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Test: Semiconductors - 6 - JEE MCQ


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19 Questions MCQ Test - Test: Semiconductors - 6

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Test: Semiconductors - 6 - Question 1

In pure silicon at 300 K the electron and hole concentration is each equal to 1.5 × 1016 m−3. When doped with indium, the hole concentration increases to 4.5 × 1022 m−3. What is the electron concentration in doped silicon?

Detailed Solution for Test: Semiconductors - 6 - Question 1

Given n= 1.5 × 1016 m−3 and nh = 4.5 × 1022 m−3
Now, we know that

Test: Semiconductors - 6 - Question 2

The truth table for the circuit given in the figure is:

Detailed Solution for Test: Semiconductors - 6 - Question 2

Test: Semiconductors - 6 - Question 3

The circuit shown below contains two ideal diodes, each with a forward resistance of If the battery voltage is the current through the resistance (in amperes) is:

Detailed Solution for Test: Semiconductors - 6 - Question 3

Since the second diode is reverse biased, it will block the current, so the simplified circuit is as shown in the figure

Test: Semiconductors - 6 - Question 4

A Zener diode, having breakdown voltage equal to is used in a voltage regulator circuit shown in the figure. The current through the diode is

Detailed Solution for Test: Semiconductors - 6 - Question 4


For

For



Test: Semiconductors - 6 - Question 5

What is the Boolean expression for the gate circuit shown in Fig.

Detailed Solution for Test: Semiconductors - 6 - Question 5

The circuit is a combination of AND and NOT gates. The output of the NAND gate is connected to the input of a NOT gate. The combined circuit is called a NAND gate. The Boolean expression for the NAND operation is 
which means that the output X is just the negation of the output of the AND operation. Hence the correct choice is (a).

Test: Semiconductors - 6 - Question 6

For this truth table

Which logic expression is correct?

Detailed Solution for Test: Semiconductors - 6 - Question 6

This is Exclusive NOR gate or XNOR gate
Therefore 

Test: Semiconductors - 6 - Question 7
The combination of gates shown in Fig. yields
Detailed Solution for Test: Semiconductors - 6 - Question 7
Using a NOT gate after a NAND gate yields an AND gate. Hence the correct choice is (a).
Test: Semiconductors - 6 - Question 8

What is the maximum wavelength of electromagnetic radiation that create a electron-hole pair in material with band gap 0.7eV ? Planck's constant = 4.136 × 1015eV−s, velocity of light = 3 × 108 m/s.

Detailed Solution for Test: Semiconductors - 6 - Question 8

The band gap energy, Eg = 0.7eV
Let the maximum wavelength of the electromagnetic radiation be λ.

Test: Semiconductors - 6 - Question 9
In the figure, which of the diode is in reverse bias
Detailed Solution for Test: Semiconductors - 6 - Question 9
When type is at low potential and type is at the higher potential a diode is in forward bias.
Test: Semiconductors - 6 - Question 10
Two ideal junction diodes and are connected to a battery as shown in Fig. The current supplied by the battery is
Detailed Solution for Test: Semiconductors - 6 - Question 10
Diode is forward biased. Therefore, effective resistance is . Hence the current is

Thus the correct choice is (b).
Test: Semiconductors - 6 - Question 11

The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than is incident on it. The band gap energy (in ) for the semiconductor is

Detailed Solution for Test: Semiconductors - 6 - Question 11

Test: Semiconductors - 6 - Question 12
The knee point of the junction diode used in the circuit shown in Fig. is . A minimum current of is required for the diode to be above the knee point. The maximum value of so that the voltage across the diode is above the knee point is (assume that, above the knee point, the voltage across the diode is independent of the current).
Detailed Solution for Test: Semiconductors - 6 - Question 12
The maximum voltage drop across must be . Hence maximum value of is

Thus the correct choice is (b).
Test: Semiconductors - 6 - Question 13
A junction diode has a resistance of when forward biased and when reverse biased. The current in the arrangement shown in Fig. will be
Detailed Solution for Test: Semiconductors - 6 - Question 13
The junction diode is forward biased. Therefore, the effective resistance . The current is

Hence the correct choice is (b).
Test: Semiconductors - 6 - Question 14
In a semiconductor, it is found that th of the total current is carried by electrons and the remaining th by the holes. If at this temperature, the drift speed of electrons is times that of holes, the ratio of the number densities of electrons and holes is
Detailed Solution for Test: Semiconductors - 6 - Question 14
Given


Hence the correct choice is (a).
Test: Semiconductors - 6 - Question 15
The electrical conductivity of a semiconductor increases when electromagnetic radiation having a wavelength shorter than is incident on it. The bandgap (in ) for the semiconductor is
Detailed Solution for Test: Semiconductors - 6 - Question 15

Energy (in )
Test: Semiconductors - 6 - Question 16
An alternating voltage is connected across the primary of a step-down transformer of turns ratio . The output of the transformer is rectified as connected in the half-wave rectifier circuit as shown in Fig. If , the final charge on the capacitor plates is
Detailed Solution for Test: Semiconductors - 6 - Question 16
Peak value of output voltage from the transformer is

The junction diode conducts during the half cycle of the input when it is forward biased. During this half cycle, the capacitor is charged to the peak value of the supply voltage (which is ). Hence the final charge on capacitor plates is

So the correct choice is (b).
Test: Semiconductors - 6 - Question 17

The truth tables of two logic gates P and Q are as follows.

When the output of gate is connected to the input of gate , we get a new gate called

Detailed Solution for Test: Semiconductors - 6 - Question 17

Gate P is an AND gate and gate Q is a NOT gate. Hence the new gate formed is a NAND gate. So the correct choice is (c).

Test: Semiconductors - 6 - Question 18

The circuit shown in Fig. contains two diodes and each with a forward resistance of 50 ohms and with infinite backward resistance. If the battery voltage is , the current through the resistance (in amperes) is

Detailed Solution for Test: Semiconductors - 6 - Question 18

In the given circuit only diode will allow the current to pass through as it is forward-biased. Hence, the current through the 100 ohm resistance is (∵ resistance of D1 = 50Ω)

Test: Semiconductors - 6 - Question 19

The resistance of a germanium junction diode, whose V − I characteristics is shown in the figure, will be (vk = 0.3 V).

Detailed Solution for Test: Semiconductors - 6 - Question 19




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