All Courses
Get the App Signup / Login
Sign in Open App
Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Tests  >  GATE ECE (Electronics) Mock Test Series 2025  >  Test: Signals And Systems & Microprocessors - 2 - Electronics and Communication Engineering (ECE) MCQ

Test: Signals And Systems & Microprocessors - 2 - Electronics and Communication Engineering (ECE) MCQ


Test Description

20 Questions MCQ Test GATE ECE (Electronics) Mock Test Series 2025 - Test: Signals And Systems & Microprocessors - 2

Test: Signals And Systems & Microprocessors - 2 for Electronics and Communication Engineering (ECE) 2024 is part of GATE ECE (Electronics) Mock Test Series 2025 preparation. The Test: Signals And Systems & Microprocessors - 2 questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: Signals And Systems & Microprocessors - 2 MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Signals And Systems & Microprocessors - 2 below.
Solutions of Test: Signals And Systems & Microprocessors - 2 questions in English are available as part of our GATE ECE (Electronics) Mock Test Series 2025 for Electronics and Communication Engineering (ECE) & Test: Signals And Systems & Microprocessors - 2 solutions in Hindi for GATE ECE (Electronics) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt Test: Signals And Systems & Microprocessors - 2 | 20 questions in 60 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study GATE ECE (Electronics) Mock Test Series 2025 for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
*Answer can only contain numeric values
Test: Signals And Systems & Microprocessors - 2 - Question 1
Save

 A sequence x(n) with the z-transform X(z) = z3 + 2z2 - 3z + z-1 - 4z-3 is applied as an input to a linear, time-invariant system with the impulse response h(n) = 28(n - 2) where

The output at n = 2 is__________________________________


Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 1

The output y(n) can be drived as,
y(z) = I-1(z) X(z)

1.--1(z) = 2z-2

Y(z) = 2z-2 (z3 + 2z2 - 3z + z-1 - 4z-3) Y(z) 2(z + 2 - 3z-1 +

Taking inverse z-transform of Y(z) y(n) 2[6(n + 1) + 28(n) - 36(n - 1) +

(n - 3) -46(p - 511

At n = 2, y(2) = 0

Test: Signals And Systems & Microprocessors - 2 - Question 2
Save

then causal sequence f(n) is

Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 2




On equating both sides we get. A 4- C = 3.

4A- 2B + C D = 5,

48 + D = 0




1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Signals And Systems & Microprocessors - 2 - Question 3
Save

Q. The value of X(eiπ) = ?

Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 3

Since 

∵ 

= -1, when n = odd = +1, when rt = even

So,
 X(eiπ) = (2 +0+  2 + 0 +

[1 - 1 - 1 - 1 - 1 + 1]

4- 2 = 2

 

Test: Signals And Systems & Microprocessors - 2 - Question 4
Save

Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 4

∵

at n 0, we have

= 2π X 2 = 4 π

Test: Signals And Systems & Microprocessors - 2 - Question 5
Save

The Laplace transform of the waveform shown in the figure below is

Then what is the value of 'C'?
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 5

From the waveform shown we have, f(t) t u(t) - (t - 1) u(t - 1) -

(t - 4) u(t - 4) + 1 .5(t - 6) u(t - 6)

- 1,5(t - 8) LAO - 8)

∴ F(s) = LT of f(t)

Comparing this with the given Laplace transform and we get,

C = +1.5

Test: Signals And Systems & Microprocessors - 2 - Question 6
Save

Fourier transform of the signal shown in figure below is,
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 6

Also, from the given plot we have

x(t) = u(t 2) + u(t + 1) - u(t - 1) - u(t - 2)

••• (I)



 

Test: Signals And Systems & Microprocessors - 2 - Question 7
Save

Answer Questions (22 and 23):

A DTS described by H(z) =  when

 

excited by x[n] = cos(0.2 n + 10°) with discrete frequency Ω = 0.2.

Q. Find H(ejΩ) at Ω = 0.2 and is equals to
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 7

For the given input x[n] cos 2n

response, y[n] 

Now

Test: Signals And Systems & Microprocessors - 2 - Question 8
Save

Answer Questions (22 and 23):

A DTS described by H(z) =  when

 

excited by x[n] = cos(0.2 n + 10°) with discrete frequency Ω = 0.2.

Q. The steady state response y[n] is given by
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 8

Now the steady state response

y[n] = 0.25 cos[0.2 n 10° + 14,1°) [n] = 0.25 cos[0.2 n +24.1°1

Test: Signals And Systems & Microprocessors - 2 - Question 9
Save

 Fourier analysis of waveform shown in figure

Q. The waveform is
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 9

wave form is neither odd nor even.

Test: Signals And Systems & Microprocessors - 2 - Question 10
Save

 Fourier analysis of waveform shown in figure

Q.  In the waveform shown

1.

