Test: Thermodynamics of Chemical Equilibrium - JEE MCQ

For the following equilibrium at 373 K,
H₂O(g)H₂O(g)
ΔAG° is

For the following electrochemical cell reaction at 298 K,
 
E^°cell = 1.10 V

Given 
COCl₂(g)  CO(g) + Cl₂ (g)
Kp = 8 x 10^-9 atm
ΔS° = 30 cal K^-1 at 373 K.
Temperature at which phosgene will be 0.1 % dissociated at 2 atm
(R = 2 cal mol^-1K^-1)is

For the following equilibrium at 298 K,
CO(g) + H₂O (g)  CO₂(g) + H₂(g);
Δ _f G° (in kcal mol^-1) of CO = - 32.81, CO₂ = - 94.26, H₂O = - 54.64, H₂ = 0.0 then, degree of dissociation of CO(g) is

At 1 atmospheric pressure, N₂O₄ is 50% dissociated at 300 K and 80% dissociated at 400 K as given
N₂O₄ (g)  2NO₂ (g)
Thus, enthalpy of dissociation is

At 800 K, ΔG° for the reaction

NiO (s) + H₂(g)  Ni (s) + H₂O (g)

is - 9.0 kcal. Thus, ratio of pressures of water vapours and hydrogen in equilibrium with NiO and Ni at 800 K in terms of logarithm is

Direction (Q. Nos. 10) This sectionis based on statement I and Statement II. Select the correct answer from the code given below.

Q. Statement I

For a reaction  2NO₂(g)  N₂O₄ (g) variation of (log₁₀ K) with (T^-1) is represented as

Statement II

Association o f NO₂ to N₂O₄ is an exotherm ic efiange.

Direction (Q. No. 11) This section contains 4 multiple choice questions. Each question has four
choices (a), (b), (c) and (d), out of which ONE or  MORE THANT ONE  is correct.

Q. Variation o f equilibrium constant K with tem perature, T is given by van’t Hoff equation

Graphically it is shown as given θ = tan (0 .5) and OP = 10

Thus,

Direction (Q. Nos. 12-13) This section contains  a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

1 mole H₂(g) and 0.2 mole CO₂(g) are introduced in a vacuum flask at 450°C and 0.5 atm.

H₂(g) + CO₂  H₂O(G) + CO(g)

Analysis shows that mixture contains 10 moles per cent steam. Also equilibrium constant increases by one per cent per degree around 450°C.(log 1.1 = 0.0414)

Q. Equilibrium constant K_p is

1 mole H₂(g) and 0.2 mole CO₂(g) are introduced in a vacuum flask at 450°C and 0.5 atm.

H₂(g) + CO₂ (g)  H₂O (g) + CO (g)
Analysis shows that mixture contains 10 moles per cent steam. Also equilibrium constant increases by one per cent per degree around 450°C.(log 1.1 = 0.0414)

Q. ΔH (enthalpy change) by taking equilibrium constant at 450° C and 460° C is

Direction (Q. No. 14) Choice the correct combination of elements and column I and coloumn II  are given as option (a), (b), (c) and (d), out of which ONE option is correct.

The hydrogenation of pyridine (C₅H₅N) to piperidine (C₅H₁₁N)

C₅H₅N(g) + 3H₂(g)  C₅H₁₁N(g)

is an equilibrium process whose equilibrium constant (K_p)is given by

Match the thermodynamics parameters in column I with their respective values in column II.

Direction (Q. Nos. 15) This section contains 1 questions. when worked out will result in an integer from 0 to 9 (both inclusive)

For a reversible reaction 
Rate constant k₁ (forward)  = 10¹⁵e ^-2000/T and k₂ (backward ) = 10¹²e -^2000/T

What is the value of