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Class 10 Exam  >  Class 10 Tests  >  Test: Resistors In Series & Parallel - Class 10 MCQ

Test: Resistors In Series & Parallel - Class 10 MCQ


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5 Questions MCQ Test - Test: Resistors In Series & Parallel

Test: Resistors In Series & Parallel for Class 10 2025 is part of Class 10 preparation. The Test: Resistors In Series & Parallel questions and answers have been prepared according to the Class 10 exam syllabus.The Test: Resistors In Series & Parallel MCQs are made for Class 10 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Resistors In Series & Parallel below.
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Test: Resistors In Series & Parallel - Question 1
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When a number of resistors are connected in parallel, then their resultant resistance is ______________ the smallest individual resistance.

Detailed Solution for Test: Resistors In Series & Parallel - Question 1

When resistors are connected in parallel, the reciprocal of the total resistance (Rtotal) is equal to the sum of the reciprocals of the individual resistances. Mathematically:

1/Rtotal = 1/R₁ + 1/R₂ + 1/R₃ + ...

This means that the total resistance is always less than the smallest individual resistance in the circuit. This occurs because the parallel connection provides multiple pathways for current to flow, reducing the overall resistance.

Test: Resistors In Series & Parallel - Question 2
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Four resistors of 4 ohm each are connected in parallel, four such combinations are then connected in series. Their total resistance is

Detailed Solution for Test: Resistors In Series & Parallel - Question 2

Then, four such combination are connected in series Rtotal = 1 + 1 + 1 +1 = 4 Ω

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Test: Resistors In Series & Parallel - Question 3
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Two resistors 4Ω and 2Ω are connected in series, and potential difference of 12 V is applied across the combination. Then, the current through the circuit is:​

Detailed Solution for Test: Resistors In Series & Parallel - Question 3
- When resistors are connected in series, the total resistance is the sum of their individual resistances.
- Here, the resistors are 4Ω and 2Ω.
- Total resistance = 4Ω + 2Ω = 6Ω.
- A potential difference of 12V is applied across the combination.
- Using Ohm's Law (V = I * R), we can find the current:
- Current (I) = Voltage (V) / Total Resistance (R) = 12V / 6Ω = 2A.
- Therefore, the current through the circuit is 2A.
Test: Resistors In Series & Parallel - Question 4
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The decrease of resistance in parallel combination is due to:
Detailed Solution for Test: Resistors In Series & Parallel - Question 4

When connections are made in parallel, the length remains the same and area gets increase, thereby reducing the resistance.Resistance is directly proportional to length and inversely proportional to area and area is a function of diameter of wire.

Test: Resistors In Series & Parallel - Question 5
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The combined resistance of 6Ω and 12Ω connected in parallel is
Detailed Solution for Test: Resistors In Series & Parallel - Question 5

Explanation:-   In parallel, we know ; 
1/ R p  = 1/R1 + 1/R2 + ----------
1/ Rp  =   1/ 6 + 1/12 
1/ Rp   =  1/ 4
Therefore  , Rp = 4 ohm.

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