Test: The Hall Effect - Electrical Engineering (EE) MCQ

To make Lorentz force into the effect, the electric field and magnetic field should be perpendicular to each other.

The Hall Effect is used for finding the whether the semiconductor is of n-type or p-type, mobility, conductivity and the carrier concentration.

The Hall Effect satisfies the Lorentz’s Force which is
E=vxB
So, the direction of the velocity, electric field and magnetic field should be perpendicular to each other.

E=vxB
v=E/B
=5/5
=1m/s.

Vh=E*d
=5*2/100
=0.1V.

 B=µH
So, option d is correct option.

Vh=BI/wρ
=5=2/ (5*10^-2*10⁵*1.6*10^-19)
=0.002V.

 R=1/ρ
=1/(1.6*10^-19*10²⁰)
=0.0625.

µ=σR
σ =µ/R
=5*10^-4/5
=0.0001 S/m.

In Hall Effect, the electric field is perpendicular to both current and magnetic field so that the force due to magnetic field can be balanced by the electric field or vice versa.