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This mock test of Test: Torque for Class 11 helps you for every Class 11 entrance exam.
This contains 10 Multiple Choice Questions for Class 11 Test: Torque (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Torque quiz give you a good mix of easy questions and tough questions. Class 11
students definitely take this Test: Torque exercise for a better result in the exam. You can find other Test: Torque extra questions,
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QUESTION: 1

A stone of mass m tied to a string of length l is rotating along a circular path with constant speed v. The torque on the stone is

Solution:

Hence the torque is zero .Because the line of action of the tension passes through the centre .So lever arm of tension is zero So the torque acting is also zero .

QUESTION: 2

An engine develops a power of 360 kw, when rotating at 30 revolutions per second. The Torque required to deliver this power is

Solution:

The power delivered by the torque τ exerted on rotating body is given by

P=τω or τ=P/ω

Here P=360KW=360000 Watt

ω=30 x 2π rad/sec,

ω=60π rad/sec

now,

τ=360000 /60×3.14Nm

τ= 1910.8 Nm

QUESTION: 3

The dimension of are

Solution:

QUESTION: 4

Which of the following is an axial vector?

Solution:

Torque is an axial vector. Axial vectors are those vectors which represent rotational effect and act along the axis of rotation. E.g. angular velocity, torque, angular momentum etc. are axial vectors.

QUESTION: 5

Moment of inertia of a solid sphere of mass M and radius R is ______

Solution:

QUESTION: 6

A wheel having moment of inertia 3.5 kgm^{2} rotates about the vertical axis. The torque required to produce an angular acceleration of 25rad/s^{2} in the wheel is

Solution:

Torque = moment of inertia × angular acceleration

3.5 × 25 =87.5 Nm

QUESTION: 7

For a system to be in equilibrium, the net torques acting on it must balance. This is true only if the torque are taken about

Solution:

For a system to be in equilibrium torques on the system must be equal to zero

This is true only if the torques are taken about the centre of mass as the whole mass of the object seems to be situated at centre of mass.

QUESTION: 8

The rotational analog to the expression F = ma in linear motion is ___________in rotational motion.

Solution:

Force (in linear) = torque (in rotational)

Mass (in linear motion) = moment of inertia ( l ) (in rotational motion)

Acceleration(a) (in linear) = angular acceleration (α) (in rotational)

F = ma (in linear) and torque = Iα (in rotational)

QUESTION: 9

Rotational analogue of force of linear motion is

Solution:

Rotational analogue of force in linear motion is torque. Torque is the turning effect of force.

QUESTION: 10

When no external Torque acts on a system, what is conserved

Solution:

τ = dI/dt

If τ = 0 then L is conserved.

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