Work, Power And Energy NAT Level - 1

# Work, Power And Energy NAT Level - 1

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## 10 Questions MCQ Test Topic wise Tests for IIT JAM Physics | Work, Power And Energy NAT Level - 1

Work, Power And Energy NAT Level - 1 for IIT JAM 2022 is part of Topic wise Tests for IIT JAM Physics preparation. The Work, Power And Energy NAT Level - 1 questions and answers have been prepared according to the IIT JAM exam syllabus.The Work, Power And Energy NAT Level - 1 MCQs are made for IIT JAM 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Work, Power And Energy NAT Level - 1 below.
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*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 1

### The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25kg and initial velocity is 2m/s. When the distance covered by the body is 4m, its kinetic energy (in Joule) would be :

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 1

Area under curve
W = work done by resistive force F

*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 2

### A particle moves with a velocity  under the influence of a constant force  The instantaneous power  (in Js–1) applied to the particle is :

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 2

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Work, Power And Energy NAT Level - 1 - Question 3

### An electric motor creates a tension of 4500N in hoisting cable and reels it at the rate of  2m/s. What is the power of electric motor in kW?

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 3

*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 4

A body of mass 5kg is acted upon by a variable force. The force varies with the distance covered by the body. Find the kinetic energy (in Joule) of the body when the body has covered 30m distance? Assume that the body starts from rest.

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 4

Work done by force when body has covered 25m
Area under curve upto distance 25m

Area between  25m to 30m is
So total work done by variable force till 30m is 250+45 = 295Joule
So, change in kinetic energy = 295J.
So final energy  = 295J.

*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 5

In the figure shown initially spring is in unstretched state and blocks are at rest. Now 100N force is applied on block A and B  as shown in figure. After some time velocity of A becomes 2m/s and that of  4m/s and block A displaced by amount 10cm and spring is stretched by amount 30cm. Then work done by spring force on A will be (in Joule) :

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 5

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Work, Power And Energy NAT Level - 1 - Question 6

The potential energy for a force field  is given by  U(x,y) = sin(y). The force acting on the particle of mass m at

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 6

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Work, Power And Energy NAT Level - 1 - Question 7

A spring of force constant 800N/m has an extension of 5cm. The work done (in Joule) in extending it from 5cm to 15cm is :

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 7

*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 8

The work done by the force  where A is a constant and  x and y  in meters around the path shown is :

Take, A = 50N/m and d = 2.

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 8

*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 9

An object is moving along a straight line path from P to Q under the action of a force  If the co-ordinate of P and Q in metres are (3, 2, –1) and (2,-1,4) respectively. Then the work done by the force in Joule is :

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 9

*Answer can only contain numeric values
Work, Power And Energy NAT Level - 1 - Question 10

Power supplied to a particle of mass 2kg varies with time as P = watt. Here t is time in second. If velocity of particle at  t =0sec is v = 0m/s. The velocity of particle (in ms-1)  at time = 2sec  will be :

Detailed Solution for Work, Power And Energy NAT Level - 1 - Question 10

Applying work energy theorem

Solving we get v = 2 m/s

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