Bending moment distribution in a beam is shown in the figure beiow.
The shear force diagram will be given by
It is a fixed beam carrying concentrated load at mid span. The shear force diagram will be given by (a).
A simply supported beam is loaded as shown in the figure. The maximum shear force in the beam will be
The reactions at the supports A and B respectively are
The SF diagram will be
The maximum shear force = 2 W.
The shape of the bending moment diagram for a cantilever beam carrying a uniformly distributed load over its length is
Mx = -wx2/2 which is parabolic in nature.
A simply supported beam is subjected to a distributed loading as shown in the diagram given
What is the maximum shear force in the beam?
The point of contraflexure is a point where
At the point of contraflexure, bending moment changes sign.
The ratio of reactions RA and RB of the simply supported beam (as shown) is
The bending moment in a simple supported beam can be calculated with the help of influence line drawn for the following types of load
In a simply supported beam of length ‘L’ with a triangular load varying from zero at one end to the maximum value at the other end, the maximum, bending moment is
For a simply supported beam of length L , the bending moment M is described as M = a (x - x3/L2), 0 ≤ x < L where a is a constant. The shear force will be zero at
if S = 0
⇒ x = L/√3
Match List-I (Type 0f .be4 rp.with type of loading) with List-ll ( Maximum BM formula) and select the correct answer using the codes given beiowthe lists: