Test: Tabulation - Bank Exams MCQ

F = Total production of R2 type of rice by all the states.
⇒ F = (6/17 × 0.4 × 0.68 + 9/19 × 0.4 × 0.38 + 3/8 × 0.4 × 0.48 + 4/9 × 0.45 × 0.48 + 3/13 × 0.2 × 0.26) × 625000
⇒ (0.096 + 0.072 + 0.072 + 0.096 + 0.012) × 625000
⇒ 0.348 × 625000
⇒ 217500
K = Average of the total production of R1 type of rice by all the states.
⇒ Total production of R1 type of rice by all the states = (0.6 × 0.68 + 0.6 × 0.38 + 0.6 × 0.48 + 0.55 × 0.48 + 0.8 × 0.26) × 625000
⇒ (0.408 + 0.228 + 0.288 + 0.264 + 0.208) × 625000
⇒ (1.396) × 625000
⇒ 872500
⇒ K = 872500/5 = 174500
∴ K/F = 174500/217500 = 0.802

⇒ R3 type of rice produced by state H = 11/17 × 0.4 × 0.68 × 625000 = 110000
⇒ R3 type of rice produced by state R = 10/19 × 0.4 × 0.38 × 625000 = 50000
⇒ R3 type of rice produced by state S = 5/9 × 0.45 × 0.48 × 625000 = 75000
⇒ R3 type of rice produced by state X = 5/8 × 0.4 × 0.48 × 625000 = 75000
⇒ A = Average of the R3 type of rice produced by state H, R, S and X together
⇒ A = (110000 + 50000 + 75000 + 75000) /4 = 77500
⇒ R2 type of rice produced by state T = 3/13 × 0.2 × 0.26 × 625000 = 7500
⇒ R1 type of rice produced by state R = 0.6 × 0.38 × 625000 = 142500
⇒ B = Difference between the R2 type of rice produced by state T and R1 type of rice produced by state R.
⇒ B = 142500 - 7500 = 135000
∴ B - A = 135000 - 77500 = 57500

Quantity of rice produced by state X = 0.48 × 625000 = 300000
⇒ (R2 and R3) type of rice produced by state X = 300000 × 0.40 = 120000
⇒ R3 type rice produced in state X = 5/8 × 120000 = 75000
And
⇒ Quantity of rice produced by state S = 625000 × 0.48 = 300000
⇒ R1 type rice produced in state S = 300000 × 0.55 = 165000
∴ Required percentage = (75000/165000) × 100 = 45.45%
A = Average of the R3 type of rice produced by state H, R, S and X together.
B = Difference between the R2 type of rice produced by state T and R1 type of rice produced by state R.

Total production of maize by state X and T = 625000 × (0.52 + 0.74) = 787500
Now
⇒ Quantity of rice produced by state S = 625000 × 0.48 = 300000
⇒ (R2 and R3) type of rice produced by state S = 300000 × 0.45 = 135000
⇒ R2 type of rice produced in state S = 4/9 × 135000 = 60000
And
⇒ Quantity of rice produced by state R = 625000 × 0.38 = 237500
⇒ (R2 and R3) type of rice produced by state R = 237500 × 0.4 = 95000
⇒ R2 type of rice produced in state R = 9/19 × 95000 = 45000
⇒ Total production of R2 type of Rice by state S and R = 60000 + 45000 = 105000
∴ Required sum = 787500 + 105000 = 892500

Rice produced by state X = 48% and that of by state H = 68%
⇒ Quantity of rice produced by state X = 0.48 × 625000 = 300000
⇒ R1 type of rice produced by state X = 300000 × 0.6 = 180000
Now
⇒ Quantity of rice produced by state H = 0.68 × 625000 = 425000
⇒ R1 type of rice produced by state H = 425000 × 0.6 = 255000
⇒ Remaining quantity of rice = 425000 - 255000 = 170000
⇒ R2 type of rice produced by state H = 6/17 × 170000 = 60000
∴ Required difference = 180000 - 60000 = 120000

Profit of A in year 2013 = 3,20,000 - 3,00,000 = Rs. 20,000
Profit of B in year 2016 = 4,50,000 - 4,00,000 = Rs. 50,000
Ratio = 20000/50000 = 2 : 5

Average income of A = (250000 + 320000 + 425000 + 490000 + 600000)/5 = Rs. 4,17,000
Average expenditure of A = (200000 + 300000 + 400000 + 450000 + 525000)/5= Rs. 3,75,000
Average profit of A = 417000 - 375000 = Rs. 42,000

Profit percentage of B for 2012 = (180000 - 150000)/150000 × 100 = 20%
Profit percentage of B for 2013 = (250000 - 220000)/220000 × 100 = 13.64%
Profit percentage of B for 2014 = (320000 - 300000)/300000 × 100 = 6.67%
Profit percentage of B for 2015 = (375000 - 350000)/350000 × 100 = 7.14%
Profit percentage of B for 2016 = (450000 - 400000)/400000 × 100 = 12.5%
The profit percentage of B for 2012 is the highest

Income of A in 2017 = 600000 × (600000/490000) = Rs. 7,34,693.88
Expenditure of A in 2017 = 525000 × (525000/450000) = Rs. 6,12,500
Profit percent = (734693.88 - 612500)612500 × 100 = 20%

• From the given data of 2014, we can see that.
• Profit of Company A = Income - expenditure
• = 425000 - 400000 = Rs 25000
• Profit of Company B = Income - Expenditure
• = 320000 - 300000 = Rs 20000
• Hence , Company A has more profit of Rs 25000

From the given data,

As we can see from the given table, the number of students appearing in all streams was minimum in the year 2014

Total students appearing in 2014 = 310 + 395 + 106 + 1180 = 1991
Students appearing in Arts stream in 2014 = 1180
Per cent of total students appearing in 2014, appeared in Arts stream 

Number of students appearing in Maths = 384
Number of students passed in 2013 = 326
Percentage of students appearing in Maths, passed in 2013 

The number of children in 1992 is = 23758
The number of men in 1992 is = 71274
Therefore, ratio is 1:3

∵ Total population in 1990 = 153922
∵ Decrease I population in 1991 over the preceding year = 5337
∵ Total population in 1991 = 153922 – 5337 = 148585
∴ Number of women in 1991 = 148585 – (69395 + 21560) = 57630

∵ Total population in 1988 = 146947
∵ Increase in population in 1989 over preceding year = 11630
∵ Total population in 1989 = 146947 + 11630 = 158577
∴ Number of children in 1989 = 158577 – (70391 + 62516) = 25670

∵ Total population in 1990 = 153922
∴ Number of men in 1990 = 153922 – (63143 + 20314) = 70465

∵ Total population in 1988 = 146947
∴ Number of children in 1988 = 146947 – (65104 + 60387) = 21456