 2,10,000. If at the end of the year profit is Rs. 2,42,000 then the share of each is:
If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then find the value of A:B:C:D
Log_{4} (x^{2}+x)  log_{4} (x+1) = 2. Find x
Fourth proportional to x, 2x, (x+1) is:
If x=3^{1/3}+3^{1/3} then find value of 3x^{3}9x
If log_{a} b + log_{a} c=0 then
The value of log_{2} (log_{5} 625) is :
Let log_{5} 625 = x.
Then, 5^{x} = 625 = 5^{4} or x = 4.
Let log_{2}(log_{5} 625) = y.
Then, log_{2} 4 = y or 2^{y}= 4 = 2^{2} or y = 2.
∴ log_{2}(log_{5} 625) = 2.
If A:B=2:5, then (10A+3B):(5A+2B) is equal to
A/B = 2/5
so in (10A+3B)/(5A+2B)
divide both numerator and denominator by B
(10A/B +3)/(5A/B +2)
put A/B value
this becomes (10 * 2/5 + 3)/(5 * 2/5 + 2)
=7/4 = 7:4
Find the subduplicate ratio of 81 : 64 ?
Required sub  duplicate ratio of 81 : 64 = √81 : √64 = 9 : 8
The sub duplicate ratio of 25:36 is
The ratio compounded of 2:3, 9:4, 5:6 and 8:10 is
The sub triplicate ratio of 8:27 is
The triplicate ratio of 2:3 is
The student of two classes are in the ratio 5:7, if 10 students left from each class, the remaining students are in the ratio of 4:6 then the number of students in each class is:
The ratio of two quantities is 3:4. If the antecedent is 15, the consequent is
The ratio compounded of 4:9, the duplicate ratio of 3:4, the triplicate ratio of 2:3 and 9:7is
Stepbystep explanation:
The duplicate ratio of 3:4 is 3^2/4^2 = 9/16.
The triplicate ratio of 2:3 is 2^3/3^3 = 8/27.
Now we have 4 ratios: 4:9, 9:16, 8:27 and 9:7.
We have to calculate the ratio compounded of all these ratios.
That will be (4 x 9 x 8 x 9)/(9 x 16 x 27 x 7) = 2/21.
The duplicate ratio of 3:4 is
The ratio compounded of 4:9 and the duplicate ratio of 3:4 is
Option ( a) 1:4 is right.
Explanation:
Duplicate ratio of 3:4 , will be the square of the ratio, so this will be 9:16
And the compounded ratio will be product of two ratios:
4:9 * 9:16 => 1:4
( 9 will be cancelled and 16 by 4 )
The recurring decimal 2.7777………….can be expressed as
The ratio of the quantities is 5:7. If the consequent of its inverse ratio is 5, the antecedent is
The angles of a triangle are in ratio 2:7:11. The angles are
If p:q =2:3 and x:y = 4:5, then the value of 5px + 3qy: 10px + 4qy is
Given as :
The ratio are as follows
p : q = 2 : 3
Let The value of p = 2 a ,
Let The value of q = 3 a
And
x : y = 4 : 5
Let The value of x = 4 b
Let The value of y = 5 b
Now, According to question
Let 5 p x + 3 q y : 10 p x + 4 q y = m : n
Two numbers are in the ratio 2:3. If 4 be subtracted from each, they are in the ratio 3:5. The numbers are
Two numbers are in the ratio 2:3.
Let the two numbers are 2x and 3x.
If 4 be subtracted from each, they are in the ratio 3:5.
The value of x is 8.
The two numbers are
2x = 2 * 8 = 16
3x = 3 * 8 = 24
Therefore the two numbers are 16 and 24.
If x:y = 3:4, the value of (x^{2}y+xy^{2}):(x^{3} +y^{3}) is
(x^{2}y+xy^{2}):(x^{3} +y^{3}) divide boht numerator and denominator by y^{3}
(x^{2}/y^{2} + x/y) / ((x/y)^{3} + 1)
put value of x/y = 3/4
(9/16 + 3/4) / (27/64 + 1)
= 12/13
P, Q and R are three cities. The ratio of average temperature between P and Q is 11:12 and that between P and R is 9:8. The ratio between the average temperature of Q and R is
The ratio of two numbers is 7:10 and their difference is 105. The numbers are
We don't know the numbers so let it be xX
7x,10x and they said that the difference of two numbers is 105
10x7x=105
3x=105
X=105/3
X=35
So the numbers are 245,350
Daily earnings of two persons are in the ratio 4:5 and their daily expenses are in the ratio 7:9. If each saves Rs. 50 per day, their daily incomes in Rs. are
The number which when subtracted from each of the terms of the ratio 19:31 reducing it to 1:4 is
If 2s:3t is the duplicate ratio of 2sp:3tp then
The ratio compounded of duplicate ratio of 4:5, triplicate ratio of 1:3, sub duplicate ratio of 81: 256 and sub triplicate ratio of 125: 512 is
duplicate of 4:5 = 16/25
tripicate of 1:3 = 1/27
sub duplicate of 81:256 =9/16
sub triplicate of 125:512 =5/8
now mulitipliy (16*1*9*5) :(25*27*16*8)
=1/120
The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
Let the speed of two trains be 7x and 8x km/hr.
Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
Division of Rs. 324 between X and Y is in the ratio 11:7. X & Y would get Rupees
If a : b = 3:4, the value of (2a+3b) : (3a+4b) is
a/b=3/4
So,
[(2 x 3k)+(3 x 4k)]/[(3 x 3k)+(4 x 4k)]
= (6k+12k)/(9k+16k)
=18/25.
Anand earns Rs. 80 in 7 hours and Promod Rs. 90 in 12 hours. The ratio of their earnings is
Earning of Anand in 1 hour=80/7
earning of promod in 1 hour 90/12
so ratio of their earnings =(80/7)/90/12=80*12/90*7=96/63=32/21
If x/2=y/3=z/7, then the value of (2x5y+4z)/2y is
The ratio of market prices of wheat and paddy is 2:3 and the ratio of quantities consumed in a family is 5:4. Find the ratio of expenditure of wheat and paddy.
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