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In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side. Every triangle has exactly three medians, one from each vertex, and they all intersect each other at the triangle's centroid.
A/an _____________ connect a vertex of a triangle to the midpoint of the opposite side.
A/an median connect a vertex of a triangle to the midpoint of the opposite side.
A triangle can have 3 altitudes
ΔABC is rightangled at C. If AC = 5 cm and BC = 12 cm find the length of AB.
By Pythagoras property,
AB^{2} = AC^{2} + BC^{2}
= 5^{2} + 12^{2} = 25 + 144 = 169 = 132
or AB^{2}= 132. So, AB = 13 or the length of AB is 13 cm.
In triangle PQR, for vertex Q the line joining the other two vertex is the side opposite to Q.
for example,
The vertex opposite to side RT is S.
Stepbystep explanation:
In the given question,
We have a triangle RST which has sides RS, ST and TR.
We know that a triangle consists three vertices and three sides each of which is particularly opposite to any one of the side of the triangle and viceversa.
Therefore, we can see here that in the triangle RST.
The side RS is opposite to the vertex T.
The side ST is opposite to the vertex R.
and,
The side TR is opposite to the vertex S.
Hence, the correct answer will be S as side RT is opposite to S.
In Δ PQR, PM is altitude
Find the value of x in the adjoining figure.
An exterior angle of a triangle is equal to the sum of the opposite interior angles
x^{o} = 70^{o} + 50^{o}
x^{o} = 120^{o} .
So option C is the correct answer.
An exterior angle of a triangle is equal to the sum of the opposite interior angles
So in the given figure
110^{o} = 50^{o} + x
110^{o}  50^{o} = x
60^{o} = x
So option B is correct answer.
An exterior angle of a triangle is equal to the sum of the opposite interior angles
So in the given figure
80^{o} = 30^{o} + x
it implies x = 50^{o}.
If the angles of a triangle are in the ratio 4:5:9. Find all the angles of a the triangle
The sum of the angles of a triangle is 180 degrees. As the ratio of the angles of the triangle is 4:5:9 they can be taken to be 4x, 5x and 9x. 4x + 5x + 9x = 180
=> 18x = 180
=> x = 10
This gives the angles of the triangle as 4*10=40,
5*10=50 and 9*10=90 degrees.
The triangle whose lengths of sides are 3 cm, 4 cm, 5 cm is a
a^{2}+b^{2}=c^{2}
we find 3^{2}+4^{2}=5^{2}
9 + 16 = 25
So, these sides also cause it to be a right triangle.
One of the angles of a triangle is 110° and the other two angles are equal what is the measure of each of these equal angles
One angle of the triangle = 110°
Let the other two angles each be x
Sum of all the angles of a triangle = 180°
x + x + 110 = 180
2x = 180  110
2x = 70
x = 35°
The other two angles are 35°, 35°.
The measure of three angles of a triangle are in the ratio 5:3:1.find the measure of this angles
Let the angles be x
sum of the angles of a triangle=180
5x+3x+x=180
9x=180
x=20
angle I = 5x = 5*20 = 100
angle II = 3x = 3*20 = 60
angle III = x = 20
The altitude and median be same for a which triangle?
Since the sides of the isosceles triangle are equal the line drawn from vertex to middle of the opposite side which is median is perpendicular. And altitude is also perpendicular . So both are the same in the isosceles triangle.
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