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Test: Units & Measurements (April 4) - JEE MCQ


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15 Questions MCQ Test Daily Test for JEE Preparation - Test: Units & Measurements (April 4)

Test: Units & Measurements (April 4) for JEE 2024 is part of Daily Test for JEE Preparation preparation. The Test: Units & Measurements (April 4) questions and answers have been prepared according to the JEE exam syllabus.The Test: Units & Measurements (April 4) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Units & Measurements (April 4) below.
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*Answer can only contain numeric values
Test: Units & Measurements (April 4) - Question 1

In a vernier calliper, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with tenth main scale division, then the value of vernier constant will be .............. x 10-2 mm. (in integers)


Test: Units & Measurements (April 4) - Question 2

If momentum [P], area [A] and time [T] are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is:

Detailed Solution for Test: Units & Measurements (April 4) - Question 2

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Test: Units & Measurements (April 4) - Question 3

Identify the pair of physical quantities that have same dimensions.

Detailed Solution for Test: Units & Measurements (April 4) - Question 3

Decay constant λ has dimensions of [T-1] because of the relation .
⇒ Velocity gradient and decay constant have same dimensions.

Test: Units & Measurements (April 4) - Question 4

If L, C and R are the self inductance, capacitance and resistance, respectively, which of the following does not have the dimension of time?

Detailed Solution for Test: Units & Measurements (April 4) - Question 4

does not have dimension of time.

RC and L/R are time constant, while  √LC is the reciprocal of angular frequency or has the dimension of time.

Test: Units & Measurements (April 4) - Question 5

Match List-I with List-II.

Choose the most appropriate answer from the options given below

Detailed Solution for Test: Units & Measurements (April 4) - Question 5

(a) Magnetic Induction = MT-2A-1
(b) Magnetic Flux = ML2T-2A-1
(c) Magnetic Permeability = MLT-2A-2
(d) Magnetization = M0L-1A

Test: Units & Measurements (April 4) - Question 6

Given below are two statements: One is labelled as Assertion (A) and other is labelled as Reason (R).

Assertion (A): Time period of oscillation of a liquid drop depends on surface tension (S), if density of the liquid is ρ and radius of the drop is r, then   is dimensionally correct, where K is dimensionless.

Reason (R): Using dimensional analysis, we get R.H.S. having different dimension than that of time period.

In the light of above statements, choose the correct answer from the options given below.

Detailed Solution for Test: Units & Measurements (April 4) - Question 6

Given,


Dimensions of LHS ≠ Dimensions of RHS

Test: Units & Measurements (April 4) - Question 7

A physical quantity 'y' is represented by the formula  If the percentage errors found in y, m, r, l and g are 18, 1, 0.5, 4 and p respectively, then find the values of x and p.

Test: Units & Measurements (April 4) - Question 8

Match List-I with List-II.

Detailed Solution for Test: Units & Measurements (April 4) - Question 8

SI unit of Rydberg constant = m-1
SI unit of Planck's constant = kg m2 s-1
SI unit of magnetic field energy density = kg m-1 s-2
SI unit of coefficient of viscosity = kg m-1 s-1

Test: Units & Measurements (April 4) - Question 9

The magnitude of vectors in the given figure are equal. The direction of with x-axis will be:

Detailed Solution for Test: Units & Measurements (April 4) - Question 9

*Answer can only contain numeric values
Test: Units & Measurements (April 4) - Question 10

The vernier constant of vernier callipers is 0.1 mm and it has zero error of (-0.05) cm. While measuring diameter of a sphere, the main scale reading is 1.7 cm and coinciding vernier division is 5. The corrected diameter will be _____ x 10-2 cm. (in integers)


Detailed Solution for Test: Units & Measurements (April 4) - Question 10

Measured diameter = MSR + VSR x VC
= 1.7 + 0.01 x 5
= 1.75
Corrected = Measured - Error
= 1.75 - (-0.05)
= 1.80 cm
= 180 × 10-2 cm
= 180

Test: Units & Measurements (April 4) - Question 11

If velocity [V], time [T] and force [F] are chosen as the base quantities, the dimensions of the mass will be:

Detailed Solution for Test: Units & Measurements (April 4) - Question 11

[M] = K[F]a [T]b [V]c
[M1] = [M1L1T-2]a [T1]b [L1T-1]C
a = 1, b = 1, c = -1
 [M] = [FTV-1]

*Answer can only contain numeric values
Test: Units & Measurements (April 4) - Question 12

The radius of a sphere is measured to be (7.50 ± 0.85) cm. Suppose the percentage error in its volume is x. The value of x, to the nearest integer, is _______.


Detailed Solution for Test: Units & Measurements (April 4) - Question 12

Test: Units & Measurements (April 4) - Question 13

Identify the pair of physical quantities which have different dimensions.

Detailed Solution for Test: Units & Measurements (April 4) - Question 13

Test: Units & Measurements (April 4) - Question 14

If  then the relative error in Z will be:

Test: Units & Measurements (April 4) - Question 15

A silver wire has mass (0.6  0.006) g, radius (0.5 ± 0.005) mm and length (4 ± 0.04) cm. The maximum percentage error in the measurement of its density will be:

Detailed Solution for Test: Units & Measurements (April 4) - Question 15

M = (0.6 ± 0.006) g
r = (0.5±  0.005) mm
l = (4 ± 0.04) cm

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