2.
3.
4.
5.
Test: Signals And Systems & Microprocessors - 2 - Question 11
Save

Causal sequence f(n) if F(z) =

, is given by
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 11



........................(i)

........................(ii)

From 0) and 0) we get

A 1, B = 1, C = -1

Also we know, f(n) = Inverse z-transform of F(z)

f(n) = [(-1)n (-3)n - (2)n ] u (n)

Test: Signals And Systems & Microprocessors - 2 - Question 12
Save

A signal x1(t) is having Fourier transform

Xi(co). Another signal x2(t) having Fourier transform X2(w) is related to Xi(co) by X2(w) = [1 +sg n(w)]Xi (co)

Value of x2(t) in terms of x1(t) will be
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 12

Test: Signals And Systems & Microprocessors - 2 - Question 13
Save

After some arithmetic operation flag register of 8085 microprocessor becomes BBH. The contents of the accumulator after the operation may be
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 13

Flag registers in 808511P is as,

Since, sign bit of 138.1-1. is 1 so, number is negative from the given choice only (c) or (d) gives the sign bit T.

Here, parity bit = 0 means total number of 1 's present is odd

So, only options (d) contains odd nu -r. her of 1's

 Here five l's are present.

Test: Signals And Systems & Microprocessors - 2 - Question 14
Save

The contents of register HL pair is 24FF H. Then the contents of register pair if, 1NR H and INR L operations are performed is
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 14

∴  [H] <— 24
and [L] <— FF

INH H means increment the content of 'H' by 01.

  ∴          [H] <—  25

and       [L] <— FE

⇒ Content of H-L pair = 25FF H

L means increment the content of 'L'by 01.

∴    [H] <—  24

and    [L]   <— [FF] + [01]

i.e.  [L] <— 00

⇒ Content of IH-L pair = 2400 H

Test: Signals And Systems & Microprocessors - 2 - Question 15
Save

If the HLT instruction of a 8085 microprocessor is executed then,
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 15

HLT  →  is a 1-byte instruction.

→ processor stops executing and enters wait state

→ no register contents are affected.

 → the address bus and data bus are placed in high impedance state

Test: Signals And Systems & Microprocessors - 2 - Question 16
Save

Line :                     MVI A,               B5H

MVI B,              OEH

XRI                   69H

ADD

ANI                    9BH

CPI                    9FH

STA                   3010 H

HLT

After execution of STA 3010H the status of Cy and Z flag will be
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 16

 

Line    Cy        Z

1

2           0         0

3           0         0

4           0         0

0          0

6           1         0

7         1

Test: Signals And Systems & Microprocessors - 2 - Question 17
Save

Three memory chips are of size 1 kB, 2 kB and 4 kB. Their address bus is 10 bits. The data bus sizes of chips are respectively
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 17

∴ Memory size

= Add, bus size x Data bus size.

=(2)add bus line x.(Data bus size)

So, for 1 kB Chip.

Data bus size = 

For 2 kB chip,

Data bus size =

= 16 bits

For 4 kB chip, Elata bus size

= 32 bits

Test: Signals And Systems & Microprocessors - 2 - Question 18
Save

An 8085 assembly language program is given below:

MV1C,           03H

LXI H,             2000 H

MOV             A, M

DCR

LOOP 1 : INX H

MOV B, M CMP B

JNC LOOP 2 MOV A, B

LOOP 2 : DCR C

JNZ LOOP 1 STA 2100 H HLT

Contents of memory location 2000: 18 H

2001 : 10H

2002 : 2BH

Q At the end of the program what will be the condition of carry and zero flags?
Test: Signals And Systems & Microprocessors - 2 - Question 19
Save

An 8085 assembly language program is given below:

MV1C,           03H

LXI H,             2000 H

MOV             A, M

DCR

LOOP 1 : INX H

MOV B, M CMP B

JNC LOOP 2 MOV A, B

LOOP 2 : DCR C

JNZ LOOP 1 STA 2100 H HLT

Contents of memory location 2000: 18 H

2001 : 10H

2002 : 2BH

Q  What does the program do?
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 19

Program is searching the value higher than the content of accumulator.

Test: Signals And Systems & Microprocessors - 2 - Question 20
Save

Consider the given instructions of program for the delay register.

MVI           C, FFH

LOOP: DCR              C

JNZ           LOOP

Assume clock frequency of the system is 2 MHz.

Q.  The total T-states for this above programme is given by
Detailed Solution for Test: Signals And Systems & Microprocessors - 2 - Question 20

MVI C, FFH  →  7 T-states

LOOP: DCR C  → 5 T-states

JNZ LOOP → 10 T-states

25 docs|263 tests
Join Course
Information about Test: Signals And Systems & Microprocessors - 2 Page
In this test you can find the Exam questions for Test: Signals And Systems & Microprocessors - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Signals And Systems & Microprocessors - 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Electronics and Communication Engineering (ECE)

Download as PDF

Top Courses for Electronics and Communication Engineering (ECE)

Important Questions for Signals And Systems & Microprocessors - 2

Find all the important questions for Signals And Systems & Microprocessors - 2 at EduRev.Get fully prepared for Signals And Systems & Microprocessors - 2 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Signals And Systems & Microprocessors - 2 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Signals And Systems & Microprocessors - 2 resources.

Signals And Systems & Microprocessors - 2 MCQs with Answers

Prepare for the Signals And Systems & Microprocessors - 2 within the Electronics and Communication Engineering (ECE) exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Signals And Systems & Microprocessors - 2 GATE ECE (Electronics) Mock Test Series 2025

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Signals And Systems & Microprocessors - 2 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup