Test: Simplification- 2 - SSC CGL MCQ

Expression:

( 47.932 + 56 + 97.168 - 67 - 78.3 - 22.7 )

Step 1: Add the positive terms:

( 47.932 + 56 + 97.168 = 201.1 )

Step 2: Add the negative terms:

( 67 + 78.3 + 22.7 = 168 )

Step 3: Subtract the sum of negative terms from the sum of positive terms:

( 201.1 - 168 = 33.1 )

Final Answer: The result of the expression is 33.1.

• To solve 4789300 x 11, we can break it down.
• First, multiply 4789300 by 10, which gives 47893000.
• Next, add 4789300 to that result (because 11 is 10 + 1).
• So, 47893000 + 4789300 = 52682300.
• The correct answer is 52682300, which is option 1.

To solve the expression:

Step 1: Convert the mixed fraction to a decimal.

6 ¹⁄₄   = 6.25)

Now, substitute (6.25) into the expression:

Expression: (6.25 + 0.25 + 0.75 - 0.3125)

Step 2: Calculate each operation:

• (6.25 + 0.25 = 6.5)
• (6.5 + 0.75 = 7.25)
• (7.25 - 0.3125 = 6.9375)

Answer: a) 6.9375

= we know,
(4-3+13-8)+(1/2 - 1/7 + 2/7 -1/4)
= 6 + 11/28

= option C 

Given equation:
√169 × 256 = (?)² × 13
Step 1: Calculate the square root of 169
√169 = 13
Substitute this value back into the equation:
13 × 256 = (?)² × 13

Step 2: Divide both sides by 13
256 = (?)²

Step 3: Solve for ( ? )
Taking the square root of both sides:
? = √256 = 16

The answer is: d) 16

The correct option is C.
(7*x)^2/49 = _/81
⇒ 49*x^2/49 = _/81
⇒ x² = _/81
⇒ x² = 9
⇒ x = 3

Given expression = 10 1/2 -[8 1/2+{6-(7–2)}]

= 10 1/2 -[8 1/2+{6–5}]

= 10 1/2 -[8 1/2+1]

= 10 1/2 -9 1/2

= 1

Given,

14.998% of 619.999 =?

It can also be approximated as

15% of 600=?

= ×600

= 90 ≈ 95

Given,

2³ × 3⁴ × 1080 ÷ 15 = 6^x

⇒ 2³ × 3⁴ × 72 = 6^x

⇒ 2³ × 3⁴ × (2 × 6²) = 6^x

⇒ 2⁴ × 3⁴ × 6² = 6^x

⇒ (2 × 3)⁴ × 6² = 6^x           [∵ x^m × y^m = (xy)^m]

⇒ 6⁴ × 6² = 6^x

⇒ 6^{(4 + 2)} = 6^x

⇒ x = 6

1. Start with the innermost part: 111 + 111 × 111

   111×111=12321
   111+12321=12432

2. Next, calculate 111÷12432, which is approximately 0 since 12432 is much larger than 111.

3. Substitute back into the expression:

   111−[111+{111×0}] = 111−[111+0] = 111−111 = 0

Answer: 0 (Option a)

x=
x²=380+x
x²-x-380=0
(x-20)(x+19)
 

1/7 = 0.1429
2/9 = 0.2222
4/11 = 0.3636
3/10 = 0.3
So, the greatest fraction is 4/11

Let the two-digit number be represented as 10a + b, where:

• a is the tens digit.
• b is the one digit.

According to the problem:

1. The sum of the digits is 8:

   a+b=8

2. When the digits are reversed, the number is decreased by 54. The number with reversed digits is 10b + a. So:

   10a+b−(10b+a)=54

   Simplifying this equation:

   10a+b−10b−a=54
   9a−9b=54
   a−b=6

Now, we have two equations:

1. a+b=8
2. a−b=6

Add these two equations:

(a+b)+(a−b)=8+6
2a = 14
a=7

Substitute a=7 into a+b=8:

7+b=8 , b = 1

So, the number is 10a+b=10×7+1=71

Answer: The number is 71.

Let the number be x.
x+x2=156
x²+x−156=0
(x−12)(x+13)=0

x+13=0
x=−13 (Since x is a natural number)
x−12=0
x=12

The correct answer is B as the unit place will be 7 only .

321 raised to 321=1 in unit digit and any number ending in 5 raised to any number has always 5 as unit digit, so 1×5=5