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Test: Structure of Atom - 2 - Grade 10 MCQ


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10 Questions MCQ Test Chemistry for Grade 10 - Test: Structure of Atom - 2

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Test: Structure of Atom - 2 - Question 1

What is the shape of the orbital, whose “l” is 1?

Detailed Solution for Test: Structure of Atom - 2 - Question 1

The azimuthal quantum number is given by “l”. When l =0, 1, 2, and 3, they are s-orbital, p-orbital, d-orbital, and f-orbital respectively. The shapes of s-orbital, p-orbital, d-orbital, and f-orbital are Spherical, Dumbbell, Double dumbbell, and Complex respectively.

Test: Structure of Atom - 2 - Question 2

No two electrons have the same set of all four quantum numbers.

Detailed Solution for Test: Structure of Atom - 2 - Question 2

Yes, no two electrons have the same set of all four quantum numbers. This is explained by Pauli’s exclusion principle. At most electrons can have all 3 quantum numbers the same as they are in the same orbital. But the spin quantum number’s values are different.

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Test: Structure of Atom - 2 - Question 3

What property of an element determines its chemical behaviour?

Detailed Solution for Test: Structure of Atom - 2 - Question 3

An element's valence is the number of hydrogen atoms that can combine with or replace (directly or indirectly) one of the element's atoms. Oxygen, for instance, has six valence electrons but its valence is 2. Some elements may have more than one power combination (or valence), while others may have only one.

Test: Structure of Atom - 2 - Question 4

What was the source of alpha particles in the Rutherford scattering experiment?

Detailed Solution for Test: Structure of Atom - 2 - Question 4

Alpha particle consists of two neutrons and two protons and is thus identical to the nucleus of a helium atom. It has no charge. The mass of the particle is approximately the sum of the mass of the proton and neutron. Its charge is equal to that of 2 protons.

Test: Structure of Atom - 2 - Question 5

Who discovered the electron?

Detailed Solution for Test: Structure of Atom - 2 - Question 5

J.J Thomson discovered electrons in 1897 by performing the cathode ray experiment. Electrons are the smallest of the particles that make up an atom, and they carry a negative charge. The number of protons and electrons is equal in a neutral atom.

Test: Structure of Atom - 2 - Question 6

The increasing order for the e/m values for the following are – 

Detailed Solution for Test: Structure of Atom - 2 - Question 6

The charge to mass ratio (e/m) for the following is as follows –

  • neutron, n = (0/1) = 0
  • α− particle = (2/4) = 0.5
  • Proton, p = (1/1) = 1
  • Electron, p = (1/1837) = 1837.
Test: Structure of Atom - 2 - Question 7

What does the magnetic quantum number signify? 

Detailed Solution for Test: Structure of Atom - 2 - Question 7

The magnetic quantum number signifies the orientation of orbitals

Test: Structure of Atom - 2 - Question 8

An element in the ground state that has 13 electrons in its M-shell is – 

Detailed Solution for Test: Structure of Atom - 2 - Question 8

As it is in M shell, n = 3

Number of electrons in M shell = 13 → 3s23p63d5

The electronic configuration is (1s2) (2s2 2p6) (3s2 3p6 3d5) (4s1)

The element is therefore chromium.

Test: Structure of Atom - 2 - Question 9

The ionization enthalpy of a hydrogen atom is 1.312 × 106 J mol-1. The energy to excite the electron from n = 1 to n = 2 is – 

Detailed Solution for Test: Structure of Atom - 2 - Question 9

The energy required when an electron shifts from n = 1 to n = 2

E2 = −(1.312 × 106 × (1)²)/(2²) = −3.28 × 105 J mol-1

E1 = −1.312 × 106 J mol-1

ΔE = E2 − E1

= −3.28 × 105−(−13.2 × 106)

ΔE = 9.84 × 105 J mol-1

Test: Structure of Atom - 2 - Question 10

In Bohr’s hydrogen atom model, the ratio of kinetic energy to the total energy of the electron in a quantum state n is

Detailed Solution for Test: Structure of Atom - 2 - Question 10

In the Bohr model, the kinetic energy of an electron in an orbit = + (1/2) (e2/rn)

Total energy of the electron in an orbit = -(e2/2rn)

Therefore, KE/TE = -1

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