EduRev

Courses

Get the App Signup / Login

Welcome Back

Forgot Password?

New User? Sign Up

Create your account now

I accept the Terms & Conditions.

Already Have an Account? Login

Test: Theories of Column & Theories of Failure - 2

25 Questions MCQ Test RRB JE for Mechanical Engineering | Test: Theories of Column & Theories of Failure - 2

Description

Attempt Test: Theories of Column & Theories of Failure - 2 | 25 questions in 75 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study RRB JE for Mechanical Engineering for Mechanical Engineering Exam | Download free PDF with solutions

QUESTION: 1

Match 4 correct pairs between list I and List II for the questions

[GATE-1994]

A.
(a) - 3,

(c) -1,

(d) -5,

(e) -2
B.
(a) - 3,

(b) -1,

(d) -6,

(c) -5
C.
(b) -5 ,

(a) -6,

(e) -1,

(c) -2
D.
(a) - 3,

(b) -1,

(c) -5,

(d) -2

Solution:

St. Venant's law: Maximum principal strain theory

QUESTION: 2

Which theory of failure will you use for aluminium components under steady loading?

[GATE-1999]

A.
Principal stress theory
B.
Principal strain theory
C.
Strain energy theory
D.
Maximum shear stress theory

Solution:

Aluminium is a ductile material so use maximum shear stress theory

QUESTION: 3

According to Von-Mises' distortion energy theory, the distortion energy under three dimensional stress state is represented by

Solution:

QUESTION: 4

A small element at the critical section of a component is in a bi-axial state of stress with the two principal stresses being 360 MPa and 140 MPa. The maximum working stress according to Distortion Energy Theory is:

[GATE-1997]

A.
220 MPa
B.
110 MPa
C.
314 MPa
D.
330 MPa

Solution:

According to distortion energy theory if maximum stress (σt) then

QUESTION: 5

Match List-I (Theory of Failure) with List-II (Predicted Ratio of Shear Stress to Direct Stress at Yield Condition for Steel Specimen) and select the correct answer using the code given below the Lists:

[IES-2006]

A.
A
B.
B
C.
C
D.
D

Solution:

QUESTION: 6

A circular solid shaft is subjected to a bending moment of 400 kNm and a twisting moment of 300 kNm. On the basis of the maximum principal stress theory, the direct stress is σ and according to the maximum shear stress theory, the shear stress is τ . The ratio σ/τ is:

[IES-2000]

A.
1/3
B.
3/9
C.
9/5
D.
11/6

Solution:

QUESTION: 7

Design of shafts made of brittle materials is based on

[IES-1993]

A.
Guest's theory
B.
Rankine‟s theory
C.
St. Venant's theory
D.
Von Mises theory

Solution:

Rankine's theory or maximum principle stress theory is most commonly used for
brittle materials.

QUESTION: 8

According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:

[IES-1998: ISRO-2008]

A.
T/2
B.
T
C.
√2T
D.
2T

Solution:

principalstressesfor only thisshear stressare

maximum principal stress theory of failuregives

QUESTION: 9

A cold roller steel shaft is designed on the basis of maximum shear stress theory. The principal stresses induced at its critical section are 60 MPa and - 60 MPa respectively. If the yield stress for the shaft material is 360 MPa, the factor of safety of the design is

[IES-2002]

A.
2
B.
3
C.
4
D.
6

Solution:

QUESTION: 10

For a two-dimensional state stress the designed values are most conservative if which one of the following failure theories were used?

[IES-1998]

A.
Maximum principal strain theory
B.
Maximum distortion energy theory
C.
Maximum shear stress theory
D.
Maximum principal stress theory

Solution:

Graphical comparison of different failure theories
Above diagram shows that will occur at 4th quadrant and most
conservative design will be maximum shear stress theory.

QUESTION: 11

Who postulated the maximum distortion energy theory?

