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Test: Three Dimensional Geometry - 2 - JEE MCQ


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30 Questions MCQ Test Mathematics (Maths) for JEE Main & Advanced - Test: Three Dimensional Geometry - 2

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Test: Three Dimensional Geometry - 2 - Question 1

In the following case, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them. 2x – y + 3z – 1 = 0 and 2x – y + 3z + 3 = 0

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Test: Three Dimensional Geometry - 2 - Question 2

If l1, m1, n1 and l2, m2, n2 are the direction cosines of two lines; and θ is the acute angle between the two lines; then

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 2

If l1, m1, n1 and l2, m2, n2 are the direction cosines of two lines; and θ is the acute angle between the two lines; then the cosine of the angle between these two lines is given by : 

Test: Three Dimensional Geometry - 2 - Question 3

Find the distance of the point (0, 0, 0) from the plane 3x – 4y + 12 z = 3

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 3

As we know that the length of the perpendicular from point 
P(x1,y1,z1) from the plane a1x+b1y+c1z+d1 = 0 is given by: 

Test: Three Dimensional Geometry - 2 - Question 4

If a1, b1, c1 and a2, b2, c2 are the direction ratios of two lines and θ is the acute angle between the two lines; then

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 4

If a1, b1, c1 and a2, b2, c2 are the direction ratios of two lines and θθ is the acute angle between the two lines; then , the cosine of the angle between these two lines is given by :

Test: Three Dimensional Geometry - 2 - Question 5

The vector and cartesian equations of the planes that passes through the point (1, 0, – 2) and the normal to the plane is

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 5

Let 
be the position vector of the point  here,
. Therefore, the required vector equation of the plane is: 


Test: Three Dimensional Geometry - 2 - Question 6


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Test: Three Dimensional Geometry - 2 - Question 7

If the coordinates of point A, B, C are (–1, 3, 2), (2, 3, 5) and (3, 5, –2) respectively then angle A is

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Test: Three Dimensional Geometry - 2 - Question 8

The projection of a line on the axes are 2, 3, 6 then the length of line is

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Test: Three Dimensional Geometry - 2 - Question 9


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Test: Three Dimensional Geometry - 2 - Question 10

OABC is a tetrahedron whose vertices are O(0, 0, 0) ; A(a, 2, 3) ; B(1, b, 2) and C(2, 1, c). If its centroid be (1, 2, –1) then distance of the point (a, b, c) from the origin is 

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Test: Three Dimensional Geometry - 2 - Question 11

Find the direction cosines of line joining points (1, –1, –3) and (–1, 2, 3)

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Test: Three Dimensional Geometry - 2 - Question 12

A mirror and a source of light are situated at the origin O and at a point on OX respectively. A ray of light from the source strikes the mirror and is reflected. If the DRs of the normal to the plane of mirror are 1, –1, 1, then DCs for the reflected ray are -

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Test: Three Dimensional Geometry - 2 - Question 13

Foot of perpendicular from (1, 2, 3) to the line joining points (6, 7, 7) and (9, 9, 5) is-

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Test: Three Dimensional Geometry - 2 - Question 14


Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 14


Test: Three Dimensional Geometry - 2 - Question 15

If x + y + z = 0, | x | = | y | = | z | = 2 and θ is angle between y and z. then the value of cosec2θ  + cot2θ is equal to

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Test: Three Dimensional Geometry - 2 - Question 16


Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 16


Test: Three Dimensional Geometry - 2 - Question 17


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Test: Three Dimensional Geometry - 2 - Question 18

A line passing through A(1, 2, 3) and having direction ratios (3, 4, 5) meets a plane x + 2y – 3z = 5 at B, then distance AB is equal to-

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 18

Test: Three Dimensional Geometry - 2 - Question 19

The shortest distance between a diagonal of a cube of edge-length one unit and the edge not meeting it, is -

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 19

dr’s of diagonal through the origin are (1, 1, 1)


Test: Three Dimensional Geometry - 2 - Question 20

Angle between the rays with d.r.'s 4, – 3, 5 & 3, 4, 5 is-

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Test: Three Dimensional Geometry - 2 - Question 21

The direction cosines of the line joining the points (4, 3, –5) and (–2, 1, –8) are

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Test: Three Dimensional Geometry - 2 - Question 22

The volume of the tetrahedron included between the plane 3x + 4y –5z – 60 = 0 and the coordinate planes in cubic units is

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Test: Three Dimensional Geometry - 2 - Question 23

If the sum of the squares of the distance of a point from the three co-ordinate axes be 36, then its distance from the origin is

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Test: Three Dimensional Geometry - 2 - Question 24


Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 24


Test: Three Dimensional Geometry - 2 - Question 25


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Test: Three Dimensional Geometry - 2 - Question 26

If the sum of the squares of the distance of a point from the three co-ordinate axes be 36, then its distance from the origin is

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Test: Three Dimensional Geometry - 2 - Question 27

If the foot of perpendicular drawn from the origin to the plane is (4, – 2, – 5). Then equation of plane is

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Test: Three Dimensional Geometry - 2 - Question 28

Find the angle in degree between two lines whose direction cosines are given by ℓ+m+n=0,ℓ2+m2−n2=0

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 28

Eliminating n between the given relations, we get
2+m2−(−ℓ−m)2=0
or ℓm=0   ⇒   ℓ=0orm=0
Now ℓ=0
⇒   1.ℓ+0.m+0.n=0andℓ+m+n=0
60 Solving these we get
ℓ/0 = m/−1 =n/1                ....(i)
Similarly m = 0⇒   0.ℓ + 1.m + 0.n = 0        and ℓ + m + n = 0
Solving these we get ℓ/1 = m/0 = n/−1                ...... (ii)
thus dr's of given lines are 0, -1, 1 and 1, 0, -1 respectively.
Let θ is angle between them

Test: Three Dimensional Geometry - 2 - Question 29

A line passes through the point A(2,3,5) and is parallel to the vector If P is a point on this line such that AP=2√6, then the coordinates of point P can be

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Test: Three Dimensional Geometry - 2 - Question 30

The direction ratios of line I1 passing through P(1,3,4) and perpendicular to line (where I1 and I2 are coplanar) is

Detailed Solution for Test: Three Dimensional Geometry - 2 - Question 30

Q=(1+2λ,2+3λ,3+4λ)
Direction ratio of  
As is perpendicular to I2, product of their corresponding direction ratios is 0.
Now, (2λ)2+(3λ–1)3+(4λ–1)4=0.
⇒29λ=7
⇒λ=7/29
Direction ratio of line is (14,–8,–1).

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