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CBSE Class 9  >  Class 9 Test  >  Online MCQ Tests  >  Test: Measures Of Central Tendency - Class 9 MCQ

Measures Of Central Tendency - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Measures Of Central Tendency (10 Questions)

You can prepare effectively for Class 9 Online MCQ Tests for Class 9 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Measures Of Central Tendency". These 10 questions have been designed by the experts with the latest curriculum of Class 9 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Measures Of Central Tendency - Question 1
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The mean of prime numbers between 20 and 30 is:

Detailed Solution: Question 1

The prime numbers between 20 and 30 are 23, 29.
► Mean of 23 and 29 = (23 + 29) / 2 = 52/ 2 = 26

Test: Measures Of Central Tendency - Question 2
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The arithmetic mean of 30 values is 69. The new mean, if each of the 30 values is increased by 5 is:

Detailed Solution: Question 2

Mean=30 then total sum=30×69=2070 if 5 increase to all then total sum=2070+30×5=2070+150=2220
New mean =2220÷30 =74

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Test: Measures Of Central Tendency - Question 3
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In an examination, ten students scored the following marks: 60, 58, 90, 51, 47, 81, 70, 95, 87, 99. The range of this data is:

Detailed Solution: Question 3

The difference between the maximum & minimum value of the observation is called as range.
So Range = 99-47 = 52

Test: Measures Of Central Tendency - Question 4
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If the number of observations in a data set is 25 and the mean of the data is 32. Then, the sum of all observations is:

Detailed Solution: Question 4

The number of observation is 25. The mean is 32.
► The sum = 25 + 25 + 25... 32 times
► 32*25 = 800

Test: Measures Of Central Tendency - Question 5
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If the mean of 6, 4, 7, x and 10 is 8, the value of x is:

Detailed Solution: Question 5

Mean = sum of all obs. /no. of obs.
► 8 = (6+4+7+x+10)/5
► 40 = 27+x
► x = 13

Test: Measures Of Central Tendency - Question 6
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The maximum frequency is 10 for observation 4. Hence the mode of the data is:

Detailed Solution: Question 6

  • The mode is the most frequently occurring value of data.
  • Here 4 is the most frequently occurring observation. So 4 is the mode of the data.

Test: Measures Of Central Tendency - Question 7
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Median of the data 5, 9, 8, 6, 3, 5, 7, 12, 15 is:

Detailed Solution: Question 7

Arranging the given terms in descending order 15, 12, 9, 8, 7, 6, 5, 5, 3
► Number of terms = 9
► Median = (n+1)/2 = 10/2 = 5th term = 7

Test: Measures Of Central Tendency - Question 8
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Find median of following data: 83, 37, 70, 29, 45, 63, 41, 70, 34, 54:

Detailed Solution: Question 8

Arranging the data in ascending order, we have:
29, 34, 37, 41, 45, 54, 63, 70, 70, 83
Here, the number of observations, n = 10 (Even).

Hence, the median of the given data is 49.5.

Test: Measures Of Central Tendency - Question 9
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What will be the mean of x, x + 2, x + 4, x + 6, x + 8, when the value of x is 12?

Detailed Solution: Question 9

► Mean = sum of all the obs./ no. of obs.
In the given question number of observation is 5.
► Sum of all observations = 5x + 20 
But x =12; on substituting the value of x we get 5 * 12 + 20 = 80.
► Mean = 80 / 5 = 16

Test: Measures Of Central Tendency - Question 10
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The median of observations 17, 18, 20, 22, x+2, x+4, 31, 35, 37 is found to be 24. If the observations have been arranged in ascending order, the value of x will be​:

Detailed Solution: Question 10

17, 18, 20, 22, x+2, x+4, 31, 35, 37
The total number of observation is 9, which is odd.
► Median  = (9+1)/2th term = 5th term
Now 5th term of the observation is (x+2)
Also given, median = 24
► x + 2 = 24
► x = 24-2
► x = 22
So the value of x is 22.

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This test contains 10 MCQs on Measures Of Central Tendency with detailed solutions for each question. It is part of the Online MCQ Tests for Class 9 course on EduRev, designed to align with the current Class 9 syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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