Test: The Ideal Diode - Electrical Engineering (EE) MCQ

Both of the facts mentioned hold true for an ideal operational amplifier.

V_d = V_i – V_o.

For one half of the cycle the diode conducts when 24 cos(Θ) = 12 or Θ is 60₀. Hence for a complete cycle the diode does not conducts for 2Θ or 120₀. Hence the diode does not conducts for a third of a cycle.

 Diodes are used to make rectifiers (full wave or half wave rectifiers are the most common examples), LED lamps uses diodes (diodes are generally doped for their use in this purpose) and logic gates can also be made using diodes using the fact that diodes are conducting only in the forward biased configuration.

The following circuit behaves as a OR logic gate.

The circuit shown behaves as an AND logic gate.

Average value of input voltage= 20/π or 6.366 V.
Since there is diode half of the time there is no voltage across the voltmeter hence the average value of the input voltage is 10/π or 3.183V.
The total resistance required to generate 1mA current is 3.183 kΩ out of which 50Ω is provided by the moving coil. Therefore, a resistance of 3.133 kΩ is required.

 I = V/R or 5/2.5 or 2A
For an ideal diode when it is conducting the potential drop across its terminal is zero.

The currents in forward bias is generally in MA and in the reverse bias it is very small and is generally measured in µA.

Both the statements are true for a diode.