If and h = 0.2, then solving by fourth order Runge-Kutta method:
Consider the first order initial value problem
y’ = y + 2x – x2, y(0) = 1, (0 ≤ x < ∞) with exact solution y(x) = x2 + ex. For x = 0.1, the percentage diference between the exact solution and the solution obtained using a single iteration of the second-order Runge Kutta method with step size h = 0.1 is
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A gradually varied flow profile can be governed by equation where x is distance and y is the depth of water above the bed level. Which of the following methods can be used for solution?
Consider an ordinary differential equation If x = xo at t = 0, the increment in x calculated using Runge Kutta fourth order multistep method with a step size of Δt = 0.2 is
Runge-Kutta fourth order method is used to solve the differential equation If the initial value y(0) = 2 and step-size is 0.1, then the value of k1, k2, k3, and k4 respectively is?
65 videos|120 docs|94 tests
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65 videos|120 docs|94 tests
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