AP EAMCET Mock Test - 10 - JEE MCQ

Sound from S1 and S2 will interfere at the point on the circumference of the circle.

At A, path difference between two sounds is 0 m.
At B, path difference between two sounds is S₁B−S₂B=2 m.

From A to B, along the circumference, the path difference increases. Hence maxima and minima will be observed along the circumference. At B, 5th maxima is observed.
⇒ ΔxB = 2= 5λ
⇒ λ = 0.4 m

Work function of a metal surface is defined as the minimum energy required to eject an electron from metal to a point immediately outside the solid in vacuum. The work function is not the bulk property of metal rather it's the surface phenomenon.

Given angular momentum about O and P are I_O and I_P, respectively.
Angular momentum about P: 



Also, angular moment about O,

Thus, the direction of  is constant.
But  will continuously change its direction.
Thus,  ​​will change its direction at every instant and thus varies.
But  = constant.

The magnetic field at P(a, 0, a) due to the loop is equal to the vector sum of the magnetic fields produced by loops ABCDA and AFEBA as shown in the figure.

Magnetic field due to loop ABCDA will be along  and due to loop AFEBA, along .
Magnitude of magnetic field due to both the loops will be equal.
Therefore, direction of resultant magnetic field at P will be 

When raindrops fall from the sky, the air acts like a fluid which opposes the relative motion between the layers of air and water drops.

This causes viscosity. This force opposes gravity. The value of the viscous force acting on a spherical body in the air is given by Stoke's law,

F=6πηrv 
Where v is the relative velocity between the sphere and the fluid, r is the radius of the sphere, and η is the coefficient of viscosity.

From this formula, we can see that the force of viscosity is dependent on the speed with which the body travels.

Initially, the force due to viscosity is zero when the drop is at rest. As the speed starts increasing, the viscous force starts increasing. 

The viscous force increases till it reaches a point where the force balances the force due to the gravity,

Fv=mg
The water drop reaches equilibrium at this velocity after which it travels with a constant velocity. This velocity is also called the terminal velocity.

Scale reading is due to the force acting on its pan. This force is due to the rate of change of momentum given to it because of colliding particles.
Velocity with which the particle collides with the pan, v =  =  = _^2.8√5 ms^-1
= 12.52 x 10^-3 kg ms^-1
 Momentum imparted to pan per second = 12.52 x 10^-3 x 100
= 1.252 kg = 1252 g (weight)

Let the rocket be at a distance x from the moon when the gravitational force on it is zero.
Its distance from earth = r - x. Gravitational force on the rocket due to earth is

where m is the mass of the rocket, Gravitational force on the rocket due to moon is

Since the two forces are in opposite directions, the net force on the rocket will be zero if F_e = F_m.
Equating the two we get

which gives x = r/10.
Hence the correct choice is (c).

Particle taken t₁ time to reach from 0 to 3h and also t₁ to reach from 3h to 4h and yet again t₁ time from 4h to 3h.
∴ v_x3t₁ − 10 × 3t₁ = v_xt₁
⇒ v_x = 15 m s⁻¹

XeF₄ has square planner geometry having sp³d² hybridisation in the central atom as shown below:

SF₄ has distorted trigonal bipyramidal structure with sp³d hybridisation in the central atom.

[NiCI₄]^2- has sp³ hybridisation in the central atom with a tetrahedral structure.

[PtCI₄]^2-has dsp² hybridisation in the central atom with square planar structure.

The species which has both polar and non-polar ends is surfactant. Thus, CH₃–(CH₂)₁₄–CH₂–NH₂ is not a surfactant.

Metallic lustre is the property of metals which describes the amount of light that reflects by metals.

The reflection of light happens due to oscillation of free electron. Because loosely held electrons oscillate in all directions so, when light hits the metals, it gets reflected.

Cu from sulphide ore is obtained in a Bessemer's convertor as follows:


Copper pyrite ore CuFeS₂ also contains FeS which is removed as follows:

Roasting converts FeS to FeO, which combines with silica flux to form slag.

Chain isomerism is type of structural isomerism. Chain isomers differ in the branching of carbon skeleton. Possible chain isomers of C₆H₁₄ are:

Hence, five isomers are possible.

Given, pH = 14; pOH = 0 and [OH^-] = 1 M
[Cu²⁺] [OH^-]² = K_sp = 1.0 x 10^-19
[Cu²⁺] = 1.0 x 10^-19 M
For the half-reaction,
Cu2+ + 2e^-  Cu
E_Cu²⁺_/Cu =  - 
E_Cu²⁺/Cu = 0.34 - log 10¹⁹
E_Cu²⁺/Cu = -0.22 V

In the lewis structure of disulfate  ion, sulfur atoms are located as center atoms and oxygen atoms are located around sulfur atoms. There are two double bonds around a sulfur atom in the lewis structure. Oxidation number of sulfur is six in  ion.

has no s−s linkage :

For the first card drawn , probability of ace is 4/52 .
Then for the second card, after the first ace is drawn, there are only 3 aces left out of 51 cards,
So probability is 3/51 .
The probability of performing two independent activities such as this is actually the product of the probabilities:
( 4/52 ) x ( 3/51 ).
This reduces to ( 1/13 ) x ( 1/17 ) = 1 221

The given equation reduces to (−ω)^m    = (−ω²)^m 

⇒ ω^m  = 1 

⇒ m = 3

When two sides and angle opposite to one of then be given. In this case, the triangle is not always uniquely determined. It is quite possible to have no triangle, one triangle and two triangles with this type of data.
So, it is called an ambiguous case.
Let b, c and B are given parts.
When B is acute and b < c sin B, then there is no triangle
By Cosine Law
b² = c² + a² - 2ac cos B
⇒ a² - 2ac cos B = b² - c²
⇒ a² - 2ac cos B + c² cos² B
= b² - c² + c² cos² B
⇒ (a - c cos B)² = b² - c² (1 - cos² B)
= b² - c² sin² B

This equation helps us to determine a, when b, c and B are being given. We observe that:
When b < c sin B, then a is imaginary and so there is no solution.

Required area

Required ways = 4 x 4 x 4 x 4 x 4 = 4⁵

sin 7θ + sin θ - sin 4θ = 0
⇒ 2 sin 4θ . cos 3θ - sin 4θ = 0
⇒ sin 4θ [2 cos 3θ - 1] = 0
⇒ sin 4θ = 0 or cos 3θ = 1/2 = cos ( π/3 )
⇒ 4θ = nπ or 3θ = 2nπ  ( π/3 )
⇒ θ = nπ/4 or θ = ( 2nπ/3 )  ( π/9 )
∴ The values of θ are π/4 , π/9