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Lakhmir Singh & Manjit Kaur Test: Motion - Free MCQ with solutions


MCQ Practice Test & Solutions: Lakhmir Singh & Manjit Kaur Test: Motion (10 Questions)

You can prepare effectively for Class 9 Science Class 9 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Lakhmir Singh & Manjit Kaur Test: Motion". These 10 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Lakhmir Singh & Manjit Kaur Test: Motion - Question 1

A vector quantity has

Detailed Solution: Question 1

Vector Quantity

  • Direction: A vector quantity has a specific direction in space. This means that not only does it have a magnitude, but it also has a specific orientation or direction in which it is pointing.
  • Magnitude: In addition to having a direction, a vector quantity also has a magnitude. This magnitude represents the size or strength of the vector, indicating how much of the quantity is present.
  • Both Magnitude and Direction: Therefore, a vector quantity possesses both magnitude and direction, distinguishing it from scalar quantities which only have magnitude. This dual nature of vectors allows for a more detailed description of physical quantities.

Topic in NCERT: SPEED WITH DIRECTION
Line in NCERT: "The quantity that specifies both these aspects is called velocity."

Lakhmir Singh & Manjit Kaur Test: Motion - Question 2

Odometer of automobiles records

Detailed Solution: Question 2

  • Odometer of automobiles records distance travelled.
  • The primary function of an odometer in automobiles is to measure and display the total distance the vehicle has traveled since it was first put into use.
  • This distance is usually displayed in kilometers or miles depending on the unit system used in the region.

Topic in NCERT: Example 7.2

Line in NCERT: "The odometer of a car reads 2000 km at the start of a trip and 2400 km at the end of the trip."

Lakhmir Singh & Manjit Kaur Test: Motion - Question 3

The speedometer of a car measures

Detailed Solution: Question 3

Speedometer Measurement

  • Instantaneous Speed: The speedometer of a car measures the instantaneous speed at any given moment.
  • It provides a real-time reading of how fast the car is moving at that particular moment.
  • This measurement is important for drivers to ensure they are following speed limits and driving safely.
  • It helps drivers make adjustments to their speed based on road conditions, traffic, and other factors.

Lakhmir Singh & Manjit Kaur Test: Motion - Question 4

If the displacement-time graph of a particle is parallel to the time axis, the velocity of the particle is

Detailed Solution: Question 4

  • A displacement–time graph shows how displacement changes with time.

  • If the graph is parallel to the time axis, it means that displacement is not changing over time.

  • This implies the particle is not moving, i.e., displacement is constant.

  • Velocity = change in displacement / time
    Since displacement doesn't change, the numerator is zero, so:

  • Velocity = Displacement/ Time = 0/Time = 0

Lakhmir Singh & Manjit Kaur Test: Motion - Question 5

The numerical ratio of displacement to distance for a moving object is

Detailed Solution: Question 5

  • Displacement is the straightest shot (shortest distance) between start and end.
  • Distance is the total path taken.
  • Imagine going for a walk around a block - the displacement is the length of one side, while the distance is the entire walk.
  • The numerical ratio of displacement to distance is calculated as displacement divided by distance.
  • So the ratio:
  • Can be 1 (straight path)
  • Is less than 1 (curved path or going back and forth)
  • Never more than 1

Therefore, the answer is D: equal to or less than 1.

Topic in NCERT: MOTION ALONG A STRAIGHT LINE

Line in NCERT: "The magnitude of displacement (35 km) is not equal to the path length (85 km)."

Lakhmir Singh & Manjit Kaur Test: Motion - Question 6

A body starting at a point, say A, reaches, say B, ahead in a straight line and returns back to A. Then there is

Detailed Solution: Question 6

  • Displacement is the straight line distance between the starting and ending points of an object's motion.
  • In this scenario, the body starts at A, goes to B, and then returns to A. Even though the body travels a certain distance (twice the distance between A and B), it ends up back at its starting point (A).
  • Since displacement considers the net change in position, and the body ends at the same point it started, the displacement is zero.

Topic in NCERT: Motion Along a Straight Line

Line in NCERT: "the final position coincides with the initial position, and therefore, the displacement is zero."

Lakhmir Singh & Manjit Kaur Test: Motion - Question 7

What does a steep slope on a distance-time graph indicate?

Detailed Solution: Question 7

  • In a distance-time graph, the slope or gradient. The greater the gradient, the greater the rate of change.
  • The line is equal to the speed of the object.
  • The steeper the line (and the greater the gradient) , the faster the object is moving.

On a distance–time graph, distance is on the vertical axis and time is on the horizontal axis. The slope indicates how rapidly the distance changes over time. If the line rises quickly (steeply), it means that more distance is covered in less time, indicating a higher speed. A flat line shows distance is not changing, so the object is not moving. A gentle slope shows distance increases slowly, meaning a slower speed. A steep slope shows distance increases quickly, meaning a faster speed. A curved line shows that the slope itself is changing, which means accelerated motion. Therefore, a steep slope indicates faster motion.

Topic in NCERT: DISTANCE–TIME GRAPHS

Line in NCERT: "Thus, the graph shown in Fig. 7.4 indicates that a steep slope represents faster motion."

Lakhmir Singh & Manjit Kaur Test: Motion - Question 8

Four cars A, B, C and D are moving on a levelled road. Their distance versus time graphs are shown in figure.
Choose the correct statement.

Detailed Solution: Question 8

  • Option B is correct because Car B has the flattest slope in its distance-time graph, indicating it covers the least distance in a given time and thus is the slowest among the four cars.

Lakhmir Singh & Manjit Kaur Test: Motion - Question 9

The displacement of the body in 5 seconds from the beginning of the motion is


Detailed Solution: Question 9

Displacement is calculated as the area under the velocity-time graph, which forms a triangle. Using the formula for the area of a triangle, Area = (1/2) * base * height. Here, base = 5 seconds and height = 20 m/s, so displacement = (1/2) * 5 * 20 = 50 meters. This can also be verified using the kinematic equation for constant acceleration from rest: s = (1/2) * a * t2, resulting in the same displacement of 50 meters.

Lakhmir Singh & Manjit Kaur Test: Motion - Question 10

A boy is enjoying a ride on a merry-go-round moving at a constant speed of 10 m/s. What is his state of motion?

Detailed Solution: Question 10

1. Acceleration measures the rate of change of velocity. 2. Velocity, being a vector quantity, changes if either magnitude or direction (or both) change. 3. On a merry-go-round at constant speed, the direction of velocity changes continuously, resulting in centripetal acceleration. 4. Therefore, the boy is in accelerated motion.

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