[IES-2008]

A.
Tresca
B.
Rankine
C.
St. Venant
D.
Mises-Henky

Solution:

Maximum shear stress theory → Tresca
Maximum principal stress theory → Rankine
Maximum principal strain theory → St. Venant
Maximum shear strain energy theory → Mises – Henky

QUESTION: 12

If σy is the yield strength of a particular material, then the distortion energy theory is expressed as

[IES-1994]

Solution:

QUESTION: 13

A transmission shaft subjected to bending loads must be designed on the basis of

[IES-1996]

A.
Maximum normal stress theory
B.
Maximum shear stress theory
C.
Maximum normal stress and maximum shear stress theories
D.
Fatigue strength

Solution:

QUESTION: 14

A rod having cross-sectional area 100 x 10^{- 6} m² is subjected to a tensile load. Based on the Tresca failure criterion, if the uniaxial yield stress of the material is 200 MPa, the failure load is:

[IES-2001]

A.
10 kN
B.
20 kN
C.
100 kN
D.
200 kN

Solution:

Tresca failure criterion is maximum shear stress theory.

Weknowthat

QUESTION: 15

Who postulated the maximum distortion energy theory?

[IES-2008]

A.
Tresca
B.
Rankine
C.
St. Venant
D.
Mises-Henky

Solution:

QUESTION: 16

For what is the physical boundary for Rankine failure theory?

[IAS-2004]

A.
A rectangle
B.
An ellipse
C.
A square
D.
A parabola

Solution:

Rankine failure theory or
Maximum principle stress theory.

QUESTION: 17

Which one of the following graphs represents Mises yield criterion?

IAS-1996]

Solution:

QUESTION: 18

The maximum distortion energy theory of failure is suitable to predict the failure of which one of the following types of materials?

[IES-2004]

A.
Brittle materials
B.
Ductile materials
C.
Plastics
D.
Composite materials

Solution:

QUESTION: 19

The ratio of Euler's buckling loads of columns with the same parameters having (i) both ends fixed, and (ii) both ends hinged is:

[GATE-1998; 2002; IES-2001]

A.
2
B.
4
C.
6
D.
8

Solution:

Euler‟s buckling loads of columns

QUESTION: 20

For a long slender column of uniform cross section, the ratio of critical buckling load for the case with both ends clamped to the case with both ends hinged is

[GATE-2012]

A.
1
B.
2
C.
4
D.
8

Solution:

QUESTION: 21

Four columns of same material and same length are of rectangular cross-section of same breadth b. The depth of the cross-section and the end conditions are, however different are given as follows:

Which of the above columns Euler buckling load maximum?

[IES-2004]

A.
Column 1
B.
Column 2
C.
Column 3
D.
Column 4

Solution:

QUESTION: 22

Assertion (A): A long column of square cross-section has greater buckling stability than that of a column of circular cross-section of same length, same material, same end conditions and same area of cross-section.

Reason (R): The second moment of area of a column of circular cross-section is smaller than that of a column of square cross section having the same area.

[IAS-1998]

A.
Both A and R are individually true and R is the correct explanation of A
B.
Both A and R are individually true but R is NOT the correct explanation of A
C.
A is true but R is false
D.
A is false but R is true

Solution:

QUESTION: 23

For which one of the following columns, Euler buckling load

[IAS-1999; 2004]

A.
Column with both hinged ends
B.
Column with one end fixed and other end free
C.
Column with both ends fixed
D.
Column with one end fixed and other hinged

Solution:

QUESTION: 24

What is the expression for the crippling load for a column of length „l‟ with one end fixed and other end free?

[IES-2006; GATE-1994]

A.
B.
C.
D.
none of these

Solution:

QUESTION: 25

Euler's formula gives 5 to 10% error in crippling load as compared to experimental results in practice because:

[IES-1998]

A.
Effect of direct stress is neglected
B.
Pin joints are not free from friction
C.
The assumptions made in using the formula are not met in practice
D.
The material does not behave in an ideal elastic way in tension and compression